Introduction to Genetic Analysis
11th Edition
ISBN: 9781464109485
Author: Anthony J.F. Griffiths, Susan R. Wessler, Sean B. Carroll, John Doebley
Publisher: W. H. Freeman
expand_more
expand_more
format_list_bulleted
Question
Chapter 4, Problem 67P
Summary Introduction
To determine: The pattern, frequency, and relevance for the given red and blue balls.
Introduction. The given question indicates that the blue and red balls stop at the end of the bowling lane. The balls stop in a fashion like a tetrad formation that takes place during the meiosis division.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
(7) In a family-based alcohol use disorder genetic study, a total of 50 families, each with a pair of
siblings, were recruited. The result showed that 12 families have the 1" siblings with marijuana
dependence and the 2nd siblings without the disorder, while another 11 families are opposite (i.e. the 1st
siblings without the disorder but the 2nd siblings with the disorder). In contrast, 20 families have both
siblings exhibiting the disorder and another 17 families have both siblings without the disorder. What
kind of heritability can you calculate using this family study and what is the heritability value for
alcohol use disorder?
A) Narrow-sense heritability, approximately 88%
B) Narrow-sense heritability, approximately 44%
C) Broad-sense heritability, approximately 88%
D) Broad-sense heritability, approximately 44%
A scientist investigating the genome of two related individuals observes a difference of a few nucleotides in one individual compared to the other. The nucleotide differences are
in a region of noncoding DNA on chromosome 1. Would these differences be considered a mutation? Why or why not?
Yes, the difference in nucleotide sequences between the individuals is a mutation because it will affect the phenotype of the two individuals.
Yes, any heritable variation in the nucleotide sequence is considered a mutation, even if that variation is in a noncoding region of DNA.
Not enough information was provided to determine if this nucleotide difference is a mutation because the effect on phenotype is unknown.
No, the change in nucleotide sequence doesn't appear in a coding region of the DNA and so can't be a mutation.
A blood stain from a crime scene and blood samples from four suspects were analyzed by PCR using fluorescent primers associated with three STR loci: D3S1358, vWA, and FGA. The resulting electrophoretograms are shown below. The numbers beneath each peak identify the allele (upper box) and the height of the peak in relative fluorescence units (lower box). Solve, (a) Since everyone has two copies of each chromosome and therefore, two alleles of each gene, what accounts for the appearance ofonly one allele at some loci? (b) Which suspect is a possible source of the blood? (c) Could the suspect be identifi ed using just one of the three STR loci? (d) What can you conclude about the amount of DNA obtained from Suspect 1 compared to Suspect 4?
Chapter 4 Solutions
Introduction to Genetic Analysis
Ch. 4 - Prob. 1PCh. 4 - Prob. 5PCh. 4 - Prob. 12PCh. 4 - Prob. 13PCh. 4 - Prob. 14PCh. 4 - Prob. 15PCh. 4 - Prob. 16PCh. 4 - Prob. 17PCh. 4 - Prob. 18PCh. 4 - Prob. 19P
Ch. 4 - Prob. 20PCh. 4 - Prob. 21PCh. 4 - Prob. 21.1PCh. 4 - Prob. 21.2PCh. 4 - Prob. 21.3PCh. 4 - Prob. 21.4PCh. 4 - Prob. 21.5PCh. 4 - Prob. 21.6PCh. 4 - Prob. 21.7PCh. 4 - Prob. 21.8PCh. 4 - Prob. 21.9PCh. 4 - Prob. 21.10PCh. 4 - Prob. 21.11PCh. 4 - Prob. 21.12PCh. 4 - Prob. 21.13PCh. 4 - Prob. 21.14PCh. 4 - Prob. 21.15PCh. 4 - Prob. 21.16PCh. 4 - Prob. 21.17PCh. 4 - Prob. 21.18PCh. 4 - Prob. 21.19PCh. 4 - Prob. 21.20PCh. 4 - Prob. 21.21PCh. 4 - Prob. 21.22PCh. 4 - Prob. 21.23PCh. 4 - Prob. 21.24PCh. 4 - Prob. 21.25PCh. 4 - Prob. 21.26PCh. 4 - Prob. 22PCh. 4 - Prob. 23PCh. 4 - Prob. 24PCh. 4 - Prob. 25PCh. 4 - Prob. 26PCh. 4 - Prob. 27PCh. 4 - Prob. 28PCh. 4 - Prob. 29PCh. 4 - Prob. 30PCh. 4 - Prob. 31PCh. 4 - Prob. 32PCh. 4 - Prob. 33PCh. 4 - Prob. 34PCh. 4 - Prob. 35PCh. 4 - Prob. 36PCh. 4 - Prob. 37PCh. 4 - Prob. 38PCh. 4 - Prob. 38.1PCh. 4 - Prob. 38.2PCh. 4 - Prob. 38.3PCh. 4 - Prob. 38.4PCh. 4 - Prob. 38.5PCh. 