Genetics: Analysis and Principles
6th Edition
ISBN: 9781259616020
Author: Robert J. Brooker Professor Dr.
Publisher: McGraw-Hill Education
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Chapter 8, Problem 22CONQ
Summary Introduction
To review:
The birth of a red-eyed male when a female homozygous for X linked white allele is mated with a red-eyed male, and it is assumed that there is no mutation in the mother’s X chromosome that converted the white-eyed allele into a red eye allele.
Introduction:
The failure of homologous chromosomes to separate during cell division is known as nondisjunction. It can be of 3 types: improper separation of homologous chromosomes during meiosis 1, improper separation of sister chromatids during meiosis 2, and improper separation of sister chromatids during mitosis.
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Chapter 8 Solutions
Genetics: Analysis and Principles
Ch. 8.1 - 1. A chromosome that is metacentric has its...Ch. 8.1 - Staining eukaryotic chromosomes is useful because...Ch. 8.2 - Prob. 1COMQCh. 8.3 - Which of the following statements is correct? a....Ch. 8.3 - Prob. 2COMQCh. 8.4 - 1. A paracentric inversion
a. includes the...Ch. 8.4 - Due to crossing over within an inversion loop, a...Ch. 8.4 - 3. A mechanism that may cause a translocation is...Ch. 8.5 - 1. Humans have 23 chromosomes per set. A person...Ch. 8.6 - Prob. 1COMQ
Ch. 8.6 - Prob. 2COMQCh. 8.7 - The term endopolyploidy refers to the phenomenon...Ch. 8.7 - 2. In agriculture, an advantage of triploidy in...Ch. 8.8 - Prob. 1COMQCh. 8.8 - The somatic cells of an allotetraploid contain a....Ch. 8 - 1. Which changes in chromosome structure cause a...Ch. 8 - Prob. 2CONQCh. 8 - 3. How does a chromosomal duplication occur?
Ch. 8 - 4. What is a gene family? How are gene families...Ch. 8 - Prob. 5CONQCh. 8 - Two chromosomes have the following orders for...Ch. 8 - An inversion heterozygote has the following...Ch. 8 - Prob. 8CONQCh. 8 - Explain why inversions and reciprocal...Ch. 8 - 10. An individual has the following reciprocal...Ch. 8 - A phenotypically normal individual has the...Ch. 8 - 12. Two phenotypically normal parents produce a...Ch. 8 - With regard to the segregation of centromeres, why...Ch. 8 - Prob. 14CONQCh. 8 - Prob. 15CONQCh. 8 - 16. A phenotypically abnormal individual has a...Ch. 8 - 17. A diploid fruit fly has eight chromosomes. How...Ch. 8 - Prob. 18CONQCh. 8 - Prob. 19CONQCh. 8 - 20. Aneuploidy is typically detrimental, whereas...Ch. 8 - 21. Explain how aneuploidy, deletions, and...Ch. 8 - Prob. 22CONQCh. 8 - 23. A cytogeneticist has collected tissue samples...Ch. 8 - Prob. 24CONQCh. 8 - A zookeeper has collected a male and a female...Ch. 8 - Prob. 26CONQCh. 8 - 27. What is mosaicism? How is it produced?
Ch. 8 - 28. Explain how polytene chromosomes of Drosophila...Ch. 8 - 29. Describe some of the advantages of polyploid...Ch. 8 - 30. While conducting field studies on a chain of...Ch. 8 - Prob. 31CONQCh. 8 - Which of the following terms should not be used to...Ch. 8 - Prob. 33CONQCh. 8 - Prob. 34CONQCh. 8 - A triploid plant has 18 chromosomes (i.e., 6...Ch. 8 - Prob. 36CONQCh. 8 - Prob. 37CONQCh. 8 - 38. A woman who is heterozygous, Bb, has brown...Ch. 8 - 39. What is an allodiploid? What factor determines...Ch. 8 - Prob. 40CONQCh. 8 - 41. Table 8.1 shows that Turner syndrome occurs...Ch. 8 - 42. Male honeybees, which are haploid, produce...Ch. 8 - Prob. 1EQCh. 8 - Prob. 2EQCh. 8 - With regard to the analysis of chromosome...Ch. 8 - 4. Describe how colchicine can be used to alter...Ch. 8 - 5. Describe the steps you would take to produce a...Ch. 8 - Prob. 6EQCh. 8 - What are G bands? Discuss how G bands are useful...Ch. 8 - A female fruit fly has one normal X chromosome and...Ch. 8 - Prob. 2QSDCCh. 8 - Besides the ones mentioned in this textbook, look...Ch. 8 - Prob. 4QSDCCh. 8 - 5. Discuss the importance of gene families at the...
