Human Heredity: Principles and Issues (MindTap Course List)
11th Edition
ISBN: 9781305251052
Author: Michael Cummings
Publisher: Cengage Learning
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Chapter 7, Problem 17QP
Equalizing the Expression of X Chromosome Genes in Males and Females
How many Barr bodies would the following individuals have?
- a. normal male
- b. normal female
- c. Klinefelter male
- d. Turner female
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Chapter 7 Solutions
Human Heredity: Principles and Issues (MindTap Course List)
Ch. 7.6 - Prob. 1EGCh. 7.6 - Prob. 2EGCh. 7 - As outlined in this chapter, sex can be defined at...Ch. 7 - As outlined in this chapter, sex can be defined at...Ch. 7 - Prob. 1QPCh. 7 - The Human Reproductive System Discuss and compare...Ch. 7 - Prob. 3QPCh. 7 - A Survey of Human Development from Fertilization...Ch. 7 - Prob. 5QPCh. 7 - Prob. 6QP
Ch. 7 - Prob. 7QPCh. 7 - How Is Sex Determined? The absence of a Y...Ch. 7 - Prob. 9QPCh. 7 - Mutations Can Uncouple Chromosomal Sex from...Ch. 7 - Prob. 11QPCh. 7 - Mutations Can Uncouple chromosomal Sex from...Ch. 7 - Prob. 13QPCh. 7 - Sex-Influenced and Sex-Limited Traits What method...Ch. 7 - Prob. 15QPCh. 7 - Prob. 16QPCh. 7 - Equalizing the Expression of X Chromosome Genes in...Ch. 7 - Equalizing the Expression of X Chromosome Genes in...Ch. 7 - Equalizing the Expression of X Chromosome Genes in...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- Barr bodies are formed to adjust X chromosome dosage in species other than humans, such as Drosophila (fruit flies) and C. elegans (nematodes). True or False ?arrow_forwardA woman with normal chromosomes mates with a man who also has normal chromosomes. a. Suppose that, in the course of oogenesis, the woman’s sex chromosomes undergo nondisjunction in meiosis I; the man’s chromosomes separate normally. Give all possible combinations of sex chromosomes that this couple’s children might inherit and the number of Barr bodies that you would expect to see in each of the cells of each child. b. What chromosome combinations and numbers of Barr bodies would you expect to see if the chromosomes separate normally in oogenesis, but nondisjunction of the sex chromosomes takes place in meiosis I of spermatogenesis?arrow_forwardHow many Barr bodies would you expect to find in humans withthe following abnormal compositions of sex chromosomes?A. XXYB. XYYC. XXXD. X0 (a person with just a single X chromosome)arrow_forward
- A man who is color blind and has hemophilia and a woman who is neither color blind nor a hemophiliac have a daughter with triple X syndrome (XXX) who has hemophilia and is color blind. Where did the nondisjunction occur? Group of answer choices a. Paternal meiosis II only b. Maternal meiosis II or paternal meiosis I c. Maternal meiosis I or paternal meiosis II d. Paternal meiosis II or maternal meiosis II e. Maternal meiosis II only (b is not the right answer)arrow_forwardAn individual is heterozygous for a reciprocal translocation, with the following chromosomes: A • B C D E F A • B C V W X R S T • U D E F R S T • U V W X a. Draw a picture of these chromosomes pairing in prophase I of meiosis. b. Draw the products of alternate, adjacent-1, and adjacent-2 segregations. c. Explain why the fertility of this individual is likely to be less than the fertility of an individual without a translocation.arrow_forwardGive only typing answer with explanation and conclusion What is a Barr body? How many Barr bodies would you expect to see in human cells containing the following chromosomes? XY XO XXY XXYY XXXY XYY XXX XXXXarrow_forward
- 2) A. Explain how polyribosomes form. B. Why might you expect the insertion of 3 DNA base pairs to be less disruptive than th deletion of a single base pair? C. Compare and contrast mitosis and meiosis with respect to their genetic outcomes? D. What are the possible consequences of non-disjunction during cell division? E. How does meiosis increase genetic diversity in populations?arrow_forwardSex-reversed females with XY were found to be missing SRY gene on their Y chromosomes, while sex-reversed males with XX were found to carry a portion of a Y chromosome that has the SRY gene. What can you conclude from these two cases? 1.Sex determination depends primarily on the combination of sex chromosomes and the presence of SRY gene. 2.X and Y chromosomes can’t pair up during meiosis because they are not true homologous chromosomes. 3.Nonreciprocal crossover could result in translocation of the SRY gene between X and Y chromosome. 4. The SRY gene has a key role to determine maleness. 5.The Y chromosome contains a gene that determine maleness.arrow_forwardA. How many gamete classes would be formed from the following genotype: Tt Rr Ss Gg Yy? B. Deduce a simple formula for predicting the classes of gametes formed for heterozygous, diploid organisms, that can take into account number of genes being considered. Tt; TtRr; AaTtRr.arrow_forward
- An individual has the following genotype. Gene loci (A) and (B) are 15 m.u. apart. What are the correct frequencies of some of the gametes that car be made by this individual? Bl a O A. Ab = 7.5%; AB = 42.5% B. ab = 25%; aB = 50% O C. AB = 7.5%; aB = 42.5% O D. aB = 15%; Ab = F0% E. aB = 70%; Ab = 15% Reset Selection OMark for Review What's This?arrow_forwardWhat is/are the phenotypes of the recombinant offspring of the F2generation?a. red eyes, long wingsb. white eyes, miniature wingsc. red eyes, long wings and white eyes, miniature wingsd. red eyes, miniature wings and white eyes, long wings [Answer the multiple-choice questions based on the following experiment:P generation: True-breeding flies with red eyes and long wings werecrossed to flies with white eyes and miniature wings. All F1 offspringhad red eyes and long wings.The F1 female flies were then crossed to males with white eyes and miniaturewings. The following results were obtained for the F2 generation:129 red eyes, long wings133 white eyes, miniature wings71 red eyes, miniature wings67 white eyes, long wings]arrow_forwardA. Give 7 genes located on X chromosomes and provide 2 protein products of each gene. B. Give 4 genes located on Y chromosomes and provide 2 protein products of each gene.arrow_forward
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