4 - Prob. 38.6PCh. 4 - Prob. 38.7PCh. 4 - Prob. 38.8PCh. 4 - Prob. 38.9PCh. 4 - Prob. 38.10PCh. 4 - Prob. 38.11PCh. 4 - Prob. 38.12PCh. 4 - Prob. 38.13PCh. 4 - Prob. 38.14PCh. 4 - Prob. 38.15PCh. 4 - Prob. 38.16PCh. 4 - Prob. 38.17PCh. 4 - Prob. 38.18PCh. 4 - Prob. 38.19PCh. 4 - Prob. 38.20PCh. 4 - Prob. 38.21PCh. 4 - Prob. 38.22PCh. 4 - Prob. 38.23PCh. 4 - Prob. 38.24PCh. 4 - Prob. 39PCh. 4 - Prob. 40PCh. 4 - Prob. 41PCh. 4 - Prob. 42PCh. 4 - Prob. 43PCh. 4 - Prob. 44PCh. 4 - Prob. 45PCh. 4 - Prob. 46PCh. 4 - Prob. 47PCh. 4 - Prob. 48PCh. 4 - Prob. 49PCh. 4 - Prob. 50PCh. 4 - Prob. 51PCh. 4 - Prob. 52PCh. 4 - Prob. 53PCh. 4 - Prob. 54PCh. 4 - Prob. 55PCh. 4 - Prob. 56PCh. 4 - Prob. 57PCh. 4 - Prob. 58PCh. 4 - Prob. 59PCh. 4 - Prob. 60PCh. 4 - Prob. 62PCh. 4 - Prob. 63PCh. 4 - Prob. 64PCh. 4 - Prob. 65PCh. 4 - Prob. 66PCh. 4 - Prob. 67PCh. 4 - Prob. 68PCh. 4 - Prob. 69P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- Pedigree Analysis Is a Basic Method in Human Genetic: What does OMIM stand for? What kinds of information are in this database?arrow_forwardWhat genetic model of an organism is the most ideal? And why is it an ideal model in genetics?arrow_forwardWhy is knowing the genetic basis of a trait such as blond hair important? Why would scientists go to the trouble to investigate the genetic basis of blond hair in Solomon Islanders?arrow_forward
- In a family-based genetic study for a mental disorder called marijuana dependence, a total of 50 families, each with a pair of siblings, were recruited. The result showed that 11 families have the 1st siblings with marijuana dependence and the 2nd siblings without the disorder, while another 9 families are opposite (i.e. the 1st siblings without the disorder but the 2nd siblings with the disorder). In contrast, 13 families have both siblings exhibiting the disorder and another 17 families have both siblings without the disorder. What kind of heritability can you calculate using this family study and what is the heritability value for marijuana dependence? O A. Broad-sense heritability, approximately 38% B. Narrow-sense heritability, approximately 38% O. Narrow-sense heritability, approximately 76% O D. Broad-sense heritability, approximately 76%arrow_forwardA couple enters your genetic counseling clinic for some family planning advice. The woman’s father was color blind, but her own vision is normal. The man has no family history of color blindness. Neither the man nor woman have any known history of hemophilia, but their first child (a boy) has hemophilia. They ask you to calculate the chance that their nextchild will be affected by one or both conditions. You remember from your genetics training that these are both X-linked recessive conditions and that they are closely linked: in fact, their genetic loci are separated by only 10cM! During the interview with this couple, you draw the following pedigree to represent their information. Given what you know, determine for this couple what chance they have of each of the following (in the table).arrow_forwardI have seen that this was answered as C, Why is the answer C, how is that not evidence of it being genetic? Shouldnt it be none of the above? Question: Of the following, which supports the idea that alcoholism has no genetic or a low genetic component? a) Some strains of mice select alcohol over water 75% of the time, whereas others shun alcohol. b) The concordance value is 55% for MZ twins and 28% for DZ twins. c) Biological sons of alcoholic men who have been adopted have a rate of alcoholism more like that of their adoptive fathers. d) There is a 20% to 25% risk of alcoholism in the sons of alcoholic men. e) None of these.arrow_forward
