Physics: Principles with Applications
Physics: Principles with Applications
6th Edition
ISBN: 9780130606204
Author: Douglas C. Giancoli
Publisher: Prentice Hall
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Question
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Chapter 2, Problem 36P

(a)

To determine

The height gained by the baseball

(a)

Expert Solution
Check Mark

Answer to Problem 36P

24.7 m.

Explanation of Solution

Given:

Initial velocity of the baseball =vi=22ms

Final velocity of the baseball at the highest point =vf=0ms

Acceleration experienced by baseball = acceleration due to gravity =a=9.8ms2

Height gained by the ball =h

Displacement of the ball =Δy=h

Formula Used:

Displacement of an object in uniform accelerated motion is given as

  Δy=vf2vi22aWhere vf and vi are final and initial velocity of the object and a is the acceleration

Calculation:

Consider the motion of the baseball in vertical direction.

Displacement of the baseball is given as

  Δy=vf2vi22a

Substituting the values

  Δy=022222(9.8)=24.69mΔy24.7m

Conclusion:

Therefore, height gained is 24.7 m.

(b)

To determine

The time spent by the baseball in air

(b)

Expert Solution
Check Mark

Answer to Problem 36P

4.5 seconds.

Explanation of Solution

Given:

Initial velocity of the baseball =vi=22ms

Acceleration experienced by baseball = acceleration due to gravity =a=9.8ms2

Time of travel =t

Displacement of the ball as it comes back to its starting location =Δy=0m

Formula Used:

Displacement of an object in uniform accelerated motion is given as

  Δy=vit+(0.5)at2where vi= initial velocityΔy=displacementt=timea=acceleration

Calculation:

Consider the motion of the baseball in vertical direction.

Substituting the values, to find the time.

  0=22t+(0.5)(9.8)t2t=4.5s

Conclusion:

Therefore, time spent by baseball in air is 4.5 seconds.

Chapter 2 Solutions

Physics: Principles with Applications

Ch. 2 - Can an object be increasing in speed as its...Ch. 2 - A baseball player hits a ball straight up into the...Ch. 2 - As a freely falling object speeds up, what is...Ch. 2 - Prob. 14QCh. 2 - You travel from point A to point B in a car moving...Ch. 2 - Prob. 16QCh. 2 - Prob. 17QCh. 2 - Prob. 18QCh. 2 - Prob. 19QCh. 2 - Prob. 20QCh. 2 - Describe in words the motion plotted in Fig. 2-32...Ch. 2 - Describe in words the motion of the object graphed...Ch. 2 - Prob. 1PCh. 2 - Prob. 2PCh. 2 - Prob. 3PCh. 2 - Prob. 4PCh. 2 - Prob. 5PCh. 2 - Prob. 6PCh. 2 - Prob. 7PCh. 2 - Prob. 8PCh. 2 - Prob. 9PCh. 2 - Prob. 10PCh. 2 - Prob. 11PCh. 2 - Prob. 12PCh. 2 - Prob. 13PCh. 2 - Prob. 14PCh. 2 - Prob. 15PCh. 2 - A sports car accelerates from rest to 95 km/h in...Ch. 2 - Prob. 17PCh. 2 - Prob. 18PCh. 2 - 19.(II) A sports car moving at constant velocity...Ch. 2 - Prob. 20PCh. 2 - Prob. 21PCh. 2 - Prob. 22PCh. 2 - Prob. 23PCh. 2 - Prob. 24PCh. 2 - Prob. 25PCh. 2 - Prob. 26PCh. 2 - Prob. 27PCh. 2 - Prob. 28PCh. 2 - Prob. 29PCh. 2 - Prob. 30PCh. 2 - Prob. 31PCh. 2 - Prob. 32PCh. 2 - Prob. 33PCh. 2 - Prob. 34PCh. 2 - Prob. 35PCh. 2 - Prob. 36PCh. 2 - Prob. 37PCh. 2 - Prob. 38PCh. 2 - Prob. 39PCh. 2 - Prob. 40PCh. 2 - Prob. 41PCh. 2 - Prob. 42PCh. 2 - Prob. 43PCh. 2 - Prob. 44PCh. 2 - Prob. 45PCh. 2 - Prob. 46PCh. 2 - Prob. 47PCh. 2 - Prob. 48PCh. 2 - Prob. 49PCh. 2 - Prob. 50PCh. 2 - Prob. 51PCh. 2 - Prob. 52PCh. 2 - Prob. 53PCh. 2 - Prob. 54PCh. 2 - Prob. 55PCh. 2 - Prob. 56PCh. 2 - Prob. 57GPCh. 2 - Prob. 58GPCh. 2 - Prob. 59GPCh. 2 - Prob. 60GPCh. 2 - Prob. 61GPCh. 2 - Prob. 62GPCh. 2 - Prob. 63GPCh. 2 - Prob. 64GPCh. 2 - Prob. 65GPCh. 2 - Prob. 66GPCh. 2 - Prob. 67GPCh. 2 - Prob. 68GPCh. 2 - Prob. 69GPCh. 2 - Prob. 70GPCh. 2 - Prob. 71GPCh. 2 - Prob. 72GPCh. 2 - Prob. 73GPCh. 2 - Prob. 74GPCh. 2 - Prob. 75GPCh. 2 - Prob. 76GPCh. 2 - Prob. 77GPCh. 2 - Prob. 78GPCh. 2 - Prob. 79GPCh. 2 - Prob. 80GPCh. 2 - Prob. 81GPCh. 2 - Prob. 82GPCh. 2 - Prob. 83GPCh. 2 - Prob. 84GPCh. 2 - Prob. 85GP
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Position/Velocity/Acceleration Part 1: Definitions; Author: Professor Dave explains;https://www.youtube.com/watch?v=4dCrkp8qgLU;License: Standard YouTube License, CC-BY