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- In fruit flies, the following X-linked traits are found: white eyes are recessive to red eyes, ebony body is recessive to gray body, and short wings is recessive to long wings. A cross was made between wild-type males with red eyes, long wings, and gray bodies and females with white eyes, short wings, and ebony bodies. Female heterozygote resulting from this cross, which had red eyes, long wings, and gray bodies, were then crossed with males with white eyes, short wings, and ebony bodies. The F2 generation data is obtained below: 1299 white eyes, short wings, ebony bodies 1367 red eyes, long wings, gray bodies 99 white eyes, short wings, gray body 89 red eyes, long wings, ebony bodies 49 white eyes, long wings, ebony bodies 49 red eyes, short wings, gray bodies 1 red eyes, short wings, ebony bodies 1 white eyes, long wings, gray bodies A) Calculate the map distance separating the three genes B) Which gene is in the middle?arrow_forwardIn Drosophila melanogaster, red eyes are dominant over white and the variation for this characteristic is on the X chromosome. Vestigial wings (v) are recessive to normal (V) for an autosomal gene. Predict the appearance of offspring of the following crosses: XW/XwV/v×Xw/Y v/v, Xw/XwV/v×XW/Y V/v.arrow_forwardMales of many diploid species (like us) have X and Y sex chromosomes. They are hemizygous for most X- linked genes. Thus, males express most X-linked alleles, whether they are dominant or recessive in females. In the fruit fly Drosophila, it is common to achieve the equivalent of a test cross of X-linked genes in females by assessing the readily observed phenotypes of their male progeny. Since males do not receive X-linked genes from their father, sires of these crosses can be normal or wild-type flies. In fly genetics, it is conventional to name a gene after the mutant phenotype that enabled its discovery. Your challenge is to establish gene order and map distances between three X-linked genes in Drosophila. Each gene is represented by recessive mutant alleles that express rather distinctive phenotypes relative to their dominant wild-type alternative alleles. Flies expressing fruitless (f) are bisexual, lush (1) have a heightened responses to ethanol, and ken&barbie (kb) lack external…arrow_forward
- Draw a Punnett square for the dihybrid cross. There are two known alleles of gene occupying a specific locus in the X chromosome. The gene in question codes for a transcription factor involved in digit development. The mutant allele is dominant and gives rise to an additional but non-functioning little finger (polydactyly) on both hands. A couple have had their DNA sequenced at the region of interest, the male exhibits polydactyly because of the mutation, the female is homozygous wild type at the same locus and therefore has the wild type phenotype. Both have green eyes. In this story; eye colour shows a monogenic autosomal inheritance pattern and the allele for brown eyes shows incomplete dominance with that for blue eyes, the heterozygote phenotype is green eyes. The genes for eye colour and polydactyly show no linkage.arrow_forwardButterflies have an X-Y sex-determination system that is different from that of flies or humans. Female butterflies may be either XY or X0, while butterflies with two or more X chromosomes are males. This photograph shows a tiger swallowtail gynandromorph, which is half male (left side) and half female (right side). Given that the first division of the zygote divides the embryo into the future right and left halves of the butterfly, propose a hypothesis that explains how nondisjunction during the first mitosis might have produced this unusual-looking butterfly. Question is also in the picture.arrow_forwardAnother cross in Drosophila involved the recessive, X-linked genes yellow (y), white (w), and cut (ct). A yellow-bodied, white-eyed female with normal wings was crossed to a male whose eyes and body were normal but whose wings were cut. The F1 females were wild type for all three traits, while the F1 males expressed the yellow-body and white-eye traits. The cross was carried to an F2 progeny, and only male offspring were tallied. On the basis of the data shown here, a genetic map was constructed. Phenotype Male Offspring y + ct 9 + w + 6 y w ct 90 + + + 95 + + ct 424 y w + 376 y + + 0 + w ct 0 (a) Diagram the genotypes of the F1 parents. (b) Construct a map, assuming that white is at locus 1.5 on the X chromosome. (c) Were any double-crossover offspring expected? (d) Could the F2 female offspring be used to construct the map? Why or why not?arrow_forward
- : In Drosophila, yellow body is due to an X-linked gene that is recessive to the gene forgray body.(a) A homozygous gray female is crossed with a yellow male. The F1 are intercrossed toproduce F2. Give the genotypes and phenotypes, along with the expected proportions, of theF1 and F2 progeny.(b) A yellow female is crossed with a gray male. The F1 are intercrossed to produce the F2.Give the genotypes and phenotypes, along with the expected proportions, of the F1 and F2progeny.(c) A yellow female is crossed with a gray male. The F1 females are backcrossed with graymales. Give the genotypes and phenotypes, along with the expected proportions, of the F2progeny.(d) If the F2 flies in part b mate randomly, what are the expected phenotypic proportions offlies in the F3??arrow_forwardThe following X-linked recessive traits are found in fruit flies:vermilion eyes are recessive to red eyes, miniature wings are recessiveto long wings, and sable body is recessive to gray body. A cross wasmade between wild-type males with red eyes, long wings, and graybodies and females with vermilion eyes, miniature wings, and sablebodies. The heterozygous female offspring from this cross, whichhad red eyes, long wings, and gray bodies, were then crossed tomales with vermilion eyes, miniature wings, and sable bodies. Thefollowing data were obtained for the F2 generation (including bothmales and females):1320 vermilion eyes, miniature wings, sable body1346 red eyes, long wings, gray body102 vermilion eyes, miniature wings, gray body90 red eyes, long wings, sable body42 vermilion eyes, long wings, gray body48 red eyes, miniature wings, sable body2 vermilion eyes, long wings, sable body1 red eyes, miniature wings, gray bodyAnalyze data. Make a drawing. Make a calculation.arrow_forwardThe following X-linked recessive traits are found in fruit flies:vermilion eyes are recessive to red eyes, miniature wings are recessiveto long wings, and sable body is recessive to gray body. A cross wasmade between wild-type males with red eyes, long wings, and graybodies and females with vermilion eyes, miniature wings, and sablebodies. The heterozygous female offspring from this cross, whichhad red eyes, long wings, and gray bodies, were then crossed tomales with vermilion eyes, miniature wings, and sable bodies. Thefollowing data were obtained for the F2 generation (including bothmales and females):1320 vermilion eyes, miniature wings, sable body1346 red eyes, long wings, gray body102 vermilion eyes, miniature wings, gray body90 red eyes, long wings, sable body42 vermilion eyes, long wings, gray body48 red eyes, miniature wings, sable body2 vermilion eyes, long wings, sable body1 red eyes, miniature wings, gray bodyWhat information do you know based on the question and your…arrow_forward
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