Introduction to Genetic Analysis
11th Edition
ISBN: 9781464109485
Author: Anthony J.F. Griffiths, Susan R. Wessler, Sean B. Carroll, John Doebley
Publisher: W. H. Freeman
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 4, Problem 53P
Summary Introduction
To explain: If the test cross between F1 progeny obtained from the parental genotypes A/A · B/B and a/a · b/b and homozygous recessive genotype a/a · b/b provides any evidence of linkage.
Introduction: The linkage between the two genes indicates that the loci of those genes are on the same chromosome. When the two genes are linked, they do not assort independently and do not follow the classical Mendelian ratio, 1:1:1:1.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
From parents of genotypes A/A ⋅ B/B and a/a ⋅ b/b, adihybrid was produced. In a testcross of the dihybrid,the following seven progeny were obtained:A/a ⋅ B/b, a/a ⋅ b/b, A/a ⋅ B/b, A/a ⋅ b/b,a/a ⋅ b/b, A/a ⋅ B/b, and a/a ⋅ B/bDo these results provide convincing evidence of linkage?
The genotype of EB27 and EB67 are unknown. Based on pedigree, what are the most likely genotype of each individual?
What will be the PR and GR of the following crosses? Give also their phenotypes. (Designate your own phenotype for each character)
AaBb x aabb
AAbb x AaBB
AaBb x aaBB
AABb x aabb
Chapter 4 Solutions
Introduction to Genetic Analysis
Ch. 4 - Prob. 1PCh. 4 - Prob. 5PCh. 4 - Prob. 12PCh. 4 - Prob. 13PCh. 4 - Prob. 14PCh. 4 - Prob. 15PCh. 4 - Prob. 16PCh. 4 - Prob. 17PCh. 4 - Prob. 18PCh. 4 - Prob. 19P
Ch. 4 - Prob. 20PCh. 4 - Prob. 21PCh. 4 - Prob. 21.1PCh. 4 - Prob. 21.2PCh. 4 - Prob. 21.3PCh. 4 - Prob. 21.4PCh. 4 - Prob. 21.5PCh. 4 - Prob. 21.6PCh. 4 - Prob. 21.7PCh. 4 - Prob. 21.8PCh. 4 - Prob. 21.9PCh. 4 - Prob. 21.10PCh. 4 - Prob. 21.11PCh. 4 - Prob. 21.12PCh. 4 - Prob. 21.13PCh. 4 - Prob. 21.14PCh. 4 - Prob. 21.15PCh. 4 - Prob. 21.16PCh. 4 - Prob. 21.17PCh. 4 - Prob. 21.18PCh. 4 - Prob. 21.19PCh. 4 - Prob. 21.20PCh. 4 - Prob. 21.21PCh. 4 - Prob. 21.22PCh. 4 - Prob. 21.23PCh. 4 - Prob. 21.24PCh. 4 - Prob. 21.25PCh. 4 - Prob. 21.26PCh. 4 - Prob. 22PCh. 4 - Prob. 23PCh. 4 - Prob. 24PCh. 4 - Prob. 25PCh. 4 - Prob. 26PCh. 4 - Prob. 27PCh. 4 - Prob. 28PCh. 4 - Prob. 29PCh. 4 - Prob. 30PCh. 4 - Prob. 31PCh. 4 - Prob. 32PCh. 4 - Prob. 33PCh. 4 - Prob. 34PCh. 4 - Prob. 35PCh. 4 - Prob. 36PCh. 4 - Prob. 37PCh. 4 - Prob. 38PCh. 4 - Prob. 38.1PCh. 4 - Prob. 38.2PCh. 4 - Prob. 38.3PCh. 4 - Prob. 38.4PCh. 4 - Prob. 38.5PCh. 4 - Prob. 38.6PCh. 4 - Prob. 38.7PCh. 4 - Prob. 38.8PCh. 4 - Prob. 38.9PCh. 4 - Prob. 38.10PCh. 4 - Prob. 38.11PCh. 4 - Prob. 38.12PCh. 4 - Prob. 38.13PCh. 4 - Prob. 38.14PCh. 4 - Prob. 38.15PCh. 4 - Prob. 38.16PCh. 4 - Prob. 38.17PCh. 4 - Prob. 38.18PCh. 4 - Prob. 38.19PCh. 4 - Prob. 38.20PCh. 4 - Prob. 38.21PCh. 4 - Prob. 38.22PCh. 4 - Prob. 38.23PCh. 4 - Prob. 38.24PCh. 4 - Prob. 39PCh. 4 - Prob. 40PCh. 4 - Prob. 41PCh. 4 - Prob. 42PCh. 4 - Prob. 43PCh. 4 - Prob. 44PCh. 4 - Prob. 45PCh. 4 - Prob. 46PCh. 4 - Prob. 47PCh. 4 - Prob. 48PCh. 4 - Prob. 49PCh. 4 - Prob. 50PCh. 4 - Prob. 51PCh. 4 - Prob. 52PCh. 4 - Prob. 53PCh. 4 - Prob. 54PCh. 4 - Prob. 55PCh. 4 - Prob. 56PCh. 4 - Prob. 57PCh. 4 - Prob. 58PCh. 4 - Prob. 59PCh. 4 - Prob. 60PCh. 4 - Prob. 62PCh. 4 - Prob. 63PCh. 4 - Prob. 64PCh. 4 - Prob. 65PCh. 4 - Prob. 66PCh. 4 - Prob. 67PCh. 4 - Prob. 68PCh. 4 - Prob. 69P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- The following pedigree shows the incidence of ABO blood types in a family. Which individual(s) is/are a known homozygote for blood type? What is/are the possible genotype(s) of individual III-2? What is/are the possible genotype(s) of individual III-3?arrow_forwardThe expected ratio of phenotypes among the progeny of a test cross is 1:1:1:1. Out of 200 total resulting progeny, 48 occur in one of the four phenotypic classes. Given this information, which of the following must also be true? a)At least one additional cell must also contain a count of 48. b)The progeny of this cross do not conform to a 1:1:1:1ratio. c)The value of observed - expected for this cell = -2. d)Since 48 is so close to the expected value, there is no need to calculate chi square before drawing a conclusion about the ratio.arrow_forwardConsider the following dihybrid testcross: B/b • E/e × b/b • e/e For the progeny from this testcross, determine the relative proportions (from 0% to 100%) of each genotype if the two genes: a) are linked (dominant alleles in cis conformation) with no crossing over: Be/be: be/be: BE/be: bE/be: b) assort independently. B/b; E/e: B/b; e/e: b/b; E/e: b/b; e/e: c) are linked (dominant alleles in cis conformation) and 20 map units apart. Be/be: be/be: BE/be: bE/be:arrow_forward
