1. An equal-tangent crest vertical curve is being designed for a speed of 45 mph. The curveconnects grades of 1.3% and -2.4% in the direction of interest. The curve high point is atstation 110+30 and has an elevation of 930 ft. What is the station and elevation of the PVCand the PVI?[Answer: PVI station: 110+50.3; PVI elevation: 930.6']

Answered: Image /qna-images/answer/bbd7527c-1321-42d7-9f42-6c712bb0abb6.jpg

1. An equal-tangent crest vertical curve is being designed connects grades of 1.3% and -2.4% in the direction of in station 110+30 and has an elevation of 930 ft. What is the and the PVI? [Answer: PVI station: 110+50.3; PVI elevation: 930.6']

1. An equal-tangent crest vertical curve is being designed connects grades of 1.3% and -2.4% in the direction of in station 110+30 and has an elevation of 930 ft. What is the and the PVI? [Answer: PVI station: 110+50.3; PVI elevation: 930.6']

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: 1. A grade of -3.7% grade intersects a grade of +2.80% at Station 11 + 488.00 of elevations 122.50…

A: G1 = -3.7% G2 = 2.8% PI Station = 11+488 PI elevation = 122.5 Vd (design velocity) = 60Km/h = 60…

Q: A parabolic vertical curve with a grade in of 2.1%, a grade out of - 3.2%, a curve length of…

A: (Note: Since part C is asked to solve, the solution for the c part is given below.) Given: Grade in,…

Q: A-3.00% grade meets a +2.50% grade at station 4 + 200 and elevation 105.568 m, 200-m curve, stakeout…

Q: The minimum length of vertical curve shall be -for a grades of 4% and 3% respectively in feet -- O…

A: Given data- Grades (n1) = 4% (n2) = 3% To Find- Minimum length of vertical curve (L)

Q: 94444% 00962% 11702% 25000% 41892% ne of the Choices

Q: A 9% grade meets a 5% grade at station 2 + 270 of elevation 150 m. The lengths are L1 = 80 m. and L2…

A: Given: The grade g1 is 9%. The grade g2 is 5%. The station PVI is 2 + 270. The elevation of PVI is…

Q: 500ft vertical curve has PVI elevation 240.31ft. the initial and final grades are 2.1% and -3.3%…

A: solution Given g1=2.1% ;g2=-3.3%so total change N =g1-g2=2.1-3.3=5.4%Length L =500ftelevation of…

Q: Question # 5 An existing crest vertical curve which connects +3% and -1% grades is designed for 55…

Q: t vertical curve has its PVI at elevation 491.52ft. The ini™ on of a point 327ft from PVC. your…

Q: 2. There is a Vertical Curve with a length of 300 feet, a gl of -3.2%, a g2 of 1.8%, a PVI at…

A: The grade of back tangent, g1=-3.2%The grade of forward tangent, g2=+1.8%The elevation of PVI…

Q: = An equal-tangent crest vertical curve with a length L unknown, has an initial grade is G₁ +2.5%…

A: G1 = 2.5% G2 = -1%

Q: A -4% grade at Sta. 5 + 700 and elev. 110.2 is to connect to a +6% grade at Sta. 6 + 100 and elev.…

A: G1 = -4% , BVC, station = 5+700 , elevation = 110.2 G1 = +6% , EVC,…

Q: Q 3: What is the maximum safe speed on a vertical crest

A: Given N= +0.03(-0.03) N=0.06 Lc=200m As, S = Stopping sight distance

Q: A +4.0% grade intersects a -3.0% percent grade al r two-lane highway with a design speed of 45 mph.…

A: Given: PVI station= 222+00 Elevation= 300.00 Design speed = V=45 mph To determine: A) the minimum…

Q: A 777m equal tangent crest vertical curve has PVC at Sta 17+315 and at elevation 189m. The initial…

A: Given data- 777m equal tangent crest vertical curve. PVC at Sta 17+315 and at elevation 189m. The…

