Chapter 15, Problem 104A

(a)

Interpretation Introduction

Interpretation: To balance the given reaction.

Concept Introduction: The type of chemical reaction in which the count of atoms will be identical on both sides of the reaction is named a balanced chemical reaction.

Answer to Problem 104A

The balanced complete reaction will be ${\text{6CO}}_{\text{2}}\text{(g)}+{\text{6H}}_{\text{2}}\text{O(l)}\to {\text{C}}_{\text{6}}{\text{H}}_{\text{12}}{\text{O}}_{\text{6}}\text{(s)}+{\text{3O}}_{\text{2}}\text{(s)}$

Explanation of Solution

The chemical reaction is:

  ${\text{CO}}_{\text{2}}{\text{(g)+H}}_{\text{2}}\text{O(l)}\to {\text{C}}_{\text{6}}{\text{H}}_{\text{12}}{\text{O}}_{\text{6}}{\text{(s)+O}}_{\text{2}}\text{(s)}$

The number of carbon atoms on the reactant side = 1

The number of carbon atoms on the product side = 6

The number of carbon atoms is unbalanced, by multiplying with 6 as the coefficient of carbon dioxide and water, and by 3 as the coefficient of oxygen. The equation will be balanced.

The balanced chemical reaction will be:

  ${\text{6CO}}_{\text{2}}{\text{(g)+6H}}_{\text{2}}\text{O(l)}\to {\text{C}}_{\text{6}}{\text{H}}_{\text{12}}{\text{O}}_{\text{6}}{\text{(s)+3O}}_{\text{2}}\text{(s)}$

(b)

Interpretation Introduction

Interpretation: To determine the balance of chemical reactions.

Concept Introduction: The type of chemical reaction in which the count of atoms will be identical on both sides of the reaction is named a balanced chemical reaction.

Answer to Problem 104A

  ${\text{2Na(s)+2H}}_{\text{2}}\text{O(l)}\to 2{\text{NaOH(aq)+H}}_2(g)$

Explanation of Solution

The chemical reaction is:

  ${\text{Na(s)+H}}_{\text{2}}\text{O(l)}\to {\text{Na}}^{\text{+}}{\text{(aq)+OH}}^{\text{-}}{\text{(aq)+H}}_{\text{2}}\text{(g)}$

It can be written as:

  ${\text{Na(s)+H}}_{\text{2}}\text{O(l)}\to {\text{NaOH(aq)+H}}_2(g)$

The number of hydrogen atoms on the reactant side = 2

The number of hydrogen atoms on the product side = 3

The number of hydrogen atoms is unbalanced, by multiplying with 2 as the coefficient of sodium, water, and sodium hydroxide molecules. The equation will be balanced.

The balanced chemical reaction will be:

  ${\text{2Na(s)+2H}}_{\text{2}}\text{O(l)}\to 2{\text{NaOH(aq)+H}}_2(g)$