- An individual with the genotype F/f • G/g • H/h is testcrossed. Among the progeny, the proportions of genotypes from this cross are shown in the following table: a) What gene is in the middle? Type you answer in this box: b) Calculate the genetic distances (in centimorgans, cM) between: genes g and f: genes f and h: genes g and h: c) What are the genotypes of the two parents? d) Calculate the interference and type your answer here:arrow_forwardA three-point cross was conducted, 8500 progeny were evaluated, and the genetic map was determined to be:Gene J----3mu----Gene K-----5mu-----Gene LA total of 8 double cross-over progeny were identified among the 8,500 evaluated. What is the coefficient of coincidence?arrow_forwardIn poultry , the genotype-phenotype relationship for comb shape are R/-P/-, walnut. R/-p/p rose, r/rP/-,pea and r/r/p/p single.what will be the following crosses? a)A rose rose crossed with a walnut produces offspring that are walnut ,rose,pea and single. b)A rose crossed with a pea produces five walnut and six rose offspring. c) A walnut crossed with a walnut produces one rose two walnut and one single offspring.arrow_forward
- The trihybrid e+f+g+/efg is test crossed to the triple recessive efg/efg and the following genotypes were obtained in the progeny: efg = 2; efg = 28; e'fg* = 9; e*rg 32; efg 73; e*fg* = 10; ef g* =10; e'fg 2; %3D "The odd gene is The gene order is The gene distance between e-f is The gene distance between f-g is The gene distance between e-g isarrow_forwardThe A & B antigens in humans may be found in water-soluble forms in secretions, including saliva of individuals with the genotypes E/E& E/e, but not individuals with the genotype e/e. Thus, the population contains ‘secretors’ & ‘nonsecretors’. A cross was performed between 2 heterozygous secretors, one with type O blood and the second with type AB blood. What phenotypic ratios are expected in their offspring? A) 1/4 type A : 1/4 type B : 1/2 non-secretor B) 3/8 type A : 3/8 type B : 2/8 non-secretor C) 1/2 type A : 1/2 type B D) 3/4 type AB : 1/4 non-secretorarrow_forwardA dihybrid cross is performed between two heterozygous individuals (heterozygous for two traits). The resulting offspring had 62 individuals that were dominant for trait 1 and 2 (D/D), 7 individuals that were R/R, 21 individuals that were R/D, and 25 individuals that were D/R. Using Mendelian inheritance as the null hypothesis, use χ2 analysis to determine if the trait follows Mendelian inheritance. A. How many D/D phenotype offspring are expected? B. How many R/D phenotype offspring are expected? C. How many degrees of freedom are there? D. What is your calculated χ2 value? E. What is the critical value if using a probability of 0.05? F. Does the trait follow Mendelian inheritance?arrow_forward
- These genotypes are crossed: AaBbCcdd x AabbCcDd. What will the proportion of thefollowing genotypes be among the progeny of this cross? (Show your solution and put the final answerin a box).a) AAbbCcdd b) AaBbCcDdarrow_forwardA purple flowering, smooth seed dihybrid plant (genotype PpSs) is test crossed with a white flowering, wrinkled seed plant (genotype ppss). These produce progeny in the following numbers of four phenotypes: 24:76:74:26 (purple flower + smooth seed coat: purple flower + wrinkled seed coat: white flower + smooth seed coat: white flower + wrinkled seed coat). a) What is the genotype of the original dihybrid plant? Specify which alleles are on each chromosome of the purple flowering, smooth seed plant (i.e. AB/ab or Ab/aB). b) How many map units separate the colour and seed coat genes? Show your calculations.arrow_forwardGive an example of a monohybrid cross and a dihybrid cross.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Human Heredity: Principles and Issues (MindTap Co...BiologyISBN:9781305251052Author:Michael CummingsPublisher:Cengage Learning
Human Heredity: Principles and Issues (MindTap Co...
Biology
ISBN:9781305251052
Author:Michael Cummings
Publisher:Cengage Learning
How to solve genetics probability problems; Author: Shomu's Biology;https://www.youtube.com/watch?v=R0yjfb1ooUs;License: Standard YouTube License, CC-BY
Beyond Mendelian Genetics: Complex Patterns of Inheritance; Author: Professor Dave Explains;https://www.youtube.com/watch?v=-EmvmBuK-B8;License: Standard YouTube License, CC-BY