Chemistry 2012 Student Edition (hard Cover) Grade 11
Chemistry 2012 Student Edition (hard Cover) Grade 11
12th Edition
ISBN: 9780132525763
Author: Prentice Hall
Publisher: Prentice Hall
Question
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Chapter 15, Problem 6STP
Interpretation Introduction

Interpretation: To explain the reason for similar conductivities between two pairs of conducting solutions.

Concept Introduction: Conductivity is defined as the ability of an electrolyte or a solute to conduct electricity. Not all the solutions need to conduct electricity as all the solutions are not electrolytes. Therefore, only the solutions which can dissociate can participate in conduction.

Expert Solution & Answer
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Answer to Problem 6STP

As both solutions will produce the same number of ions in the solution.

Explanation of Solution

When two pairs of conducting solutions are considered, similar conductivity is possible only when the number of ions that are produced upon dissociation in both the solutions. Only if there are the same number of ions in both solutions, there is a possibility for similar conductivities.

Conclusion

When there are a greater number of free electrons, then the conductivity will be good. The conductivity is purely based on the number of ions that are present in the solution. When there are no ions in the solution, the conductivity will be nil.

Chapter 15 Solutions

Chemistry 2012 Student Edition (hard Cover) Grade 11

Ch. 15.2 - Prob. 11LCCh. 15.2 - Prob. 12LCCh. 15.2 - Prob. 13LCCh. 15.2 - Prob. 14LCCh. 15.2 - Prob. 15LCCh. 15.2 - Prob. 16LCCh. 15.2 - Prob. 17LCCh. 15.3 - Prob. 18LCCh. 15.3 - Prob. 19LCCh. 15.3 - Prob. 20LCCh. 15.3 - Prob. 21LCCh. 15.3 - Prob. 22LCCh. 15.3 - Prob. 23LCCh. 15 - Prob. 24ACh. 15 - Prob. 25ACh. 15 - Prob. 26ACh. 15 - Prob. 27ACh. 15 - Prob. 28ACh. 15 - Prob. 29ACh. 15 - Prob. 30ACh. 15 - Prob. 31ACh. 15 - Prob. 32ACh. 15 - Prob. 33ACh. 15 - Prob. 34ACh. 15 - Prob. 35ACh. 15 - Prob. 36ACh. 15 - Prob. 37ACh. 15 - Prob. 38ACh. 15 - Prob. 39ACh. 15 - Prob. 40ACh. 15 - Prob. 41ACh. 15 - Prob. 42ACh. 15 - Prob. 43ACh. 15 - Prob. 44ACh. 15 - Prob. 45ACh. 15 - Prob. 46ACh. 15 - Prob. 47ACh. 15 - Prob. 48ACh. 15 - Prob. 49ACh. 15 - Prob. 50ACh. 15 - Prob. 51ACh. 15 - Prob. 52ACh. 15 - Prob. 53ACh. 15 - Prob. 54ACh. 15 - Prob. 55ACh. 15 - Prob. 56ACh. 15 - Prob. 57ACh. 15 - Prob. 58ACh. 15 - Prob. 59ACh. 15 - Prob. 60ACh. 15 - Prob. 61ACh. 15 - Prob. 62ACh. 15 - Prob. 63ACh. 15 - Prob. 64ACh. 15 - Prob. 65ACh. 15 - Prob. 66ACh. 15 - Prob. 67ACh. 15 - Prob. 68ACh. 15 - Prob. 69ACh. 15 - Prob. 70ACh. 15 - Prob. 71ACh. 15 - Prob. 72ACh. 15 - Prob. 73ACh. 15 - Prob. 74ACh. 15 - Prob. 75ACh. 15 - Prob. 76ACh. 15 - Prob. 77ACh. 15 - Prob. 78ACh. 15 - Prob. 79ACh. 15 - Prob. 80ACh. 15 - Prob. 81ACh. 15 - Prob. 82ACh. 15 - Prob. 83ACh. 15 - Prob. 84ACh. 15 - Prob. 85ACh. 15 - Prob. 86ACh. 15 - Prob. 87ACh. 15 - Prob. 88ACh. 15 - Prob. 89ACh. 15 - Prob. 90ACh. 15 - Prob. 91ACh. 15 - Prob. 92ACh. 15 - Prob. 93ACh. 15 - Prob. 94ACh. 15 - Prob. 95ACh. 15 - Prob. 96ACh. 15 - Prob. 97ACh. 15 - Prob. 98ACh. 15 - Prob. 99ACh. 15 - Prob. 100ACh. 15 - Prob. 101ACh. 15 - Prob. 102ACh. 15 - Prob. 103ACh. 15 - Prob. 104ACh. 15 - Prob. 105ACh. 15 - Prob. 106ACh. 15 - Prob. 107ACh. 15 - Prob. 108ACh. 15 - Prob. 109ACh. 15 - Prob. 110ACh. 15 - Prob. 111ACh. 15 - Prob. 1STPCh. 15 - Prob. 2STPCh. 15 - Prob. 3STPCh. 15 - Prob. 4STPCh. 15 - Prob. 5STPCh. 15 - Prob. 6STPCh. 15 - Prob. 7STPCh. 15 - Prob. 8STPCh. 15 - Prob. 9STPCh. 15 - Prob. 10STP
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