Chemistry 2012 Student Edition (hard Cover) Grade 11
Chemistry 2012 Student Edition (hard Cover) Grade 11
12th Edition
ISBN: 9780132525763
Author: Prentice Hall
Publisher: Prentice Hall
Question
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Chapter 8, Problem 91A

(a)

Interpretation Introduction

Interpretation: The electron dot structure for BeF2 molecule needs to be drawn. Also, the reason for it too fails to obey the octet rule needs to be explained.

Concept Introduction: An electron dot structure represents the arrangement of total valence electrons in a molecule. Here, electrons are represented as dots in pairs around the symbol of atoms of the molecule.

According to the octet rule, all the atoms in a molecule are bonded to other atoms in such a way that they have complete octets (8 electrons in valence shell). There are some exceptions and some molecule does not obey the octet rule. This is due to the odd number of electrons, the number of electrons more than 8, and the number of electrons less than 8.

(a)

Expert Solution
Check Mark

Explanation of Solution

The given molecule is BeF2

. Here, the number of the valence electron in Be is 2 and that in F is 7. The electron dot structure can be represented as follows:

  Chemistry 2012 Student Edition (hard Cover) Grade 11, Chapter 8, Problem 91A , additional homework tip  1

Here, Be does not have a complete octet; thus, the octet rule is not obeyed.

(b)

Interpretation Introduction

Interpretation: The electron dot structure for SiF6 molecule needs to be drawn. Also, the reason for it too fails to obey the octet rule needs to be explained.

Concept Introduction: An electron dot structure represents the arrangement of total valence electrons in a molecule. Here, electrons are represented as dots in pairs around the symbol of atoms of the molecule.

According to the octet rule, all the atoms in a molecule are bonded to other atoms in such a way that they have complete octets (8 electrons in valence shell). There are some exceptions and some molecule does not obey the octet rule. This is due to the odd number of electrons, the number of electrons more than 8, and the number of electrons less than 8.

(b)

Expert Solution
Check Mark

Explanation of Solution

The given molecule is SiF6

. Here, the number of valence electrons in Si is 4 and that in F is 7. The electron dot structure can be represented as follows:

  Chemistry 2012 Student Edition (hard Cover) Grade 11, Chapter 8, Problem 91A , additional homework tip  2

Since there are 4 valence electrons on the Si atom it must gain 2 electrons to bond 6 F atoms. Thus, there will be an overall -2 charge. Here, the Si atom has an extended configuration as there are more than 8 electrons.

(c)

Interpretation Introduction

Interpretation: The electron dot structure for ClO2 molecule needs to be drawn. Also, the reason for it too fails to obey the octet rule needs to be explained.

Concept Introduction: An electron dot structure represents the arrangement of total valence electrons in a molecule. Here, electrons are represented as dots in pairs around the symbol of atoms of the molecule.

According to the octet rule, all the atoms in a molecule are bonded to other atoms in such a way that they have complete octets (8 electrons in valence shell). There are some exceptions and some molecule does not obey the octet rule. This is due to the odd number of electrons, the number of electrons more than 8, and the number of electrons less than 8.

(c)

Expert Solution
Check Mark

Explanation of Solution

The given molecule is ClO2

. Here, the Cl atom has 7 valence electrons and the O atom has 6 valence electrons. The arrangement of electrons around atoms takes place according to the following electron dot structure:

  Chemistry 2012 Student Edition (hard Cover) Grade 11, Chapter 8, Problem 91A , additional homework tip  3

Here, the Cl atom does not have 8 electrons in the valence shell; thus, it does not follow the octet rule. Here, the number of electrons in the valence shell is more than 8; thus, it has an extended configuration.

(d)

Interpretation Introduction

Interpretation: The electron dot structure for BF3 molecule needs to be drawn. Also, the reason for it too fails to obey the octet rule needs to be explained.

Concept Introduction: An electron dot structure represents the arrangement of total valence electrons in a molecule. Here, electrons are represented as dots in pairs around the symbol of atoms of the molecule.

According to the octet rule, all the atoms in a molecule are bonded to other atoms in such a way that they have complete octets (8 electrons in valence shell). There are some exceptions and some molecule does not obey the octet rule. This is due to the odd number of electrons, the number of electrons more than 8, and the number of electrons less than 8.

(d)

Expert Solution
Check Mark

Explanation of Solution

The given molecule is BF3

. Here, the number of valence electrons in B is 3, and that in F is 7. The electron dot structure can be represented as follows:

  Chemistry 2012 Student Edition (hard Cover) Grade 11, Chapter 8, Problem 91A , additional homework tip  4

There are 6 electrons in the valence shell thus, it has less than 8 electrons. Here, boron does not have a complete octet thus, the octet rule is not obeyed.

(e)

Interpretation Introduction

Interpretation: The electron dot structure for XeF2 molecule needs to be drawn. Also, the reason for it too fails to obey the octet rule needs to be explained.

Concept Introduction: An electron dot structure represents the arrangement of total valence electrons in a molecule. Here, electrons are represented as dots in pairs around the symbol of atoms of the molecule.

