Essentials of Genetics (9th Edition) - Standalone book
9th Edition
ISBN: 9780134047799
Author: William S. Klug, Michael R. Cummings, Charlotte A. Spencer, Michael A. Palladino
Publisher: PEARSON
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Textbook Question
Chapter 12, Problem 4PDQ
The mRNA formed from the repeating tetranucleotide UUAC incorporates only three amino acids, but the use of UAUC incorporates four amino acids. Why?
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For the following mRNA sequences, what is the amino acid sequence formed? Consult genetic code table for reference.
5' AGUCCGUAC 3'
5' AAUUGCUUC 3'
Using the genetic code table provided below, write out the sequence of three different possible
mRNA sequences that could encode the following sequence of amino acids:
Met-Phe-Cys-Trp-Glu
C
A
G
U
C
UUU Phe UCU Ser
UUC Phe UCC Ser
UCA Ser
UUA Leu
UUG Leu UCG Ser
CUU Leu CCU Pro
CUC Leu
CUA Leu
CUG Leu CCG
A
CAU His CGU Arg
CCC Pro CAC His CGC Arg
UAU Tyr UGU Cys U
UAC Tyr UGC Cys C
Stop UGA Stop
Stop UGG
Trp
UAA
A
UAG
G
CCA Pro CAA Gln
Pro CAG
AUU lle
AUC lle
AUA lle
AUG Met ACG
G
등등
Gln
CGA Arg
CGG Arg
ACU Thr AAU Asn AGU Ser
ACC
AAC Asn
AGC Ser
Thr
ACA Thr
Thr
AAA Lys AGA Arg
AAG
Lys
AGG Arg
GUU Val GCU
Ala
GAU Asp
GGU Gly
GGC Gly
GUC Val GCC
Ala
GAC
Asp
GUA Val
GCA
Ala
GAA
Glu GGA Gly
GUG Val
GCG Ala GAG
Glu GGG Gly
U
C
A
G
U
C
A
G
SUAU
Using the genetic code table provided below, identify the open reading frame in this mRNA
sequence, and write out the encoded 9 amino acid long peptide sequence:
5'- CGACAUGCCUAAAAUCAUGCCAUGGAGGGGGUAACCUUUU
C
A
G
U
UUU Phe UCU Ser
UUC Phe UCC Ser UAC
UCA Ser UAA
UCG Ser
UAG
UUA Leu
Leu
G
C
CUU Leu
CUC Leu CCC
CUA Leu
CUG Leu
AUU lle
AUC lle
AUA lle
AUG Met ACG
ACU
Thr
ACC
Thr
ACA Thr
Thr
A
UAU Tyr
UGU Cys
Tyr UGC Cys
CCU Pro CAU His CGU Arg
Pro CAC His
Pro CAA Gln
CGC Arg
CGA
Arg
CCA
CCG Pro
CAG Gln CGG
Arg
GUU Val GCU
Ala
GAU
GUC Val GCC
Ala
GAC
GUA Val GCA Ala
GAA
GUG Val GCG Ala GAG
Stop UGA
Stop UGG
AAU Asn
AAC
AAA
AAG
AGU
Asn AGC
G
Lys
Lys
Asp
Asp
Glu
Glu
Stop A
Trp
Ser
Ser
AGA Arg
AGG Arg
GGU Gly
GGC Gly
UCAG
GGA Gly
GGG Gly
с
U
C
A
G
U
C
A
G
U
C
A
G
Chapter 12 Solutions
Essentials of Genetics (9th Edition) - Standalone book
Ch. 12 - CASE STUDY | A drug that sometimes works A...Ch. 12 -
CASE STUDY | A drug that sometimes works
A...Ch. 12 -
CASE STUDY | A drug that sometimes works
A...Ch. 12 - HOW DO WE KNOW? In this chapter, we focused on the...Ch. 12 - Review the Chapter Concepts list on p. 215. These...Ch. 12 - In studies of frameshift mutations, Crick,...Ch. 12 -
4. The mRNA formed from the repeating...Ch. 12 - In studies using repeating copolymers, AC......Ch. 12 - Prob. 6PDQCh. 12 - Prob. 7PDQ
Ch. 12 -
8. When the amino acid sequences of insulin...Ch. 12 - Prob. 9PDQCh. 12 - Why doesn't polynucleotide phosphorylase (Ochoa's...Ch. 12 - Refer to Table 12.1. Can you hypothesize why a...Ch. 12 -
12. Predict the amino acid sequence produced...Ch. 12 - A short RNA molecule was isolated that...Ch. 12 - A glycine residue exists at position 210 of the...Ch. 12 - Shown here is a theoretical viral mRNA sequence...Ch. 12 -
16. Most proteins have more leucine than...Ch. 12 - Define the process of transcription. Where does...Ch. 12 - Describe the structure of RNA polymerase in...Ch. 12 - In a written paragraph, describe the abbreviated...Ch. 12 - Messenger RNA molecules are very difficult to...Ch. 12 - One form of posttranscriptional modification of...Ch. 12 - In a mixed copolymer experiment, messages were...Ch. 12 -
