Organic Chemistry
12th Edition
ISBN: 9781118875766
Author: T. W. Graham Solomons, Craig B. Fryhle, Scott A. Snyder
Publisher: WILEY
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Chapter 20, Problem 45P
Compound W
Figure 20.6 The
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Indicate two basic differences that exist between the spectra of 1H y 13C in NMR.
A compound A of mass 114 has the following elemental analysis: C = 63.14%, H=8.83%.
The IR, 1H NMR and 13C NMR spectra are given below.
1) Assign and interpret all the data from the 1H NMR and 13C NMR spectra. Propose a formula
for A.
7.0
175
с
3000
1,3; 13
I=1
6.0
150
I=1
с
5.0
CH₂
125
2000
Explain why the answer is this one :
CH,—CH,—0
4,2; 60
mavermy
I=2
cm-1
4.0
100
1500
3.0
75
135
167 |
CH₂
6
125
CH 3
1,95 ; 18
I=3
1000
2.0
50
H
5,5
I=3
1.0
CH₂
CH₂
25
500
Ppm
ppm
08) The NMR spectra of the two isomeric compounds with formula C3H5ClO2 are shown in letters a and b. Low-field protons appearing in the NMR spectrum around 12.1 and 11.5 ppm, respectively, are shown highlighted. Draw the structures of the isomers.
Chapter 20 Solutions
Organic Chemistry
Ch. 20 - Prob. 1PPCh. 20 - Prob. 2PPCh. 20 - Practice Problem 20.3
Write a mechanism that...Ch. 20 - Prob. 4PPCh. 20 - PRACTICE PROBLEM 20.5 Outline a preparation of...Ch. 20 - Prob. 6PPCh. 20 - Prob. 7PPCh. 20 - Prob. 8PPCh. 20 - Prob. 9PPCh. 20 - Prob. 10PP
Ch. 20 - Practice Problem 20.11 In the preceding examples...Ch. 20 - Prob. 12PPCh. 20 - Prob. 13PPCh. 20 - Practice Problem 20.14
Outline a synthesis of...Ch. 20 - Prob. 15PPCh. 20 - Prob. 16PPCh. 20 - Prob. 17PPCh. 20 - Prob. 18PPCh. 20 - Prob. 19PCh. 20 - 20.20 Give common or systematic names for each of...Ch. 20 - Which is the most basic nitrogen in each compound?...Ch. 20 - Prob. 22PCh. 20 - Prob. 23PCh. 20 - Show how you might synthesize each of the...Ch. 20 - Prob. 25PCh. 20 - 20.26 Provide the major organic product from each...Ch. 20 - Prob. 27PCh. 20 - 20.28 What products would you expect to be formed...Ch. 20 - Prob. 29PCh. 20 - Prob. 30PCh. 20 - Prob. 31PCh. 20 - Write equations for simple chemical rests or state...Ch. 20 - Prob. 33PCh. 20 - Explain the following, including mention of key...Ch. 20 - 20.35 Provide a detailed mechanism for each of the...Ch. 20 - Prob. 36PCh. 20 - Prob. 37PCh. 20 - Prob. 38PCh. 20 - Prob. 39PCh. 20 - 20.40 Give structures for compounds R-W:
Ch. 20 - Prob. 41PCh. 20 - Prob. 42PCh. 20 - Diethylpropion (shown here) is a compound used in...Ch. 20 - Prob. 44PCh. 20 - 20.45 Compound W is soluble in dilute aqueous HCI...Ch. 20 - 20.46 Propose structures for compounds X, Y, and...Ch. 20 - Compound A(C10H15N) is soluble in dilute HCI. The...Ch. 20 - Prob. 48PCh. 20 - Prob. 49PCh. 20 - For each of the following, identify the product...Ch. 20 - 20.51 Develop a synthesis for the following...Ch. 20 - 20.52 When phenyl isochiocyanatc, , is reduced...Ch. 20 - Prob. 53PCh. 20 - 20.54 Propose a mechanism that can explain the...Ch. 20 - When acetone is treated with anhydrous ammonia in...Ch. 20 - Prob. 56P