According to the octet rule, all the atoms in a molecule are bonded to other atoms in such a way that they have complete octets (8 electrons in valence shell). There are some exceptions and some molecule does not obey the octet rule. This is due to the odd number of electrons, the number of electrons more than 8, and the number of electrons less than 8.

(e)

Expert Solution
Check Mark

Explanation of Solution

The given molecule is XeF2

. Here, the number of the valence electron in Xe is 8 and that in F is 7. The electron dot structure can be represented as follows:

  Chemistry 2012 Student Edition (hard Cover) Grade 11, Chapter 8, Problem 91A , additional homework tip  5

Now, Xe has more than 8 electrons thus, the octet rule is not obeyed.

Chapter 8 Solutions

Chemistry 2012 Student Edition (hard Cover) Grade 11

Ch. 8.2 - Prob. 11LCCh. 8.2 - Prob. 12LCCh. 8.2 - Prob. 13LCCh. 8.2 - Prob. 14LCCh. 8.2 - Prob. 15LCCh. 8.2 - Prob. 16LCCh. 8.2 - Prob. 17LCCh. 8.2 - Prob. 18LCCh. 8.2 - Prob. 19LCCh. 8.2 - Prob. 20LCCh. 8.3 - Prob. 21LCCh. 8.3 - Prob. 22LCCh. 8.3 - Prob. 23LCCh. 8.3 - Prob. 24LCCh. 8.3 - Prob. 25LCCh. 8.3 - Prob. 26LCCh. 8.3 - Prob. 27LCCh. 8.3 - Prob. 28LCCh. 8.4 - Prob. 29SPCh. 8.4 - Prob. 30SPCh. 8.4 - Prob. 31LCCh. 8.4 - Prob. 32LCCh. 8.4 - Prob. 33LCCh. 8.4 - Prob. 34LCCh. 8.4 - Prob. 35LCCh. 8.4 - Prob. 36LCCh. 8.4 - Prob. 37LCCh. 8.4 - Prob. 38LCCh. 8 - Prob. 39ACh. 8 - Prob. 40ACh. 8 - Prob. 41ACh. 8 - Prob. 42ACh. 8 - Prob. 43ACh. 8 - Prob. 44ACh. 8 - Prob. 45ACh. 8 - Prob. 46ACh. 8 - Prob. 47ACh. 8 - Prob. 48ACh. 8 - Prob. 49ACh. 8 - Prob. 50ACh. 8 - Prob. 51ACh. 8 - Prob. 52ACh. 8 - Prob. 53ACh. 8 - Prob. 54ACh. 8 - Prob. 55ACh. 8 - Prob. 56ACh. 8 - Prob. 57ACh. 8 - Prob. 58ACh. 8 - Prob. 59ACh. 8 - Prob. 60ACh. 8 - Prob. 61ACh. 8 - Prob. 62ACh. 8 - Prob. 63ACh. 8 - Prob. 64ACh. 8 - Prob. 65ACh. 8 - Prob. 66ACh. 8 - Prob. 67ACh. 8 - Prob. 68ACh. 8 - Prob. 69ACh. 8 - Prob. 70ACh. 8 - Prob. 71ACh. 8 - Prob. 72ACh. 8 - Prob. 73ACh. 8 - Prob. 74ACh. 8 - Prob. 75ACh. 8 - Prob. 76ACh. 8 - Prob. 77ACh. 8 - Prob. 78ACh. 8 - Prob. 79ACh. 8 - Prob. 80ACh. 8 - Prob. 81ACh. 8 - Prob. 82ACh. 8 - Prob. 83ACh. 8 - Prob. 84ACh. 8 - Prob. 85ACh. 8 - Prob. 86ACh. 8 - Prob. 87ACh. 8 - Prob. 88ACh. 8 - Prob. 89ACh. 8 - Prob. 90ACh. 8 - Prob. 91ACh. 8 - Prob. 92ACh. 8 - Prob. 94ACh. 8 - Prob. 95ACh. 8 - Prob. 96ACh. 8 - Prob. 97ACh. 8 - Prob. 98ACh. 8 - Prob. 99ACh. 8 - Prob. 100ACh. 8 - Prob. 101ACh. 8 - Prob. 102ACh. 8 - Prob. 103ACh. 8 - Prob. 104ACh. 8 - Prob. 105ACh. 8 - Prob. 106ACh. 8 - Prob. 107ACh. 8 - Prob. 108ACh. 8 - Prob. 109ACh. 8 - Prob. 110ACh. 8 - Prob. 111ACh. 8 - Prob. 112ACh. 8 - Prob. 113ACh. 8 - Prob. 114ACh. 8 - Prob. 115ACh. 8 - Prob. 1STPCh. 8 - Prob. 2STPCh. 8 - Prob. 3STPCh. 8 - Prob. 4STPCh. 8 - Prob. 5STPCh. 8 - Prob. 6STPCh. 8 - Prob. 7STPCh. 8 - Prob. 8STPCh. 8 - Prob. 9STPCh. 8 - Prob. 10STPCh. 8 - Prob. 11STPCh. 8 - Prob. 12STPCh. 8 - Prob. 13STPCh. 8 - Prob. 14STP
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