Chapter 2, Problem 21P

To determine

Acceleration of car and distance travelled by car.

Answer to Problem 21P

Acceleration of car is $2{\text{ m/s}}^2$

Distance travelled by car is $\text{114 m}$

Explanation of Solution

Given data:

Initial velocity: $\text{13 m/s}$

Final velocity: $25\text{ m/s}$

Time taken:6.0s

Formula used:

Equation of motion is

  $\begin{array}{l}v=u+at\\ s=ut+\frac{1}{2}a{t}^2\end{array}$

Calculation:

Acceleration of car

  $\begin{array}{l}v=u+at\\ 25=13+6a\\ a=2{\text{ m/s}}^2\end{array}$

The distance is,

  $\begin{array}{l}s=ut+\frac{1}{2}a{t}^2\\ s=13\times 6+\frac{1}{2}\times 2\times 6^2\\ s=114\text{ m}\end{array}$

Conclusion:

Acceleration of car is $2{\text{ m/s}}^2$

Distance travelled by car is $114\text{ m}$