Chapter 11.3, Problem 36PPSE

Solution

To identify:The probabilitya person is neitherin service nor in sales and office. The graph at the right shows the types of jobs held by people in the U.S.

  

The probability that a person is neither in service nor in sales and office $P=58,7\%$

Given information:

  

Explanation:

Consider the information.

The objective is to find the probability that a person is neither in service nor in sales and office.

From the graph, 16.5% population is in service occupation and24.8% population is in sales and office.

For mutually exclusive events $P\left(AorB\right)=P\left(A\right)+P\left(B\right)$

The probabilities of service sales and office are mutually exclusive events

So probability that a person is in service or sales and office

  $\begin{array}{c}P\left(ServiceorSalesandOffice\right)=P\left(Service\right)+P\left(SalesandOffice\right)\\ =16.5\%+24.8\%\\ =41.3\%\end{array}$

To determine probability that a person is neither in service nor in sales and office subtract the probability of the population is in service and the probability of the population is sales and office from 100 percent.

The probability that a person is neither in service nor in sales and office is

  $\begin{array}{c}P=100\%-P\left(ServiceorSalesandOffice\right)\\ =100\%-41.3\%\\ =58.7\%\end{array}$

Therefore.the probability that a person is neither in service nor in sales and office

  $P=58,7\%$