Study Guide for Campbell Biology
11th Edition
ISBN: 9780134443775
Author: Lisa A. Urry, Michael L. Cain, Steven A. Wasserman, Peter V. Minorsky, Jane B. Reece, Martha R. Taylor, Michael A. Pollock
Publisher: PEARSON
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Chapter 14, Problem 15GP
Summary Introduction
To explain: The genetic outcome when black guinea pig is crossed with albino pig.
Introduction: According to
Summary Introduction
To determine: The genotypes of parent and offspring.
Introduction: For a given trait, a recessive allele is expressed only in homozygous condition, but a dominant allele is expressed both in homozygous and heterozygous conditions.
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Chapter 14 Solutions
Study Guide for Campbell Biology
Ch. 14 - Fill in the following diagram of a cross of...Ch. 14 - A tall pea plant is crossed with a recessive dwarf...Ch. 14 - A true-breeding tall, purple-flowered pea plant...Ch. 14 - a. In the following cross, what is the probability...Ch. 14 - Prob. 5IQCh. 14 - Consider an example in which the M/m gene (for...Ch. 14 - The height of spike weed is a result of polygenic...Ch. 14 - Consider the following pedigree for the trait...Ch. 14 - a. What is the probability that a mating between...Ch. 14 - If two prospective parents both have siblings who...
Ch. 14 - Prob. 1SYKCh. 14 - How many different types of gametes can be formed...Ch. 14 - Prob. 3SYKCh. 14 - _______ gene Description a. has no effect on...Ch. 14 - _________ allele Description a. has no effect on...Ch. 14 - Prob. 3TYKMCh. 14 - Prob. 4TYKMCh. 14 - __________ dominant allele Description a. has no...Ch. 14 - __________ recessive allele Description a. has no...Ch. 14 - __________ genotype Description a. has no effect...Ch. 14 - Prob. 8TYKMCh. 14 - Prob. 9TYKMCh. 14 - Prob. 10TYKMCh. 14 - Prob. 11TYKMCh. 14 - Prob. 12TYKMCh. 14 - According to Mendels law of segregation, a. there...Ch. 14 - The F2 generation a. has a phenotypic ratio of...Ch. 14 - A 1:1 phenotypic ratio in a testcross indicates...Ch. 14 - Which phase of meiosis is most directly related to...Ch. 14 - After obtaining two heads from two tosses of a...Ch. 14 - The probability of tossing three coins...Ch. 14 - The probability of tossing three coins...Ch. 14 - In the F2 of a dihybrid cross involving two...Ch. 14 - In guinea pigs, the brown coat color allele (B) is...Ch. 14 - A true-breeding dwarf corn plant with red ears is...Ch. 14 - Prob. 11TYKCh. 14 - Prob. 12TYKCh. 14 - Prob. 13TYKCh. 14 - In humans, earwax can be wet or dry. The form of...Ch. 14 - You have blood type B, your mother has blood type...Ch. 14 - Prob. 16TYKCh. 14 - Summer squash are either white or yellow. To get...Ch. 14 - Prob. 2GPCh. 14 - True-breeding tall red-flowered plants are crossed...Ch. 14 - Prob. 4GPCh. 14 - Prob. 5GPCh. 14 - Prob. 6GPCh. 14 - Prob. 7GPCh. 14 - Prob. 8GPCh. 14 - Prob. 9GPCh. 14 - Fur color in rabbits is determined by a single...Ch. 14 - Prob. 11GPCh. 14 - The ability to taste phenylthiocarbamide (PTC) is...Ch. 14 - Prob. 13GPCh. 14 - Prob. 14GPCh. 14 - Prob. 15GPCh. 14 - Prob. 16GPCh. 14 - Imagine that a newly discovered, recessively...Ch. 14 - In mice, black fur (B) is dominant to white (b)....
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- Two pure-breeding lines of petunia plants are crossed. Line 1 plants grow to a height of 54 cm, and Line 2 plants grow to a height of 18 cm. Petunia plant height is controlled by three genes, A, B and C. Line 1 has the genotype A₁A₁B₁B₁C₁C₁, and line 2 has the genotype A2A2B₂B₂C₂C₂. Assume that genotype alone determines plant height under ideal growth conditions and that the alleles of the three genes are additive. If the F1 plants are self crossed, what is the expected proportion of F2 plants with the genotype A₁A₁B₁B₁C₁C₁ 1/8 1/32 1/16 1/4 1/64arrow_forwardA variety of opium poppy with lacerate leaves was crossed with a variety that has normal leaves. All the F1 plants had lacerate leaves. Two F1 plants were then interbred to produce the F2. Of the F2 plants, 249 had lacerate leaves and 16 had normal leaves. What are the genotypes of the plants in the P (parental), F1, and F2 generations? How are lacerate leaves determined in the opium poppy? Note: You can use the symbols A and B to represent the two genes involved. (How do we know there are two?)arrow_forwardIf 2 spot (S) is dominant to 4 spot (s), give the genotypes for the parents in the following crosses: 2 spot × 2 spot yields 2 spot and 4 spot 2 spot × 4 spot yields only 2 spot 2 spot × 4 spot yields 2 spot and 4 spot 2 spot × 2 spot yields only 2 spot 4 spot × 4 spot yields only 4 spotarrow_forward
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