Concepts of Genetics (12th Edition)
12th Edition
ISBN: 9780134604718
Author: William S. Klug, Michael R. Cummings, Charlotte A. Spencer, Michael A. Palladino, Darrell Killian
Publisher: PEARSON
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Chapter 9, Problem 4PDQ
A plant may have green, white, or green-and-white (variegated) leaves on its branches, owing to a mutation in the chloroplast that prevents color from developing. Predict the results of the following crosses:
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List the possible genotypes of the parents if a cross resulted in a F1-generation consisting of 50% white colonies and 50% red colonies:
In corn, male sterility is controlled by maternal cytoplasmic elements. This phenotype renders the male part of corn plants (i.e. the tassel) unable to produce fertile pollen; the female parts, however, remain receptive to pollination by pollen from male-fertile corn plants. However, the presence of a nuclear fertility restorer gene F restores fertility to male-sterile lines.
Using the following color-coded circles, simulate the crosses indicated below. Put the illustrations of crosses in the spaces provided. Be sure to include in the labels the genotypes and phenotypes of the offspring in each cross.
Big light green circle - male-sterile cytoplasm
Big orange circle - male-fertile cytoplasm
Small orange circle - FF nucleus
Small half-light green-half-orange circle - Ff nucleus
Small light-green circle - ff nucleus
In sweet peas, gene C or P alone produces white flowers, the purple colour being due to the presence of both these factors. What will be the flower colour of the offsprings of the following crosses, in which genotypes of parents are given;a) A white flowered plant crossed with a purple produces offspring, of which three-eighth are purple and five-eighth white.
Chapter 9 Solutions
Concepts of Genetics (12th Edition)
Ch. 9 - Chlamydomonas, a eukaryoric green alga, may be...Ch. 9 - In aerobically cultured yeast, a petite mutant is...Ch. 9 - DNA in human mitochondria encodes 22 different...Ch. 9 - Prob. 4NSTCh. 9 - Why did Marcia choose mitochondrial testing to...Ch. 9 - Marcia saw an ad on television for ancestry DNA...Ch. 9 - How much importance should we place on the results...Ch. 9 - HOW DO WE KNOW? In this chapter, we focused on...Ch. 9 - Review the Chapter Concepts list on page 196. The...Ch. 9 - Streptomycin resistance in Chlamydomonas may...
Ch. 9 - A plant may have green, white, or green-and-white...Ch. 9 - In diploid yeast strains, sporulation and...Ch. 9 - Predict the results of a cross between ascospores...Ch. 9 - In Lymnaea, what results would you expect in a...Ch. 9 - In a cross of Lymnaea, the snail contributing the...Ch. 9 - In Drosophila subobscura, the presence of a...Ch. 9 - A male mouse from a true-breeding strain of...Ch. 9 - Consider the case where a mutation occurs that...Ch. 9 - What is the endosymbiotic theory, and why is this...Ch. 9 - In an earlier Problems and Discussion section (see...Ch. 9 - Mitochondrial replacement therapy (MRT) offers a...Ch. 9 - The specification of the anteriorposterior axis in...Ch. 9 - The maternal-effect mutation bicoid (bcd) is...Ch. 9 - (a) In humans the mitochondrial genome encodes a...Ch. 9 - Mutations in mitochondrial DNA appear to be...Ch. 9 - Researchers examined a family with an interesting...Ch. 9 - Payne, B. A. et al. (2013) present evidence that a...Ch. 9 - As mentioned in Section 9.3, mtDNA accumulates...Ch. 9 - Because offspring inherit the mitochondrial genome...
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- In the following dihybrid cross: B/b; E/e x B/b; e/e What are the phenotypes of the offspring? 9/16 Black 3/16 brown 4/16 golden 9/16 Brown 3/16 Black 4/16 golden 9/16 Black 3/16 golden 4/16 brown 3/8 Black 1/8 brown 4/8 golden 3/8 golden 4/8 Black 1/8 brownarrow_forwardIdentify how many genes are associated with the types of crosses: A.) Monohybrid B.) Dihybridarrow_forwardGenetics : Pisatin is a chemical used for defense by Pisum sativum against parasitic fungi (thus resistant). Two susceptible pure (homozygous) lines of peas were obtained and used in the following crosses:arrow_forward
- There are some members of the genus Datura that are trisomic for the chromosome set, which carries the genes for purple (p+) and white (p) flower color. In a cross involving a trisomic p+ p+ p female and pollen from a normal p+ p plant, what is the expected proportion of purple and white flowered individuals?arrow_forwardConsider this cross in pea plants: Tt Rr yy Aa × Tt rr Yy Aa, whereT = tall, t = dwarf, R = round, r = wrinkled, Y = yellow, y = green,A = axial, a = terminal. What is the expected phenotypic outcomeof this cross? Have one group of students solve this problem bymaking one big Punnett square, and have another group solve it bymaking four single-gene Punnett squares and using the multiplication method. Time each other to see who gets done first.arrow_forwardIndicate the possible genotypes of the following crosses. (Do your own representation, all characteristics first mentioned are dominant) Tall x dwarf Hairy x glabrous Red x white Smooth x wrinkled Yellow x greenarrow_forward
- Given the following information, determine the inheritance of flower color in this plant and determine the genotypes of the parental individuals, which are from pure- breeding lines. CROSS 1 CROSS 2 purple X colorless all purple 9/16 purple colorless X red all purple as in Cross 1 F1 F1 F2 F2 3/16 red 4/16 colorlessarrow_forwardDiagram the P1 and F1 crosses, using Mendelian notation, to show the possible genotypes found in each generation. (Remember a diagram is just the cross itself, not the progeny).arrow_forwardExplain the Limitations of two-point crossesarrow_forward
- In onion, male sterility is produced when the nuclear genotype is aa and the mitochondrial gene S (sterile) are present. Any other combination of nuclear genotype and mitochondrial gene (including gene F for fertile) will result in a male fertile plant. Give the genotypic ratio and the phenotypic ratio or the percentage of male sterile and male fertile offspring that will be produced in the following crosses. 1. Aa + S male x aa + F female 2. Reciprocal cross of number 1. (Note that when we do reciprocal cross, we interchange/swap the genotypes of the parents (if there is a nuclear gene involved, you interchange the nuclear genotype as well). 3. Aa + S female x Aa + F male 4. Reciprocal cross of number 3.arrow_forwardGene “A” and gene “B” are not linked. Each has two alleles. The A allele is dominant over the a allele and the B allele is dominant over the b allele. Answer the following questions about a dihybrid (two-trait) cross. A) List all of the possible gametes (eggs) that could be produced by an individual with the genotype: aabb B) List all of the possible gametes (sperm) that could be produced by an individual with the genotype: AaBB C) Fill out a Punnett square for the dihybrid cross cross between the two individuals listed above (aabb x AaBB). What percent of the offspring from this cross would have the dominant phenotype for both traits?arrow_forwardCross 1: Purple Stem (P1) x Brown Stem (P2) = F1 Generation (all purple stem plants). Cross 2: F1 x F1 = F2 Generation (295 purple stem plants and 102 brown stem plants). a) What is the phenotype ratio of the F2 generation? b) What is the geneotype ratio of the F2 generation? c) Which trait is dominant?arrow_forward
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