Concept explainers
a.
To determine: The pedigree chart for the whole family.
Introduction. The human consists of 23 pairs of chromosomes, condensed form of chromatids which divide during cell division into daughter cells. The human has 22 autosomes and one pair of sex chromosomes. The sex chromosomes determine the sex in an individual based on the type of sex chromosomes that are present in the fusing gametes.
b.
To determine: The agreement of the pedigree with the hypothesis that Rh+ is dominant allele and Rh- is recessive.
Introduction. The pedigree chart helps to depict the complete history of the pattern of inheritance of genetic disease from one generation to another generation. The inheritable genetic disease is either autosomal dominant or recessive or sex-linked based on which the probability of disease in a future generation can be predicted.
c.
To determine: The mechanism of the transmission of elliptocytosis.
Introduction. The dominant allele masks the expression of the recessive allele. Therefore the dominant allele is expressed in homozygous and heterozygous genotype while the recessive
d.
To determine: The presence of the genes of same chromosome that govern E and Rh phenotypes.
Introduction. Recombination is the process that is exclusive to the meiotic division as it allows the exchange of genetic material between the non-homologous chromosomes. The recombination process is responsible for the shuffling of the characters and producing a zygote that is different from both the parents but have the chromosomes from both the parents.
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Introduction to Genetic Analysis
- What would the offspring's blood type be if the mother is type O+ (she is homozygous for Rh factor) and the father is A- (he is homozygous for type A)? Hint: You have to do two Punnett squares. The two Punnett squares must be shown to get the full points. After doing the Punnett squares, write down the possibilities of the offspring’s blood type.arrow_forwardThe following scenario can be seen on Ch 29 Clinical case study on Heredity (27-year-old with normal pregnancy): Mrs. Rodriguez’ blood type is type O, and her husband’s is type A. She is currently pregnant and she would like to know what type of blood her baby will have. For discussion 7 please answer the following questions: What are the genotype and phenotype of Mrs. Rodriguez? What are the genotype and phenotype of Mr. Rodriguez, given that Mr. Rodriguez’s mother has O blood type and his father has A blood type? (use Punnett Square on your worksheet to find out the genotype of Mr. Rodriquez) What is the probability that Mrs. Rodriguez’s baby will have O blood type? A? B? AB? (use Punnett Square as your worksheet) Type O =______% Type A = _____ % Type B =______% Type AB =______%arrow_forwardHemophilia is an X-linked disease associated with the inability to produce specific proteins in the blood-clotting pathway. Shown above is a family pedigree tree in which family members afflicted with the disease are shown with filled-in squares (male) or circles (females). A couple is trying to determine the likelihood of passing on the disease to their future children (represented by the ? symbol above) because the hemophilia runs in the woman’s family 4.Assuming that the woman in the couple is a carrier, what is the probability that the couple’s first son will have hemophilia?arrow_forward
- Rhesus factor is a protein found onlthe surface of the red blood cells. Having Rhesus factor (Rh+) is dominant over having none (Rh-). What cross could result to Rhesus factor incompatibility? Rh- mother x Rh+ father O Rh- father x Rhesus+ mother O Rh- mother x Rh- father O Rh+ father x Rh+ motherarrow_forwardBarbara and John have two daughters (Madison and Kelly), and one son (Mike), all have normal red blood cells. Their other son (Chase) has been diagnosed with sickle cell. Barbara recently gave birth to another son (Barry) who also has been diagnosed with sickle cell. Barbara’s mother (Beth) has sickle cell, but her father (Jason), three sisters (Emma, Lori, and Allison), and two brothers (Emmitt and Will) are all normal. John’s father (Jim), mother (Brenda), and brother (Parker) are all normal, but his sister (Demi) has sickle cell. John’s maternal grandparents (Bill and Lonna) are carriers. Barbara’s paternal grandparents (Kevin and Martha) are all normal. make an pedigreearrow_forward3) Queen Victoria of England, who ruled from 1837-1901, is believed to have been the carrier of hemophilia. Hemophilia is an X-linked disease in which the blood is unable to form clots. Please make a Punnet Square using the scenario below and answer the following questions. Queen Victoria married a man who did not have the hemophilia trait or disease. What is the likelihood that they would have a child with hemophilia? What is the likelihood that they would have a son with hemophilia? What is the likelihood that they would have a daughter with hemophilia?arrow_forward
- A woman with type O blood gave birth to a baby, also with type O blood. The woman stated that a man with type AB blood was the father of the baby. Is there any merit to her statement?arrow_forwardA woman whose blood type is A- is planning on starting a family with a B+ blood type man. Which of the following is the most accurate advice that you could give to this couple based on their blood types? They should be concerned about hemolytic disease of the newborn for all of their pregnancies . Since the woman is Rh-, she produces anti-Rh antibodies. Since the man is Rh+, the fetus in all pregnancies with this man will also be Rh+. This means that the mom?s anti-Rh antibodies will destroy fetal RBCs every time that the woman gets pregnant, thus producing a dangerous anemia to all the fetuses from all pregnancies with this man. They should be concerned about hemolytic disease of the newborn. However, problems related to this condition seldom develop during a first pregnancy, because very few fetal cells enter the maternal bloodstream then, and thus the mother?s immune system is not stimulated to produce anti-Rh antibodies. However if a future pregnancy with the…arrow_forwardA man with hemophilia has a daughter of normal phenotype. She marries a man who is normal for the trait. The probability of their son to be a hemophiliac is 1/4. Its true or false? Explain.arrow_forward
- A) A woman with type O blood is expecting a child. Her husband is type A and her husband's parents both had type AB blood. What will be their child’s blood type? 2. A)A woman with type O blood is expecting a child. Her husband is type A and her husband's parents both had type AB blood. What will be their child’s blood type? B) A couple has one child with type AB blood. If one parent is heterozygous for blood type A and the other parent is homozygous for their blood type, what are the chances of their future children having: Type A blood? Type B blood? Type AB blood? O blood?arrow_forwardA woman who is a carrier for X-linked hemophilia (she does not have the disease) marries a man who does not have hemophilia. They have a daughter, named Angela, who does not have the disease. Angela marries George, who also does not have hemophilia. Angela and George have a son named Robbie. What is the chance that Robbie will have hemophilia? O 1/4 O 1/3 O 1/2 0 1/8arrow_forwardAlpha thalassemia is a hereditary blood condition that results in varying levels of anemia. It is tied to the HB alpha 1 gene and the HB alpha 2 gene on human chromosome 16. The diagram shows the proteins for the hemoglobin genes and the pedigree shows genotypes, designated by the letter X, on the chromosomes for a family affected by the condition. Which represents the predicted level of anemia in a child born to the mother and father in the image with a mutation that results in a genotype of xxxx? Why? A - mild anemia because the loss of 4 genes would equal the loss of the 4 proteins needed for normal alpha hemoglobin B - severe anemia because the loss of 4 genes would equal the loss of the 4 proteins needed for normal alpha hemoglobin C - mild anemia because the addition of 4 genes would produce too many of the proteins needed for normal alpha hemoglobin D - severe anemia because the addition of 4 genes would produce too many of the proteins needed for normal alpha hemoglobinarrow_forward