23. Shown in this problem are the amino acid...Ch. 12 - Alternative splicing is a common mechanism for...Ch. 12 - The genetic code is degenerate. Amino acids are...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- Consider the following DNA sequence, which codes for a short polypeptide: 5'-ATGGGCTTAGCGTAGGTTAGT-3' Determine the mRNA transcript of this sequence. You have to write these sequences from the 5' end to the 3' end and indicate those ends as shown in the original sequence in order to get the full mark. How many amino acids will make up this polypeptide? Determine the first four anticodons that will be used in order to translate this sequence.arrow_forwardConsider the following coding 71 nucleotide DNA template sequence (It does not contain a translational start): 5’- GTTTCCCCTATGCTTCATCACGAGGGCACTGACATGTGTAAACGAAATTCCAACCTGAGCGGCGT GTTGAG-3’ By in vitro translating the mRNA, you determined that the translated peptide is 15 amino acids long. What is the expected peptide sequence in single letter abbreviations?arrow_forwardGiven the following mRNA transcript: 5’-UUUGGCAUGGGUAUCGUAGAGAUGGAAUUCAUAGUGGAGUAA-3’ What is the one-letter abbreviation of the protein product of the mRNA transcript?arrow_forward
- What is the peptide encoded by this mRNA sequence 5’-UCU-GCA- AAU-UAA -GUU-3’?arrow_forwardIndicate the amino acid sequence of the protein encoded by the following mRNA molecule. Use the genetic code table and assume that the very first “AUG” the ribosome encounters will serve as the start codon and specify methionine. 5’-AAUUCAUGCCCAAAUUUGGGGCACGAAGCUUCUUAGGCUAGUCCUAAAAAA-3’arrow_forwardWhat is the peptide encoded by this mRNA sequence 5’-UCU-GCA- AAU-UUA -GUU-3’?arrow_forward
- A polypeptide has 51 amino acids in its primary structure. (i) What is the minimum number of DNA bases required to code for the amino acids in this polypeptide. Show your calculation. (ii) Does AUG appear in the first three nucleotides in the mRNA coding for this mRNA? Explain why.arrow_forwardTranslate the following mRNA nucleotide sequence into an amino acid sequence, starting at the first base: 5’ - UGUCAUGCUCGUCUUGAAUCUUGUGAUGCUCGUUGGAUUAAUUGU - 3’arrow_forwardGiven the DNA sequence below: 5’-ACATGTGTACAGGCTTTGTCTGAATGGCTT-3’ 3’-TGTACACATGTCCGAAACAGACTTACCGAA-5’ Transcribe the gene. (Write the primary structure of the mRNA that will be produced.)arrow_forward
- Assume the following portion of an mRNA. Find a start signal, and write the amino acid sequence that is coded for. 5'-GCCAUGUUUCCGAGUUAUCCCAAAGAUAAAAAAGAG 3'arrow_forwardAs opposed to DNA replication or transcription, translation requires the correct reading frame. Use the sequence below to illustrate what the “reading frame” on an mRNA refers to. (A): 5’ UUGCAUUGCAGC 3’ Write out ALL of the possible reading frames for the RNA shown in part (a).arrow_forwardFor the following mRNA sequence (reading from left to right) what will be the amino acid sequence following translation? (Use chart provided) AUGCCAGUUGAAUAA First position U C A UUU UUC UUA UUG CUU CUC CUA CUG U >Phe GUU GUC GUA GUG >Leu >Leu AUU ACU AUC lle ACC AUA ACA AUG Met/start ACG >Val UCU UCC UCA UCG ©2019 Pearson Education, Inc. CCU CCC CCA CCG GCU GCC GCA GCG Second position A >Ser >Pro Thr >Ala UAU UGU U UAC UGC C UAA Stop UGA Stop A UAG Stop UGG Trp G CAU CAC CAA CAG AAU AAC AAA AAG GAU GAC GAA GAG Tyr >His >Gin >Asn >Lys >Asp >Glu CGU CGC CGA CGG AGU AGC AGA AGG G GGU GGC GGA GGG >Cys Arg >Ser >Arg >Gly DOAG SCAG U с А UCA с А G Third position Correct answer not given Met-Val-Tyr-Pro Met-His-Phe-Ala-Arg Pro-Val-Met-Leu-His Met-Pro-Val-Gluarrow_forward
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