a.
Tocalculate:The value of f in the table. If mean of the exam scores is 3.5
Score | 1 | 2 | 3 | 4 | 5 |
Frequency | 1 | 3 | f | 12 | 3 |
The value of f is 7.
Given information:
The given table is:
Score | 1 | 2 | 3 | 4 | 5 |
Frequency | 1 | 3 | f | 12 | 3 |
Formula used:
Calculation:
Consider the given table.
Score | 1 | 2 | 3 | 4 | 5 | |
Frequency | 1 | 3 | f | 12 | 3 | |
xf | 1 | 6 | 3f | 48 | 15 |
It is given mean of the exam scores is 3.5
The value of f is 7.
b.
To identify:The mode of all the exam scores.
Score | 1 | 2 | 3 | 4 | 5 |
Frequency | 1 | 3 | f | 12 | 3 |
The mode of the data is 4.
Given information:
The given table is:
Score | 1 | 2 | 3 | 4 | 5 |
Frequency | 1 | 3 | f | 12 | 3 |
Explanation:
Consider the given information.
Mode of the data is the data value with highest frequency.
It can be observed that 4 has the highest frequency that is 12.
Thus, the mode of the data is 4.
c.
To identify:The median of all the exam scores.
Score | 1 | 2 | 3 | 4 | 5 |
Frequency | 1 | 3 | f | 12 | 3 |
The median of the data is 4.
Given information:
The given table is:
Score | 1 | 2 | 3 | 4 | 5 |
Frequency | 1 | 3 | f | 12 | 3 |
Explanation:
Consider the given information.
The total number of data values is
Median is the middle value of the ordered data set. So median of the given data set will be the average of 13th and 14th data values. Data values at 13th and 14th position are both 4.
So, median of the data set is 4.
Chapter 11 Solutions
High School Math 2015 Common Core Algebra 2 Student Edition Grades 10/11
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