A vertical symmetrical sag curve has a descending grade of - 4.2% and an ascending grade of +3% intersecting at station 10 +020, whose elevation is 100 m. The two grade lines are connected by a 260 m vertical parabolic sag curve. (a) At what distance from the P.C. is the lowest point of the curve located in m? (b) What is the vertical offset of the parabolic curve to the point of intersection of the tangent grades in m. (c) If a 1 m. diameter culvert is placed at the lowest point of the curve with the top of the culvert buried 0.60 m. below the subgrade, what will be the elevation of the invert of the culvert?
A vertical symmetrical sag curve has a descending grade of - 4.2% and an ascending grade of +3% intersecting at station 10 +020, whose elevation is 100 m. The two grade lines are connected by a 260 m vertical parabolic sag curve. (a) At what distance from the P.C. is the lowest point of the curve located in m? (b) What is the vertical offset of the parabolic curve to the point of intersection of the tangent grades in m. (c) If a 1 m. diameter culvert is placed at the lowest point of the curve with the top of the culvert buried 0.60 m. below the subgrade, what will be the elevation of the invert of the culvert?
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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