Organic Chemistry
12th Edition
ISBN: 9781118875766
Author: T. W. Graham Solomons, Craig B. Fryhle, Scott A. Snyder
Publisher: WILEY
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 22, Problem 12PP
Interpretation Introduction
Interpretation:
The description of the reaction between fructose and phenylhydrazine using the Fischer projection formula is to be represented; and the description of the information regarding stereochemistry, which can be obtained on the basis of this reaction is to be represented.
Concept Introduction:
▸ Stereochemistry: A carbon atom that has four different groups attached to it is called as a stereogenic or chirality center of that atom. A stereocenter is that point in a molecule, where any two groups exchange their places to form stereoisomers. Furthermore, the pair of diastereomers that show different configuration at the chirality center are called epimers.
▸ Fischer projection is a way of representing the
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
can you please add an explanation.
Regarding 4-O- (α-D-psychofuranosyl) -β-D-allopyranose. Please indicate the RIGHT alternative:
(a) The disaccharide reacts with CH3OH in an acid medium to form a glycoside that cannot be oxidized with HNO3.
(b) It is a reducing disaccharide only in basic medium.
(c) In the structure there is only one glycosidic bond that is of the type β 1-O-4 '
(d) The hydrolysis products of this disaccharide do not show mutarrotation. (e) The disaccharide structure contains two six-membered rings.
Which of the following are reducing sugars? Comment on the common name sucrosefor table sugar.(a) methyl a-d-galactopyranoside (b) b-l-idopyranose (an aldohexose)(c) a-d-allopyranose (d) ethyl b-d-ribofuranoside
Chapter 22 Solutions
Organic Chemistry
Ch. 22 - Prob. 1PPCh. 22 - Prob. 2PPCh. 22 - Prob. 3PPCh. 22 - Prob. 4PPCh. 22 - Prob. 5PPCh. 22 - Prob. 6PPCh. 22 - Prob. 7PPCh. 22 - Prob. 8PPCh. 22 - Practice Problem 22.9 What products would you...Ch. 22 - Prob. 10PP
Ch. 22 - Prob. 11PPCh. 22 - Prob. 12PPCh. 22 - Prob. 13PPCh. 22 - Prob. 14PPCh. 22 - Prob. 15PPCh. 22 - Prob. 16PPCh. 22 - Prob. 17PPCh. 22 - Prob. 18PPCh. 22 - Prob. 19PPCh. 22 - Prob. 20PCh. 22 - Prob. 21PCh. 22 - Prob. 22PCh. 22 - Prob. 23PCh. 22 - Prob. 24PCh. 22 - Prob. 25PCh. 22 - Prob. 26PCh. 22 - Prob. 27PCh. 22 - Prob. 28PCh. 22 - Prob. 29PCh. 22 - Prob. 30PCh. 22 - Prob. 31PCh. 22 - Prob. 32PCh. 22 - Prob. 33PCh. 22 - Prob. 34PCh. 22 - Prob. 35PCh. 22 - Prob. 36PCh. 22 - Prob. 37PCh. 22 - Prob. 38PCh. 22 - Arbutin, a compound that can be isolated from the...Ch. 22 - Prob. 40PCh. 22 - Prob. 41PCh. 22 - Prob. 42PCh. 22 - Prob. 43PCh. 22 - 22.44 The following reaction sequence represents...Ch. 22 - 22.45
The NMR data for the two anomers...Ch. 22 - Shikimic acid is a key biosynthetic intermediate...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- (i) Acetylation of glucose with acetic anhydride gives glucose pentacetate. Write the structure of the pentacetate. (ii) Explain – Why glucose pentacetate does not react with hydroxylamine?arrow_forwardIdentify monomeric and multimeric (di-,tri-meric, for example) saccharides from this group. If you come across multimeric polypeptides, state the mono- mers that form these multimers. State the nature of the bond that links two units together in each case. (a) Maltose (b) Trehalose (c) Lactose (d) Sucrose (e) Cellobiose (f) Agarosearrow_forwardCompound A is a D-aldopentose that can be oxidized to an optically inactive aldaric acid B. On Kiliani-Fischer chain extension, A is converted into C and D; C can be oxidized to an optically active aldaric acid E, but D is oxidized to an optically inactive aldaric acid F. What is the structure of compound F? • Use the wedge/hash bond tools to indicate stereochemistry where it exists. You do not have to explicitly draw H atoms. If a group is achiral, do not use wedged or hashed bonds on it. • Show stereochemistry in a meso compound. • Do not include lone pairs in your answer. They will not be considered in the grading.arrow_forward
