The Practice of Statistics for AP - 4th Edition
The Practice of Statistics for AP - 4th Edition
4th Edition
ISBN: 9781429245593
Author: Starnes, Daren S., Yates, Daniel S., Moore, David S.
Publisher: Macmillan Higher Education
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Chapter 3.2, Problem 37E

(a)

To determine

To find: The slope of the line

(a)

Expert Solution
Check Mark

Answer to Problem 37E

The slope is b = 1.109

Explanation of Solution

Given:

Regression line = 4.62+1.109 (city mpg)

Calculation:

On comparing our equation to general equation of regression we get, the slope is: b = 1.109

This tells us that the highway mpg is predicted to go up by 1.109 mpg for each added city mpg.

Conclusion:

Hence, the slope is: b = 1.109.

(b)

To determine

To find: The intercept and explain why the interpret value is not statistically meaningful

(b)

Expert Solution
Check Mark

Answer to Problem 37E

The intercept is: a = 4.62

Explanation of Solution

Calculation:

On comparing our equation to general equation of regression we get, the intercept is: a = 4.62

The value of the Y intercept is meaningful only when the explanatory variable can actually take values close to zero.

Conclusion:

Hence, the intercept is: a = 4.62

(c)

To determine

To find: The predicted highway mileage for a car

(c)

Expert Solution
Check Mark

Answer to Problem 37E

Predicted highway mileage for a car that gets mileage 28 mpg will be 35.672

Explanation of Solution

Calculation:

The regression line is:

(Predicted) highway mpg = 4.62+1.109 (city mpg)

When city mpg = 16 mpg then

(Predicted) highway mpg= 4.62+1.109(16)=22.364

Predicted highway mileage for a car that gets mileage 16 mpg will be 22.364

When city mpg = 28mpg then

(Predicted) highway mpg = 4.62+1.109(28)= 35.672

Predicted highway mileage for a car that gets mileage 28 mpg will be 35.672.

Conclusion:

Hence, the predicted highway mileage for a car will be 35.672.

Chapter 3 Solutions

The Practice of Statistics for AP - 4th Edition

Ch. 3.1 - Prob. 2ECh. 3.1 - Prob. 3ECh. 3.1 - Prob. 4ECh. 3.1 - Prob. 5ECh. 3.1 - Prob. 6ECh. 3.1 - Prob. 7ECh. 3.1 - Prob. 8ECh. 3.1 - Prob. 9ECh. 3.1 - Prob. 10ECh. 3.1 - Prob. 11ECh. 3.1 - Prob. 12ECh. 3.1 - Prob. 13ECh. 3.1 - Prob. 14ECh. 3.1 - Prob. 15ECh. 3.1 - Prob. 16ECh. 3.1 - Prob. 17ECh. 3.1 - Prob. 18ECh. 3.1 - Prob. 19ECh. 3.1 - Prob. 20ECh. 3.1 - Prob. 21ECh. 3.1 - Prob. 22ECh. 3.1 - Prob. 23ECh. 3.1 - Prob. 24ECh. 3.1 - Prob. 25ECh. 3.1 - Prob. 26ECh. 3.1 - Prob. 27ECh. 3.1 - Prob. 28ECh. 3.1 - Prob. 29ECh. 3.1 - Prob. 30ECh. 3.1 - Prob. 31ECh. 3.1 - Prob. 32ECh. 3.1 - Prob. 33ECh. 3.1 - Prob. 34ECh. 3.2 - Prob. 1.3CYUCh. 3.2 - Prob. 1.4CYUCh. 3.2 - Prob. 2.1CYUCh. 3.2 - Prob. 3.1CYUCh. 3.2 - Prob. 3.2CYUCh. 3.2 - Prob. 3.3CYUCh. 3.2 - Prob. 4.1CYUCh. 3.2 - Prob. 4.2CYUCh. 3.2 - Prob. 5.1CYUCh. 3.2 - Prob. 5.2CYUCh. 3.2 - Prob. 35ECh. 3.2 - Prob. 36ECh. 3.2 - Prob. 37ECh. 3.2 - Prob. 38ECh. 3.2 - Prob. 39ECh. 3.2 - Prob. 40ECh. 3.2 - Prob. 41ECh. 3.2 - Prob. 42ECh. 3.2 - Prob. 43ECh. 3.2 - Prob. 44ECh. 3.2 - Prob. 45ECh. 3.2 - Prob. 46ECh. 3.2 - Prob. 47ECh. 3.2 - Prob. 48ECh. 3.2 - Prob. 49ECh. 3.2 - Prob. 50ECh. 3.2 - Prob. 51ECh. 3.2 - Prob. 52ECh. 3.2 - Prob. 53ECh. 3.2 - Prob. 54ECh. 3.2 - Prob. 55ECh. 3.2 - Prob. 56ECh. 3.2 - Prob. 57ECh. 3.2 - Prob. 58ECh. 3.2 - Prob. 59ECh. 3.2 - Prob. 60ECh. 3.2 - Prob. 61ECh. 3.2 - Prob. 62ECh. 3.2 - Prob. 63ECh. 3.2 - Prob. 64ECh. 3.2 - Prob. 65ECh. 3.2 - Prob. 66ECh. 3.2 - Prob. 67ECh. 3.2 - Prob. 68ECh. 3.2 - Prob. 69ECh. 3.2 - Prob. 70ECh. 3.2 - Prob. 71ECh. 3.2 - Prob. 72ECh. 3.2 - Prob. 73ECh. 3.2 - Prob. 74ECh. 3.2 - Prob. 75ECh. 3.2 - Prob. 76ECh. 3.2 - Prob. 77ECh. 3.2 - Prob. 78ECh. 3.2 - Prob. 79ECh. 3.2 - Prob. 80ECh. 3.2 - Prob. 81ECh. 3 - Prob. 1CRECh. 3 - Prob. 2CRECh. 3 - Prob. 3CRECh. 3 - Prob. 4CRECh. 3 - Prob. 5CRECh. 3 - Prob. 6CRECh. 3 - Prob. 7CRECh. 3 - Prob. 1PTCh. 3 - Prob. 2PTCh. 3 - Prob. 3PTCh. 3 - Prob. 4PTCh. 3 - Prob. 5PTCh. 3 - Prob. 6PTCh. 3 - Prob. 7PTCh. 3 - Prob. 8PTCh. 3 - Prob. 9PTCh. 3 - Prob. 10PTCh. 3 - Prob. 11PTCh. 3 - Prob. 12PTCh. 3 - Prob. 13PT
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