Physics: Principles with Applications
Physics: Principles with Applications
6th Edition
ISBN: 9780130606204
Author: Douglas C. Giancoli
Publisher: Prentice Hall
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Question
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Chapter 2, Problem 9P

(a)

To determine

The average speed of the person

(a)

Expert Solution
Check Mark

Answer to Problem 9P

The average speed of the person is 4.3 m/s .

Explanation of Solution

Given:

The number of complete laps

  n=8

Distance of one lap, l=0.25 mi

Total time taken, t=12.5 min

Formula used:

The average speed of the person is given by,

  v¯=dt    ……(1)

Here, d is the total distance travelled in the time t , which is given by,

  d=n×l    ……(2)

Calculation:

Convert the distance of one lap into meters.

  l=(0.25 mi)(1610 m1 mi)=402.5 m

The total distance travelled using equation (2) is,

  d=n×l=8(402.5 m)=3220 m

Express the time taken in seconds.

  t=(12.5 min)(60 s1 min)=750 s

Substitute the calculated values of d and t in equation (1) and determine the value of the average speed.

  v¯=dt=3220 m750 s=4.3 m/s

Conclusion:

Thus, the average speed of the person is 4.3 m/s .

(b)

To determine

The average velocity of the person.

(b)

Expert Solution
Check Mark

Answer to Problem 9P

The average velocity of the person is 0 m/s .

Explanation of Solution

Given:

The number of complete laps

  n=8

Distance of one lap, l=0.25 mi

Total time taken, t=12.5 min

Formula used:

The average velocity of the person is given by,

  v=ΔxΔt    ……(3)

Calculation:

Displacement is the shortest distance between the starting and the ending point of the body’s motion. When the jogger completes a lap, he returns to exactly the same position he was when he had started. Therefore, at the end of 8 laps, the final and the initial positions of the jogger are the same.

Since displacement is defined as the difference between the body’s initial and final positions, the jogger’s displacement at the end of 8 laps is zero.

Hence, the jogger’s velocity at the end of 8 laps is also zero.

Conclusion:

Thus, the average velocity of the person is 0 m/s .

Chapter 2 Solutions

Physics: Principles with Applications

Ch. 2 - Can an object be increasing in speed as its...Ch. 2 - A baseball player hits a ball straight up into the...Ch. 2 - As a freely falling object speeds up, what is...Ch. 2 - Prob. 14QCh. 2 - You travel from point A to point B in a car moving...Ch. 2 - Prob. 16QCh. 2 - Prob. 17QCh. 2 - Prob. 18QCh. 2 - Prob. 19QCh. 2 - Prob. 20QCh. 2 - Describe in words the motion plotted in Fig. 2-32...Ch. 2 - Describe in words the motion of the object graphed...Ch. 2 - Prob. 1PCh. 2 - Prob. 2PCh. 2 - Prob. 3PCh. 2 - Prob. 4PCh. 2 - Prob. 5PCh. 2 - Prob. 6PCh. 2 - Prob. 7PCh. 2 - Prob. 8PCh. 2 - Prob. 9PCh. 2 - Prob. 10PCh. 2 - Prob. 11PCh. 2 - Prob. 12PCh. 2 - Prob. 13PCh. 2 - Prob. 14PCh. 2 - Prob. 15PCh. 2 - A sports car accelerates from rest to 95 km/h in...Ch. 2 - Prob. 17PCh. 2 - Prob. 18PCh. 2 - 19.(II) A sports car moving at constant velocity...Ch. 2 - Prob. 20PCh. 2 - Prob. 21PCh. 2 - Prob. 22PCh. 2 - Prob. 23PCh. 2 - Prob. 24PCh. 2 - Prob. 25PCh. 2 - Prob. 26PCh. 2 - Prob. 27PCh. 2 - Prob. 28PCh. 2 - Prob. 29PCh. 2 - Prob. 30PCh. 2 - Prob. 31PCh. 2 - Prob. 32PCh. 2 - Prob. 33PCh. 2 - Prob. 34PCh. 2 - Prob. 35PCh. 2 - Prob. 36PCh. 2 - Prob. 37PCh. 2 - Prob. 38PCh. 2 - Prob. 39PCh. 2 - Prob. 40PCh. 2 - Prob. 41PCh. 2 - Prob. 42PCh. 2 - Prob. 43PCh. 2 - Prob. 44PCh. 2 - Prob. 45PCh. 2 - Prob. 46PCh. 2 - Prob. 47PCh. 2 - Prob. 48PCh. 2 - Prob. 49PCh. 2 - Prob. 50PCh. 2 - Prob. 51PCh. 2 - Prob. 52PCh. 2 - Prob. 53PCh. 2 - Prob. 54PCh. 2 - Prob. 55PCh. 2 - Prob. 56PCh. 2 - Prob. 57GPCh. 2 - Prob. 58GPCh. 2 - Prob. 59GPCh. 2 - Prob. 60GPCh. 2 - Prob. 61GPCh. 2 - Prob. 62GPCh. 2 - Prob. 63GPCh. 2 - Prob. 64GPCh. 2 - Prob. 65GPCh. 2 - Prob. 66GPCh. 2 - Prob. 67GPCh. 2 - Prob. 68GPCh. 2 - Prob. 69GPCh. 2 - Prob. 70GPCh. 2 - Prob. 71GPCh. 2 - Prob. 72GPCh. 2 - Prob. 73GPCh. 2 - Prob. 74GPCh. 2 - Prob. 75GPCh. 2 - Prob. 76GPCh. 2 - Prob. 77GPCh. 2 - Prob. 78GPCh. 2 - Prob. 79GPCh. 2 - Prob. 80GPCh. 2 - Prob. 81GPCh. 2 - Prob. 82GPCh. 2 - Prob. 83GPCh. 2 - Prob. 84GPCh. 2 - Prob. 85GP
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Position/Velocity/Acceleration Part 1: Definitions; Author: Professor Dave explains;https://www.youtube.com/watch?v=4dCrkp8qgLU;License: Standard YouTube License, CC-BY