- As the leading scientist in a biomedical science laboratory, it is a requirement to give advice to your lab assistants when they are having problems with their experiments. What advice would you give to your assistants that are having the following problems: After performing a polymerase chain reaction (PCR) and agarose gel electrophoresis to confirm the presence of the C01 gene of 750bp. 2.1. They observe no band appearing on an agarose gel. What would be your conclusion? 2.2. They observe three bands of different sizes that resemble a smear on the gel. Advice 2.3. They observe a single band on the gel and conclude that the PCR product is an exact copy of the original template DNA. Would you support their condusion? Explain. 2.4. Explain how PCR can be used to detect infectious agents in diagnoses of diseases.arrow_forwardPeople who carry a theoretical genetic disorder (called B-disease) can be identified from a 2kb DNA sequence. People who carry this genetic disorder have a single nucleotide polymorphism that results in a change of GTATCC to GGATCC, a site that only occurs once at nucleotide number 750 in this DNA sequence. Answer the following questions based on the information provided. (a) How can you develop a simple molecular test to identify the genetic disorder?r B-dif w. (41 (b) If you have carried out the molecular test (based on the information above) on a 100 individual and found that 24 were healthy (BB) and 26 were carriers (bb); 1) What is the ratio of heterozygous? 2) Show how can you identify the three types from the agarose gel (H focaiarrow_forwardYou are using the restriction enzyme HAEIII to digest different samples of the taster gene isolated from cheek cells of different people and amplified by PCR. When viewing the bands on the electrophoresis gel, one would expect that a taster (homozygote) would have---------band(s), whereas a carrier (heterozygote) would show--------band(s), and a non-taster would show------band(s).arrow_forward
- 24. 23andme is a direct to consumer genotyping company that uses a microarray to genotype people on 1 million known SNPS in the genome. A man who was adopted wants to know about his ancestry, and purchases a 23andme kit for himself. He finds that of each autosome pair, exactly one is classified as 100% Sub-Saharan African, while the other is a mixture of various East Asian and European components. He also finds that his X chromosome is 100% Sub-Saharan African. What can this man confidently infer about his recent ancestry? a. His mother was of Sub-Saharan African descent b. His father was of Sub-Saharan African descent c. He has no Neanderthal ancestry d. He has no mutations relative to his parents e. 23andme mixed up two samples and he can't infer anythingarrow_forwardRonan Farrow, son of the actress Mia Farrow, has grown up thinking that Woody Allen is his father. But Vanity Fair broke the story that Frank Sinatra might be Ronan's actual father. Vanity Fair would like to confirm the story but they are almost bankrupt. So they hire you. You're also almost bankrupt and can't afford to pay for full genome sequencing. You should be able to solve the case by sequencing a short stretch of DNA from one chromosome from Ronan and comparing it to a sequence from the same chromosome in Woody Allen. Which chromosome would you choose for your sequencing project v Choose... X-Chromosome It turns out that Woody Allen will not cooperate with this project. Ba Any autosomal chromosome nce Y-Chromosome information from which living individual, if any, can you use to solve the Relatives of Woody Allen Relatives of Frank Sinatra Woody Allen Mia Farrow Mia Farrow Frank Sinatra 4 4 6 II 1 ? II ? 2 Ronan might be Woody's son Ronan might be Frank's son 3. 2.arrow_forwardWhat is the importance of Gregor Mendel’s Law of Inheritance in Molecular Biology?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Human Heredity: Principles and Issues (MindTap Co...BiologyISBN:9781305251052Author:Michael CummingsPublisher:Cengage LearningBiology (MindTap Course List)BiologyISBN:9781337392938Author:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. BergPublisher:Cengage Learning
Human Heredity: Principles and Issues (MindTap Co...
Biology
ISBN:9781305251052
Author:Michael Cummings
Publisher:Cengage Learning
Biology (MindTap Course List)
Biology
ISBN:9781337392938
Author:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. Berg
Publisher:Cengage Learning
Serology 101: Testing for IgG and IgM antibodies; Author: Beckman Coulter Dx;https://www.youtube.com/watch?v=LtqKB-qpJrs;License: Standard youtube license