Chemistry 2012 Student Edition (hard Cover) Grade 11
Chemistry 2012 Student Edition (hard Cover) Grade 11
12th Edition
ISBN: 9780132525763
Author: Prentice Hall
Publisher: Prentice Hall
Question
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Chapter 15, Problem 39A
Interpretation Introduction

Interpretation: To state whether two of the solutes (sugar and salt) can be separated from water by filtration method.

Concept Introduction: Solubility is the interaction between a solute and the solvent particles. The solubility depends upon the physical and chemical properties of that substance. Increasing the temperature generally increases the solubility of substances. Substances such as sugar as well as salt are highly soluble in water at high temperatures.

Expert Solution & Answer
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Answer to Problem 39A

Table salt can be easily separated from the aqueous solution via the filtration method.

Explanation of Solution

The two water-soluble solids are table sugar and table salt. The mixture of sugar and salt can be easily separated by the evaporation method. During the evaporation method, the sugar can be easily separated as the mixture of salt and water evaporated in the form of vapors. Thus, during this method temperature plays a crucial role. On increasing the temperature, the solubility between the particles increases which further leads to the increase in the rate of evaporations. On heating, the more particles of the liquid get enough kinetic energy to go into a vapor state.

After alcohol is added to the mixture, the salt gets separated while sugar will be dissolved in alcohol.

At last, the solution is filtered while the salt behaves as a residue.

Conclusion

Thus, table salt can be easily separated from the aqueous solution via the filtration method.

Chapter 15 Solutions

Chemistry 2012 Student Edition (hard Cover) Grade 11

Ch. 15.2 - Prob. 11LCCh. 15.2 - Prob. 12LCCh. 15.2 - Prob. 13LCCh. 15.2 - Prob. 14LCCh. 15.2 - Prob. 15LCCh. 15.2 - Prob. 16LCCh. 15.2 - Prob. 17LCCh. 15.3 - Prob. 18LCCh. 15.3 - Prob. 19LCCh. 15.3 - Prob. 20LCCh. 15.3 - Prob. 21LCCh. 15.3 - Prob. 22LCCh. 15.3 - Prob. 23LCCh. 15 - Prob. 24ACh. 15 - Prob. 25ACh. 15 - Prob. 26ACh. 15 - Prob. 27ACh. 15 - Prob. 28ACh. 15 - Prob. 29ACh. 15 - Prob. 30ACh. 15 - Prob. 31ACh. 15 - Prob. 32ACh. 15 - Prob. 33ACh. 15 - Prob. 34ACh. 15 - Prob. 35ACh. 15 - Prob. 36ACh. 15 - Prob. 37ACh. 15 - Prob. 38ACh. 15 - Prob. 39ACh. 15 - Prob. 40ACh. 15 - Prob. 41ACh. 15 - Prob. 42ACh. 15 - Prob. 43ACh. 15 - Prob. 44ACh. 15 - Prob. 45ACh. 15 - Prob. 46ACh. 15 - Prob. 47ACh. 15 - Prob. 48ACh. 15 - Prob. 49ACh. 15 - Prob. 50ACh. 15 - Prob. 51ACh. 15 - Prob. 52ACh. 15 - Prob. 53ACh. 15 - Prob. 54ACh. 15 - Prob. 55ACh. 15 - Prob. 56ACh. 15 - Prob. 57ACh. 15 - Prob. 58ACh. 15 - Prob. 59ACh. 15 - Prob. 60ACh. 15 - Prob. 61ACh. 15 - Prob. 62ACh. 15 - Prob. 63ACh. 15 - Prob. 64ACh. 15 - Prob. 65ACh. 15 - Prob. 66ACh. 15 - Prob. 67ACh. 15 - Prob. 68ACh. 15 - Prob. 69ACh. 15 - Prob. 70ACh. 15 - Prob. 71ACh. 15 - Prob. 72ACh. 15 - Prob. 73ACh. 15 - Prob. 74ACh. 15 - Prob. 75ACh. 15 - Prob. 76ACh. 15 - Prob. 77ACh. 15 - Prob. 78ACh. 15 - Prob. 79ACh. 15 - Prob. 80ACh. 15 - Prob. 81ACh. 15 - Prob. 82ACh. 15 - Prob. 83ACh. 15 - Prob. 84ACh. 15 - Prob. 85ACh. 15 - Prob. 86ACh. 15 - Prob. 87ACh. 15 - Prob. 88ACh. 15 - Prob. 89ACh. 15 - Prob. 90ACh. 15 - Prob. 91ACh. 15 - Prob. 92ACh. 15 - Prob. 93ACh. 15 - Prob. 94ACh. 15 - Prob. 95ACh. 15 - Prob. 96ACh. 15 - Prob. 97ACh. 15 - Prob. 98ACh. 15 - Prob. 99ACh. 15 - Prob. 100ACh. 15 - Prob. 101ACh. 15 - Prob. 102ACh. 15 - Prob. 103ACh. 15 - Prob. 104ACh. 15 - Prob. 105ACh. 15 - Prob. 106ACh. 15 - Prob. 107ACh. 15 - Prob. 108ACh. 15 - Prob. 109ACh. 15 - Prob. 110ACh. 15 - Prob. 111ACh. 15 - Prob. 1STPCh. 15 - Prob. 2STPCh. 15 - Prob. 3STPCh. 15 - Prob. 4STPCh. 15 - Prob. 5STPCh. 15 - Prob. 6STPCh. 15 - Prob. 7STPCh. 15 - Prob. 8STPCh. 15 - Prob. 9STPCh. 15 - Prob. 10STP
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