Genetic Analysis: An Integrated Approach (3rd Edition)
3rd Edition
ISBN: 9780134605173
Author: Mark F. Sanders, John L. Bowman
Publisher: PEARSON
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Chapter 17, Problem 22P
Cytoplasmic male sterility (CMS) in plants has been exploited to produce hybrid seeds (see Experimental Insight
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What genotypes and
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Multiple crosses were made between true-breeding lines of black and yellow Labrador retrievers. All the F1 progeny were yellow. When these progeny were intercrossed, they produced an F2 consisting of 121 yellow, 9 black and 30 chocolate.
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Propose a biochemical pathway for coat color in Labrador retrievers based on the type of epistasis.
Correlate each genotype with the phenotype that would occur in your pathway. Also show the frequency of each genotype.
A-B-
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In corn, male sterility is controlled by maternal cytoplasmic elements. This phenotype renders the male part of the corn plants (i.e the tassel) unable to produce fertile pollen; the female parts, however, remain receptive to pollination by pollen from male fertile corn plants. However, the presence of a nuclear fertility restorer gene F restores fertility to male sterile lines
Using the cardboard chips, simulate the crosses indicated below. Give the genotypes and phenotypes of the offsprings in each cross, and properly label the nucleus and the cytoplasm of each individual in the cross
Legend
male sterile cytoplasm
Male fertile cytoplasm
FF nucleus
Ff nucleus
ff nucleus
A. Male sterile female x FF male
Explain the phenotype of the offspring
B. Male sterile female x Ff male
Explain the phenotype of the offspring
n corn, male sterility is controlled by maternal cytoplasmic elements. This phenotype renders the male part of the corn plants (i.e the tassel) unable to produce fertile pollen; the female parts, however, remain receptive to pollination by pollen from male fertile corn plants. However,
the presence of a nuclear fertility restorer gene F restores fertility to male sterile lines
Using the cardboard chips, simulate the crosses indicated below. Give the genotypes and phenotypes of the offsprings in each cross, and properly label the nucleus and the cytoplasm each individual in the cross
Legend
male sterile cytoplasm
Male fertile cytoplasm
FF nucleus
Ff nucleus
ff nucleus
A. Male sterile female x FF male
Explain the phenotype of the offspring
B. Male sterile female x Ff male
Explain the phenotype of the offspring
Chapter 17 Solutions
Genetic Analysis: An Integrated Approach (3rd Edition)
Ch. 17 - 17.1 Reciprocal crosses of experimental animals or...Ch. 17 - 17.2 How are some of the characteristics of the...Ch. 17 - 17.3 The human mitochondrial genome encodes...Ch. 17 - What is the evidence that transfer of DNA from the...Ch. 17 - Draw a graph depicting the relative amounts of...Ch. 17 - Prob. 6PCh. 17 - 17.7 What is the evidence that the ancient...Ch. 17 - 17.8 Outline the steps required for a gene...Ch. 17 - 17.9 Consider the phylogenetic tree presented in...Ch. 17 - You are a genetic counselor, and several members...
Ch. 17 - A mutation in Arabidopsis immutans results in the...Ch. 17 - What type or types of inheritance are consistent...Ch. 17 - You have isolated (1) a streptomycin-resistant...Ch. 17 - You have isolated two petite mutants, pet1 and...Ch. 17 - 17.15 Consider this human pedigree for a vision...Ch. 17 - A 50- year - old man has been diagnosed with MELAS...Ch. 17 - 17.17 The first person in a family to exhibit...Ch. 17 - Prob. 18PCh. 17 - 17.19 What is the most likely mode of inheritance...Ch. 17 - 17.20 In , the Russian Tsar Nicholaswas deposed,...Ch. 17 - 17.21 The dodo bird (Raphus cucullatus) lived on...Ch. 17 - Cytoplasmic male sterility (CMS) in plants has...Ch. 17 - 17.23 Wolves and coyotes can interbreed in...Ch. 17 - Prob. 24PCh. 17 - Prob. 25PCh. 17 - Most large protein complexes in mitochondria and...Ch. 17 - As described in this chapter, mothers will pass on...