Q: An equal tangent vertical curve is to be constructed between grades of -6.75% (initial) and 4.75%…

A: G1= -6.75% G2= 4.75%PVI station = 12+000.000 PVI elevation = 319m Station = 12 + 071.00 Elevation =…

Q: A vertical parabolic curve of length 180m has the following specifications. The point of interaction…

Q: A-4% grade line meets another line of +3.2% grade at station 11+ 40. If a 225-ft parabolic curve…

A: This question is related to Simple curve from Surveying Engineering. In this question we calculate…

Q: vertical curve has its PVI at elevation 300.55ft. The initial and n of a point 237ft from PVC. your…

Q: A 591m equal tangent crest vertical curve has PVC at Sta 19+252 and at elevation 124m. The initial…

A: Since this s an equal tangent vertical curve, distance from the center of the curve to the two…

Q: A 600ft vertical curve has its PVI at elevation 404.44ft. The initial and final grades are 3.1% and…

A: Determination of Elevation of point 364ft from PVC

Q: A 500ft vertical curve has its PVI at elevation 371.25ft. The initial and final grades are 3.4% and…

Q: forward tangent is -3.0%, and the location of the highest point elevation of the highest point is…

Q: A vertical summit curve connects a +6% grade to a -3% grade at Pl at station 150+ 00 whose elevation…

A: Answer (a) Calculation of Length of vertical curve needed to make the highest point at station 150…

Q: Q3/ A vertical curve below has a lower point (A) which exists at station (55+50) with elevation…

Q: between those two rc a. The required le b. Stationing and c. Location and el

Q: A -4% grade at Sta. 5 + 700 and elev. 110.2 is to connect to a +6% grade at Sta. 6 + 100 and elev.…

A: Determine the elevation of PCC and location of PVI.

Q: tangent is -3.0%, and the location of the highes on of the highest point is 100 m. t is the Station…

Q: A 1025 ft long vertical curve has a 4% grade on the back tangent and a -2% grade on the forward…

Q: A 524m equal tangent crest vertical curve has PVC at Sta 18+257 and at elevation 166m. The initial…

A: Given: The initial grade is 6.06%. The final grade is -3.71%. The length is 524 m. The PVC station…

Q: 1600 ft lomg equal tangent sag vertical curve has the PVI at station 120+00 and elevation 1500 ft…

A: Position of tha loest curve x=Lvn12Nhere Length of sag curve Lv=1600 ftand n1=3.5 % and…

Q: A 700ft vertical curve has its PVI at elevation 302.17ft. The initial and final grades are -4.9% and…

Q: An equal tangent crest curve connects a +2% initial grade with a -1% final grade, and is designed…

A: Grade: G1 = 2% Grade: G2 = -1% Design speed: V = 55 mi/h Station at PVI: = 233+40 Elevation of PV:=…

Q: 7. A -3% grade meets a +5% grade near an underpass. In order to maintain the minimum clearance…

A: jkjethgnfjhjjj

Q: An underpass crossing a reinforced concrete bridge has a downward grade of -4% meeting an upward…

Q: The length of curve at side of PC is 45 while on the PT is 5 having an elevation of 108.6 is found…

Q: as its PVI at elevation 336.25 ft from PVC. 3 decimal places.

Q: 800ft vertical curve has its PVI at elevation 232.25ft. The initial and final grades are

Q: A 400m vertical curve joins a +2.70% grade with a -1.50% grade. The PVI is at station 1+500 and…

A: To Find :- station and elevation of PVC

Q: a downgrade of 3.20 meets an upgrade of 4.6 at Sta. 73+180 where the elevation is 998m. A parabolic…

Q: A 618m equal tangent crest vertical curve has PVC at Sta 19+218 and at elevation 177m. The initial…

A: The gradient is, g1=4.05%g2=-6.26% The PVC station is 19+218. The length is L=618 m. The elevation…

Concept explainers

Drainage of Pavements

Pavement Drainage holds ample significance, as it prevents the accumulation of water or any liquid on the surface of pavements and ensures proper drainage system. With proper design and gradual slopes provided, the water gets easily removed from the surface into the drains, which are essential during heavy rains and unusual weather conditions keeping it less prone to accidents and increasing the durability of the pavement structure.

