Essentials of Genetics (9th Edition) - Standalone book
Essentials of Genetics (9th Edition) - Standalone book
9th Edition
ISBN: 9780134047799
Author: William S. Klug, Michael R. Cummings, Charlotte A. Spencer, Michael A. Palladino
Publisher: PEARSON
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Chapter 12, Problem 22PDQ

In a mixed copolymer experiment, messages were created with either 4/5C:l/5A or 4/5A:l/5C. These messages yielded proteins with the amino acid compositions shown in the following table. Using these data, predict the most specific coding composition for each amino acid.

4/5C:1/5A 4/5A:1/5C
Proline 63.0% Proline 3.5%
Histidine 13.0% Histidine 3.0%
Threonine 16.0% Threonine 16.6%
Glutamine 3.0% Glutamine 13.0%
Asparagine 3.0% Asparagine 13.0%
Lysine 0.5% Lysine 50.0%
98.5% 99.1%
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In a mixed heteropolymer experiment, messages were createdwith either 4/5C:1/5A or 4/5A:1/5C. These messages yielded proteinswith the amino acid compositions shown in the followingtable. Using these data, predict the most specific coding compositionfor each amino acid.4/5C:1/5A                    4/5A:1/5CPro    63.0%                Pro       3.5%His    13.0%                His       3.0%Thr    16.0%                Thr      16.6%Glu    3.0%                  Glu      13.0%Asp   3.0%                  Asp      13.0%Lys    0.5%                  Lys        50.0%         98.5%                              99.1%
A purified recombinant protein is analyzed for molecular weight by SDS-PAGE at pH 8.5. From the protein sequence deduced from the gene that was expressed in bacteria, the protein is expected to have a molecular weight of 44,000. However, the molecular weight of the protein is found by SDS-PAGE to be 52,000. Explain the reason or reasons for this difference in molecular weight. What calculation could you make to help explain this discrepancy?
The authors state: "Properties of the single mutants K557R, D591V and K617A, a double mutant, D591V/K617A, and a triple mutant, K557R/D591V/K617A, were evaluated to find an allosteric binding site for citrate." The numbers between the letters represent the residue number altered. The letter in front was the wild type and the letter afterwards is the mutant. How would the the triple mutations K557R and D591V and K617A alter the overall protein? O lower the # of charges, increase the pl O increase the # of charges, increase the pl O lower the # of charges, lower the pl O lower the # of charges, increase the pl O no change in the # of charges, increase the pl O no change in the # of charges, lower the pl

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Biomolecules - Protein - Amino acids; Author: Tutorials Point (India) Ltd.;https://www.youtube.com/watch?v=ySNVPDHJ0ek;License: Standard YouTube License, CC-BY