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- Explain at the biochemical or enzymatic level, the phenotypic consequencesof alleles incase of following cross. Rr (pink flower) x Rr (pink flower) (progeny are 1 RR (red flower) :2 Rr (pink flower): 1rr(white flower) how alleles contribute to a phenotype through metabolism.arrow_forwardIn rice, male sterility is controlled by maternal cytoplasmic elements. This phenotype renders the male part of rice plants (i.e. the stamen) unable to produce fertile pollen; the female parts, however, remain receptive to pollination by pollen from male fertile rice plants. However, the presence of a nuclear fertility restorer gene F restores fertility to male-sterile lines. Give the result(s) of the cross and explain the phenotype of the offspring.arrow_forwardSome sweet-pea plants have purple flowers and others have white flowers. A homozygous variety of sweet pea that has purple flowers is crossed with a homozygous variety that has white flowers. All the F1 have purple flowers. When these F1 self-fertilize, the F2 appear in a ratio of 916 purple to 716 white. a. Give genotypes for the purple and white flowers in these crosses. b. Draw a hypothetical biochemical pathway to explain the production of purple and white flowers in sweet peasarrow_forward
- In corn, male sterility is controlled by maternal cytoplasmic elements. This phenotype renders the male part of corn plants (i.e. the tassel) unable to produce fertile pollen; the female parts, however, remain receptive to pollination by pollen from male-fertile corn plants. However, the presence of a nuclear fertility restorer gene F restores fertility to male-sterile lines. Using the following color-coded circles, simulate the crosses indicated below. Put the illustrations of crosses in the spaces provided. Be sure to include in the labels the genotypes and phenotypes of the offspring in each cross. Big light green circle - male-sterile cytoplasm Big orange circle - male-fertile cytoplasm Small orange circle - FF nucleus Small half-light green-half-orange circle - Ff nucleus Small light-green circle - ff nucleusarrow_forwardn corn, male sterility is controlled by maternal cytoplasmic elements. This phenotype renders the male part of the corn plants (i.e the tassel) unable to produce fertile pollen; the female parts, however, remain receptive to pollination by pollen from male fertile corn plants. However, the presence of a nuclear fertility restorer gene F restores fertility to male sterile lines sing the cardboard chips, simulate the crosses indicated below. Give the genotypes and phenotypes of the offsprings in each cross, and properly label the nucleus and the cytoplasm of each individual in the cross Legend male sterile cytoplasm Male fertile cytoplasm FF nucleus Ff nucleus ff nucleus A. Male sterile female x FF male Explain the phenotype of the offspring B. Male sterile female x Ff male Explain the phenotype of the offspringarrow_forwardIn fruit flies, you are mapping three genes in a three point cross. The mutants are hairy body (h), sepia colored eyes (se) and female sterility (g). You cross a heterozygous parent with a homozygous recessive parent and obtain the following results: Type Number h se g. 5 + se + 450 + se g 27 ++g_ h se + + + + h + g. h + + TOTAL is the gene in the middle and the distance in map units between se and g is Oh; 16.4 se; 7.1 Oh; 7.1 70 82 7 327 32 1000 se; 16.4arrow_forward
- The genotypes below that give viable animals for an mdm2+/- p53+/- cross are the following (p53 on chr 17 and mdm2 on chr 12) are:arrow_forwardA complex biochemical pathway is shown below, along with the alleles that either promote or inhibit each step of the pathway leading to a phenotype. Gene A has alleles A and a, B has alleles B and b, and so forth. Genes B and C are duplicate dominant epistatic lethal as heterozygotes (i.e. Bb Cc are lethal). Genes D and E are duplicate dominant epistatic (i.e. dd eg = desired phenotype). If I were to cross AA Bb cc Dd Ee with aa BB Cc Dd e, (i) (ii) What proportion of all offspring don't show the phenotype? What proportion of offspring survive? Gene A Gene B B Gene D a Gene C Gene Earrow_forwardConsider the first category of test-cross offspring shown in figure 8.2 (+b, LS). Consider also that the parents of the heterozygous female flies in the test cross had the following genotypes: bb, SS, and +, LL. A. What would be the physical phenotype of these flies? B. If PC was conducted with the DNA of one of these flies using the primers for the molecular marker, what would be the appearance of the bands on an electrophoresis gel with the PC products? C. If the gene for black body and the locus for the molecular marker (L long or S short) were unlinked, what proportion of the test-cross progeny would be black flies that are heterozygous for the molecular marker? What proportion would be flies with normal body color, which are homozygous for one form of the molecular marker? D. If the gene for black body and the locus for the molecular marker were linked, how would the proportion of flies be different?arrow_forward
- Chlamydomonas, a eukaryotic green alga, may be sensitive to the antibiotic erythromycin, which inhibits protein synthesis in bacteria. There are two mating types in this alga, mt+ and mt-. If an mt+ cell sensitive to the antibiotic is crossed with an mt- cell that is resistant, all progeny cells are sensitive. The reciprocal cross (mt+ resistant and mt- sensitive) yields all resistant progeny cells. Assuming that the mutation for resistance is in the chloroplast DNA, what can you conclude from the results of these crosses?arrow_forwardIn sweet peas, the given enzymatic pathway result to pigment formation in the flowers: A dihybrid plant is crossed to a white one which is heterozygous at the “C” locus (provided in the image). What is the genotype of the dihybrid plant? What is the genotype of the white plant? What kinds of flowers, colored or white, are to be expected from the cross above? Include the ratio.arrow_forwardDraw a preliminary linkage map of the three loci. What is their order? (E.g. is the forked locus between yellow and cross-veinless, or outside this region?) As this is a preliminary linkage map - do not account for double crossovers. You should base the distances on this map off your map distances calculated: yellow and forked: 39.3 mu yellow and cross-veinless: 11.9 mu cross-veinless and forked: 33.6 muarrow_forward
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