Question

1. An equal-tangent crest vertical curve is being designed for a speed of 45 mph. The curve
connects grades of 1.3% and -2.4% in the direction of interest. The curve high point is at
station 110+30 and has an elevation of 930 ft. What is the station and elevation of the PVC
and the PVI?
[Answer: PVI station: 110+50.3; PVI elevation: 930.6']

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1: Given that

VIEW

Step 2: PVC elevation , length of curve calculation

VIEW

Solution

VIEW

Step by step

Solved in 3 steps with 3 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

Q3/ A vertical curve below has a lower point (A) which exists at station (55+50) with elevation (1291.2 m). the back grade of (-8%) meet the forward grade of (+7.8%) at (PVI) station (54+00) with elevation (1281.5 m). determine the length of the curve with the stations of (PVC) and (PVT)? PVT PVC g₁=(-6%) PVI g₂=(+5.8%)
A 777m equal tangent crest vertical curve has PVC at Sta 16+430 and at elevation 115m. The initial grade is 7.9% and the final grade is -3.3%. Determine the elevation (m) of PVT.
subject: surveying 2. please give a detailed answer for me to un
A 532m equal tangent crest vertical curve has PVC at Sta 19+284 and at elevation 181m. The initial grade is 3.02% and the final grade is -4.37%. Determine the elevation (m) of PVI.
2. There is a Vertical Curve with a length of 300 feet, a g1 of -3.2%, a g2 of 1.8%, a PVI at station 20+50.00, at an elevation of 365.92. Determine the HP/LP and elevate all even 100 foot stations and the HP / LP.
3. A grade g1 of +3.25% intersects grade g2 of -2.75% at a vertex whose station and elevation are STA 257+17.65 and 3,820.14 ft, respectively. An equal-tangent parabolic curve 900 ft long has been selected to join the two tangents. a. Compute the station and elevation of PVC. b. Compute the station and elevation of the first full station inside the curve. c. Identify the station and elevation of the highest point on the curve.
Determine the equation of the curve, location of the high/low point, and theelevation of the high/low point of 1300ft vertical curve that connects anentrance grade of -2.3% and an exit grade of 5.4%. The PVI of the has anelevation of 874.32ft
2. A symmetrical sag curve has a descending grade of -4.2% and an ascending grade of +2.5% intersecting at Station 10+120, whose elevation is 382.3÷4 m. The rate of change of grade is restricted to 0.60%. a. What is the vertical offset of the parabolic curve to the point of intersection of the tangent grades? b. At what distance from PC is the lowest point of the curve located?
A 600ft vertical curve has its PVI at elevation 264.96ft. The initial and final grades are 2.1% and -4.2% respectively. Determine the elevation of a point 422ft from PVC. Round your answer to 3 decimal places.
A vertical parabolic curve has its PVI at station 18 + 50 and elevation 97.52. The grade of the back tangent is 2.5 percent, and the grade of the forward tangent is – 4.5 percent, and the curve length is 400 ft. Sta V = 29 + 00 Using the CHORD GRADIENTS, what is the elevation at 28 +50?
Find reduced levels of the various points on a parabolic vertical curve, which is to be set to connect two uniform grades 0.6% and - 0.7%. The chainage and required level of the point of intersection are 2525 m and 335.65 m respectively. A ssume the rate of change of grade to be 0.05 per 20 m chain.
An equal tangent sag curve is designed with a PVC at station 3+320 and elevation 290m, the PVI at station 3+375 and elevation 288.74m, and the low point is at station 3+365.determine the design speed of the curve.