Biology
12th Edition
ISBN: 9780134813448
Author: Audesirk, Teresa, Gerald, Byers, Bruce E.
Publisher: Pearson,
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Chapter 13, Problem 2AC
Summary Introduction
To explain:
The relation of allele combination in heterozygotes and severity of cystic fibrosis symptoms, with better-functioning allele, with worse-functioning allele, and somewhere in between.
Introduction:
The inherited disease related to the functioning of mucous glands present in various parts of the body is cystic fibrosis. This is a chronic disease affecting major parts of the body and especially lungs. The affected individuals can live only up to thirty years.
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In humans, four different blood types (A, B, AB, and O) are encoded by three alleles 1,
1, and i Individuals with both I and I alleles have blood type AB (red blood cells with
both A and B antigens). Two copies of the i allele are required for an individual to have
blood type O (red blood cells with no antigens).
Which of the following correctly indicates the relationship between the I and / alleles for the blood type gene?
Select one:
OA. I is dominant to /
OB. I is recessive to i
OC. I and I are co-dominant
OD. I and/exemplify incomplete dominance
Over a thousand different alleles at the CFTR locus have been discovered that can cause cystic fibrosis. What difficulties might the presence of so many different alleles at this locus create for the diagnosis and treatment of cystic fibrosis?
Sickle cell anemia is caused by an individual carrying two recessive copies of the hemoglobin gene (hemoglobin gene is labeled Hb, and the recessive version is Hbs). Thus, to have sickle cell anemia, a person must have the genotype HbSHbS. A person that is HbAHbA carries two copies of the normal hemoglobin gene and does not have sickle cell anemia. A person that is heterozygous (HbAHbS) produces enough normal hemoglobin to not have sickle cell anemia but is also resistant to malaria. People that are heterozygous are called “carriers” because they carry the recessive allele but do not express the recessive phenotype.
a. A couple are both resistant to malaria but do not have sickle cell anemia. Draw a Punnett square to represent this cross.
b. What is the probability that the couple has three children where one child does not have a recessive allele, one child is resistant to malaria and does not have sickle cell anemia, and one child has sickle cell anemia?
Chapter 13 Solutions
Biology
Ch. 13.1 - describe three types of RNA that play roles in...Ch. 13.1 - Prob. 2CYLCh. 13.1 - Prob. 3CYLCh. 13.2 - Prob. 1TCCh. 13.2 - Prob. 1CYLCh. 13.2 - Prob. 2CYLCh. 13.2 - describe an example of post-transcription...Ch. 13.3 - Prob. 1TCCh. 13.3 - Prob. 1CSCCh. 13.3 - Prob. 1CYL
Ch. 13.3 - Prob. 2CYLCh. 13.3 - Prob. 3CYLCh. 13.3 - Prob. 4CYLCh. 13.4 - Prob. 1CSCCh. 13.4 - describe three different types of mutations?Ch. 13.4 - Prob. 2CYLCh. 13.5 - Prob. 1HYEWCh. 13.5 - Envision yourself as a physician. A mother,...Ch. 13.5 - Prob. 2TCCh. 13.5 - Prob. 1CYLCh. 13.5 - Prob. 2CYLCh. 13.5 - Prob. 3CYLCh. 13.5 - Prob. 4CYLCh. 13.5 - Prob. 1CTCh. 13 - Prob. 1MCCh. 13 - Which of the following is not true of RNA? a. It...Ch. 13 - Prob. 3MCCh. 13 - Prob. 4MCCh. 13 - Prob. 5MCCh. 13 - Synthesis of RNA from the instructions in DNA is...Ch. 13 - Prob. 2FIBCh. 13 - Prob. 3FIBCh. 13 - Prob. 4FIBCh. 13 - Prob. 5FIBCh. 13 - If a nucleotide is replaced by a different...Ch. 13 - Prob. 1RQCh. 13 - Name the three types of RNA that are essential to...Ch. 13 - Prob. 3RQCh. 13 - Prob. 4RQCh. 13 - Prob. 5RQCh. 13 - Prob. 6RQCh. 13 - Prob. 7RQCh. 13 - Define mutation. Describe four different effects...Ch. 13 - Prob. 1ACCh. 13 - Prob. 2AC
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- Sickle-cell anemia is caused by a point mutation which alters the shape of erythrocytes. Individuals with two normal alleles have normal erythrocytes, individuals with two mutated alleles have C-shaped erythrocytes and experience anemia. Heterozygous individuals produce both types of erythrocytes and experience protection from the parasite that causes malaria. If a anemic man and a normal woman have children, what percentage of the offspring are expected to be protected from malaria? 50% O 0% 75% 100% 25%arrow_forwardIn addition to the allelic pair determining pattern baldness in man (B,b), consider early baldness to be due to another autosomal allele (E) on a different pair of chromosomes and also dominant in males but recessive in females. The phenotype for ee may be late or nonbaldness depending on sex and the genotype for B, b alleles. Two doubly heterozygous persons marry. What is the phenotype of the male parent? What is the phenotype of the female parent? Give the phenotypic ratio expected among male children of couples such as this one. Show corresponding genotypes for each phenotype mentioned in your phenotypic ratio. Give the phenotypic ratio expected among female children of couples such as this one. Show corresponding genotypes for each phenotype mentioned in your phenotypic ratio.arrow_forwardα-thalassemia is another blood disorder in which abnormal hemoglobin molecules are formed, leading to anemia. One mutant allele known to cause α-thalassemia occurs in α-hemoglobin and is called Constant Spring. Normal α-hemoglobin is 141 amino acids long, while the Constant Spring protein is 172 amino acids long. Include answers to both A and B in your response. A maximum of 2 sentences per part. A) Explain how a frameshift mutation in the coding region of α-hemoglobin could result in the Constant Spring protein. B) Explain how a single base-substitution mutation in the coding region of α-hemoglobin could result in the Constant Spring protein.arrow_forward
