Essentials of Genetics (9th Edition) - Standalone book
9th Edition
ISBN: 9780134047799
Author: William S. Klug, Michael R. Cummings, Charlotte A. Spencer, Michael A. Palladino
Publisher: PEARSON
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Textbook Question
Chapter 9, Problem 16PDQ
What might Watson and Crick have concluded, had Chargaff's data from a single source indicated the following base composition?
| A | T | G | C | |
| % | 29 | 19 | 21 | 31 |
Why would this conclusion be contradictory to Wilkins and Franklin's data?
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What might Watson and Crick have concluded, had Chargaff’sdata from a single source indicated the following base composition? A T G C% 29 19 21 31Why would this conclusion be contradictory to Wilkins andFranklin’s data?
With regard to Chargaff’s experiment described in Figure shown,answer the following:A. What is the purpose of paper chromatography?B. Explain why it is necessary to remove the bases in order todetermine the base composition of DNA.C. Would Chargaff’s experiments have been convincing if theyhad been done on DNA from only one species? Discuss.
Chargaff’s results yielded a molar ratio of 1.29 for A to G in ox DNA, 1.43 for T to C, 1.04 for A to T and 1.00 for G to C. Given these values, what are the approximate mole fractions of A, C, G, and T in ox DNA?
Chapter 9 Solutions
Essentials of Genetics (9th Edition) - Standalone book
Ch. 9 - CASE STUDY |Zigs and zags of the smallpox virus...Ch. 9 -
CASE STUDY | Zigs and zags of the smallpox...Ch. 9 - CASE STUDY | Zigs and zags of the smallpox...Ch. 9 - CASE STUDY | Zigs and zags of the smallpox virus...Ch. 9 -
HOW DO WE KNOW?
1. In this chapter, we have...Ch. 9 - Review the Chapter Concepts list on p. 160. Most...Ch. 9 - Discuss the reasons why proteins were generally...Ch. 9 -
4. Contrast the various contributions made to our...Ch. 9 - When Avery and his colleagues had obtained what...Ch. 9 - Why were 32P and 35S chosen in the Hershey–Chase...
Ch. 9 - Does the design of the Hershey-Chase experiment...Ch. 9 - What observations are consistent with the...Ch. 9 - What are the exceptions to the general rule that...Ch. 9 -
10. Draw the chemical structure of the three...Ch. 9 - How are the carbon and nitrogen atoms of the...Ch. 9 - Adenine may also be named 6–amino purine. How...Ch. 9 -
13. Draw the chemical structure of a dinucleotide...Ch. 9 - Describe the various characteristics of the...Ch. 9 - Prob. 15PDQCh. 9 - What might Watson and Crick have concluded, had...Ch. 9 - Prob. 17PDQCh. 9 - Prob. 18PDQCh. 9 - Prob. 19PDQCh. 9 - Prob. 20PDQCh. 9 - Prob. 21PDQCh. 9 - Prob. 22PDQCh. 9 -
23. Why is Tm related to base composition?
Ch. 9 - What is the chemical basis of molecular...Ch. 9 - What did the Watson–Crick model suggest about the...Ch. 9 - A genetics student was asked to draw the chemical...Ch. 9 - Prob. 27PDQCh. 9 -
28. One of the most common spontaneous lesions...Ch. 9 - Prob. 29PDQCh. 9 - Prob. 30PDQCh. 9 - Prob. 31PDQCh. 9 -
32. During electrophoresis, DNA molecules can...Ch. 9 - Assume that you are interested in separating short...
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- Show the calculations for the preparation of 0.01%, 0.001%, 0.0001%, 0.00001% standard DNA solutions via serial dilution from a 0.1% stock solution. Prepare 10.0 mL of 0.10% standard DNA solution using acetate buffer pH 4.6 as solvent. Prepare four different concentrations of the 0.10% standard DNA solution from step 1 via serial dilution to obtain 0.01%, 0.001%, 0.0001%, 0.00001% standard DNA solutions. Obtain seven clean and dry test tubes. Place 1.50 mL solutions in each tube as follows: Table 2.1. Set-up for the diphenylamine assay. Test tube # Content 1 (blank) acetate buffer pH 4.6 2 0.10% standard DNA 3 0.01% standard DNA 4 0.001% standard DNA 5 0.0001% standard DNA 6 0.00001% standard DNA 7 DNA extract from Part I Add 3.50 mL diphenylamine reagent to each tube, swirl each tube to thoroughly mix the contents and heat for 10 mins in a boiling water bath. Cool immediately under tap water. Read absorbances at 595 nm.…arrow_forwardTo carry out sequencing, you need to include 600 ng of DNA and a total of 6.4 pmol of sequencing primer. If your concentration of DNA (determined by A260 reading on a Nanodrop Spectrophotometer) is 89.0 ng/μL, how many μL of this sample do you need for a total of 600 ng?arrow_forwardA sample of DNA with the sequence 5'- CTC GAG CGA AGC TCA ACC-3' he was obtained as a dry solid. The sample was dissolved in 1000 µl of deionized water ane mixed well. Ten microliters of the dissolved sample was then transferred to a new sampie tube and mixed with 990 ul of water, The dilute sample had A260 = 0.156. What was the concentration of the original sample (the solid dissolved in 1000 ul of deionized water)arrow_forward
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