- d-Xylose and d-lyxose are formed when d-threose undergoes a Kiliani–Fischer synthesis. d-Xylose is oxidized to an optically inactive aldaric acid,whereas d-lyxose forms an optically active aldaric acid. What are the structures of d-xylose and d-lyxose?arrow_forwardConsider the structure of raffinose, a trisaccharide found in sugar beets and a number of higher plants. HO CH,OH Но- OH OCH, Но Но OH НОСН Но CH,OH ÓH raffinose (a) Classify raffinose as a reducing or nonreducing sugar, and tell how you know. (b) Identify the glycoside linkages in raffinose, and clas- sify each as either a or B. (c) Name the monosaccharides formed when raffinose is hydrolyzed in aqueous acid. (d) What products are formed when raffinose is treated with dimethyl sulfate in NaOH, and then with aqueous acid and heat?arrow_forwardDraw the Fischer projection formulas for the following isomers of D-fructose: (a) an epimer (b) an enantiomer (c) a diastereomerarrow_forward
- The carbonyl group in d-galactose may be isomerized from C1 to C2 by brief treatmentwith dilute base (by the enediol rearrangement, Section 23-7). The product is the C4epimer of fructose. Draw the furanose structure of the product.arrow_forwardCarbohydrates a. Compound Z is an aldopentose. If Z is oxidized with nitric acid the product is optically active. If Z undergoes one Ruff degradation and the product of that degradation is reduced to the alditol using H₂/Ni the resulting product is optically inactive. If compound Z undergoes two Ruff degradations, D-glyceraldehyde (shown below) is obtained. Draw the usual Fischer projection of Z (aldehyde at the top). (Hint: work backwards from D- glyceraldehyde.) H HIC OH CH₂OH D-Glyceraldehydearrow_forward(i) Acetylation of glucose with acetic anhydride gives glucosepentaacetate. Write the structure of the pentaacetate.(ii) Explain why glucose pentaacetate does not react with hydroxylamine?arrow_forward
- Why can isomaltose be easily hydrolyzed through acid hydrolysis while trehalose cannot undergo acid hydrolysis?arrow_forwardDraw the two possible Haworth structures (both alpha and beta anomers) for the following monosaccharides and give their corresponding systematic names. [Show the stepwise process] (a) D-Ribose (b) D-Galactose (c) D- Fructosearrow_forward3a. 3b. 3c 3d. 3e. CO₂ clavulanic acid CH₂-OH H Answer the following questions about clavulanic acid. Does clavulanic acid inhibit D-alanyl-D-alanine transpeptidase? Does clavulanic acid contain a ß-lactam? Does clavulanic acid contain a thiazolium ring? What is the result of the treatment of penicillinase with clavulanic acid? Does clavulanic acid form a covalent acyl-enzyme intermediate with penicillinase?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Chemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning
EBK A SMALL SCALE APPROACH TO ORGANIC LChemistryISBN:9781305446021Author:LampmanPublisher:CENGAGE LEARNING - CONSIGNMENT
Chemistry for Today: General, Organic, and Bioche...
Chemistry
ISBN:9781305960060
Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen
Publisher:Cengage Learning
EBK A SMALL SCALE APPROACH TO ORGANIC L
Chemistry
ISBN:9781305446021
Author:Lampman
Publisher:CENGAGE LEARNING - CONSIGNMENT