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- The H1H1 NMR spectrum shown corresponds to an unknown compound with the molecular formula C6H10C6H10. There are no strong IR bands between 2100 and 2300 or 3250 and 3350 cm−1. Deduce and draw the structure of the molecule that corresponds to the spectrum.arrow_forwardA hydrocarbon, compound B, has molecular formula C6H6, and gave an NMR spectrum with two signals: delta 6.55 pm and delta 3.84 pm with peak ratio of 2:1. When warmed in pyridine for three hr, compound B quantitatively converts to benzene. Mild hydrogenation of B yielded another compound C with mass spectrum of m/z 82. Infrared spectrum showed no double bonds; NMR spectrum showed one broad peak at delta 2.34 ppm. With this information, address the following questions. a) How many rings are in compound C? b) How many rings are probably in B? How many double bonds are in B? c) Can you suggest a structure for compounds B and C? d) In the NMR spectrum of B, the up-field signal was a quintet, and the down field signal was a triplet. How must you account for these splitting patterns?arrow_forwardThe NMR spectra for compound 1 were acquired in a 7.5 mg / 0.6 mL solution ofCDCl3 . The 1H and 13C peaks are also listedbelow. Provide a full analysis of the NMR spectra for compound 1. correct assignment of NMR spectra of both 13C spectra. correct rationalisation of 13C spectrum1H NMR (400 MHz, CDCl3) δ 7.73 (d, J = 9.5 Hz, 1H), 7.56 (ddd, J = 8.5, 7.5, 1.6 Hz, 1H),7.51 (dd, J = 7.5, 1.6 Hz, 1H), 7.36 (d, J = 8.5 Hz, 1H), 7.30 (dd, J = 8.5, 7.5 Hz, 1H), 6.45(d, J = 9.5 Hz, 1H).13C NMR (101 MHz, CDCl3) δ 160.79, 154.09, 143.43, 131.85, 127.87, 124.44, 118.86,116.94, 116.74.Note: There are two carbon peaks in the 13C spectrum that are so close together that they are not differentiable at the resolution in this experiment. you should be able to assign these peaks to one of two carbon atoms in 1.arrow_forward
- a compound C9H10O2 has the IR, 13C NMR, and 1H NMR spectra below.What is the structure? Explain answer based on spectral assignments. Assign at least 2 bands on the IR and all protons in the H NMR spectrumarrow_forwardName the following compounds A and B. How could you distinguish these two molecules by using 1H NMR and IR techniques? Propose an analytical technique to determine the iron content of these compounds. Calculate the mass percentages of C and H of compound B (C: 12.01 g/mol; H: 1.008 g/mol; Fe: 55.845 g/mol).arrow_forwardThe proton NMR spectrum for a compound with formula C10H12O2is shown below.The infrared spectrum has a strong band al 1711 cm-1. The normal carbon-13 NMRspectral results are tabulated along with the DEPT-135 and DEPT-90 information. Drawthe structure of this compound.arrow_forward
- Identify the compound with molecular formula C8H10O that gives the IR and 1H NMR spectra shown here.arrow_forwardCompound X (molecular formula C10H120) was treated with NH2NH2, ¯OH to yield compound Y (molecular formula C10H14). Match the 1H NMR spectra of X and Y to the corresponding structures of X and Y. Compound NH2NH2 Compound 'H NMR of X 6 H OH Y 1 H 5H 8. 6. 4 ppm or H NMR of Y 6 H 2H 5H 1 H multiplet multiplet 8. 6. 4. 3. 1 nnm 2. 2. 3, O:arrow_forwardAnalysis of a sweet-smelling, neutral compound of carbon, hydrogen and oxygen produced the following results: %C = 54.5; %H = 9.1. From its mass spectrum, the molecular ion had a mass/charge ratio of 88. Its infra-red spectrum showed a prominent peak at 1735 cm–1. Figure below shows the NMR spectrum of the compound. Which of the following is this compound? A. 3-hydroxybutanalB. Methyl propionateC. Ethyl acetateD. 2-methylpropanoic acidE. Methoxyacetonearrow_forward
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