- Sickle cell anemia is a genetically inherited autosomal recessive trait in which results in a condition that there are not enough healthy red blood cells to carry oxygen throughout the body due to the production of red blood cells that are sickle shaped. The frequency of the sickle cell condition is as high as 10% in Central Africa compared to 0.5% in the United States. Calculate the frequency of the normal and carries of the sickle cell condition.arrow_forwardCystic fibrosis in humans is caused by a recessive allele. A man is known to be a carrier of the cystic fibrosis allele. He marries a phenotypically normal woman. In the general population, the incidence of cystic fibrosis at birth is approximately 1 in 1,700. Assume Hardy-Weinberg proportions. What is the probability that the wife is also a carrier? Answer in decimal number only (three decimal places; example: 0.123). What is the probability that their first child will be affected? Answer in decimal number only (three decimal places; example: 0.123).arrow_forwardCystic Fibrosis (CF) is an autosomal recessive condition. Therefore, heterozygous (Cc) carriers do not display symptoms. Two parents who are carriers plan to start a family and you are a genetic counselor helping to advise them about their chances of having children affected by CF. a) Suppose the couple has 4 children, each one year apart. What is the probability that all 4 children will inherit CF? b) What is the probability that any 3 of their 4 children will not inherit CF, but 1 will be affected? c) What is the probability that their first child will not inherit CF, but the younger 3 children will inherit CF?arrow_forward
- Sickle cell anemia is a disease that is caused by a mutation in the gene that produces hemoglobin. Hemoglobin carries oxygen in red blood cells. The HbA allele produces normal hemoglobin and the HbS allele produces hemoglobin that sticks together and causes red blood cells to sickle. Heterozygous individuals (HbAHbS) produce both normal and "sickle" hemoglobin so the HbA and HbS alleles are codominant. Heterozygotes do not develop sickle cell anemia and are described as having the sickle cell trait. Individuals that are homozygous for the sickle allele (HbSHbS) only produce "sickle" hemoglobin and develop sickle cell disease. A man with the sickle cell trait married a woman with the sickle cell trait. Determine the probability that they will have children with the sickle cell trait or sickle cell disease.Record your answer as a value between 0 and 1 rounded to two decimal places. Answerarrow_forwardCystic fibrosis (CF) is an autosomal recessive trait. A three-generation pedigree is shown below for a family that carries the mutant allele for cystic fibrosis. Note that carriers are not colored in to allow you to figure out their genotypes. Normal allele = F CF mutant allele = f What is the genotype of individual #13? A) ff B) FF C) Ff D) it is impossible to tellarrow_forwardDo you think a patient needs to have the SAME two mutant alleles of CFTR to present with/have cystic fibrosis? Why or why not?arrow_forward
- Alpha thalassemia is a hereditary blood condition that results in varying levels of anemia. It is tied to the HB alpha 1 gene and the HB alpha 2 gene on human chromosome 16. The diagram shows the proteins for the hemoglobin genes and the pedigree shows genotypes, designated by the letter X, on the chromosomes for a family affected by the condition. Which represents the predicted level of anemia in a child born to the mother and father in the image with a mutation that results in a genotype of xxxx? Why? A - mild anemia because the loss of 4 genes would equal the loss of the 4 proteins needed for normal alpha hemoglobin B - severe anemia because the loss of 4 genes would equal the loss of the 4 proteins needed for normal alpha hemoglobin C - mild anemia because the addition of 4 genes would produce too many of the proteins needed for normal alpha hemoglobin D - severe anemia because the addition of 4 genes would produce too many of the proteins needed for normal alpha hemoglobinarrow_forwardA homozygous recessive allele, aa, is responsible for albinism. Humans can exhibit this phenotype. In each of the following cases, determine the possible genotypes of the mother and father, and of their children: (a) Both parents have normal phenotypes; some of their children are albino and others are unaffected: (b) Both parents are albino and have only albino children: (c) The woman is unaffected, the man is albino, and they have one albino child and three unaffected children: at a busy hospital. The son of the first couple has hemophilia, a recessive, X-linked Two mothers give birth to sor disease. Neither parent from couple #1 has the disease. The second couple has an unaffected son, despite the fact that the father has hemophilia. The two couples challenge the hospital in court, claiming their babies must have beer swapped at birth. You must advise as to whether or not the sons could have been swapped. What would you say? 5. In a dispute over parentage, the mother of a child with…arrow_forwardThe allele for albinism is recessive to the allele for normal skin pigmentation. All individuals who are homozygous for this recessive allele (m) are unable to produce the enzyme needed for melanin production and are referred to as albinos. In the following statements, determine the correct genotypes: An albino male (genotype A) whose parents both have normal skin pigmentation (genotype B) marries a woman who does not have albinism (genotype C). This woman’s father is an albino (genotype D). The married couple has three children, two with normal skin pigmentation (genotype E) and one exhibiting albinism (genotype F)arrow_forward
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Mitochondrial mutations; Author: Useful Genetics;https://www.youtube.com/watch?v=GvgXe-3RJeU;License: CC-BY