a.
To determine:
The sequence that is genomic fragment and the sequence that is cDNA fragment.
Introduction:
The short sequences of DNA that are obtained from the genome of an organism are termed as genomic fragments. The fragments of complementary DNA that are stored in the cDNA library are termed as cDNA fragments.
b.
To determine:
The RNA like strand of the genomic fragment and to represent vertical lines between exon and introns.
Introduction:
The genetic material of eukaryotes is composed of two parts. These are introns and exons. The coding parts of DNA that encode for amino acids are termed as exons. However, the non-coding parts that do not encode for amino acids are termed as introns. The prokaryotes are composed of only the exons. They do not contain introns.
c.
To determine:
The sequence features important for RNA splicing that is missing.
Introduction:
The mRNA contains both introns and exons. The exons encode for the amino acids while the introns do not encode for amino acids. They introns inhibit the synthesis of proteins. The process by which all introns are removed from mRNA is termed as RNA splicing.
d.
To determine:
The amino acid sequence of protein product of the gene.
Introduction:
The mRNA consists of many bases. A collection of three bases that has the capability to code for a particular amino acid is called codon. Codons are present in the mRNA. These codons attach with the anticodon part of tRNA to synthesize amino acid. The anticodon part of tRNA is complementary to the codon part of mRNA. As a result, these two join together and undergo a translation process to produce amino acids.
Trending nowThis is a popular solution!
Chapter 10 Solutions
Genetics: From Genes to Genomes
- A molecular geneticist hopes to find a Gene in human liver cell that codes for an important blood-clotting protein,he knows that the nucleotide sequence of a small part of the Gene is GTGGACTGACA.briefly explain how to obtain genearrow_forwardGiven the following DNA sequence of the template strand for a given gene: 5' TTTCCGTCTCAGGGCTGAAAATGTTTGCTCATCGAACGC3' Part A ) Write the mRNA that will be transcribed from the DNA sequence above (be sure to label the 5' and 3' ends). Part B ) Use the genetic code to write the peptide sequence translated in a cell from the mRNA in part A. Please use the 3 letter abbreviation for each amino acid. Part C: How would the peptide synthesized in a cell be different if the mRNA was translated in vitro (i.e. not in the cell)?arrow_forwardDNA from a eukaryotic gene was isolated, denatured, and hybridized to the mRNA transcribed from the gene; the hybridized structure was then observed with an electron microscope. The adjoining diagram shows the structure that was observed. a. How many introns and exons are there in this gene? Explain your answer.arrow_forward
- When the cDNA was sequenced by the Sanger method utilizing ddCTP, the following products were obtained: Tetranucleotide Hexanucleotide Nonanucleotide Decanucleotide Dodenucleotide Octadecanucleotide Nonadecanucleotide 21-nucleotide 6c. What is the sequence of the bases in the mRNA coding for the peptide above? Thearrow_forwardiarrow_forward) A normal mRNA that reads 5'- UGCCAUGGUAAUAACACAUGAAGGCCUGAAC-3' was an insertion mutation that changes the sequence to 5'- UGCCAUGGUUAAUAACACAUGAGGCGUGAAC-3'. Translate the original mRNA and the mutated mRNA and explain how insertion mutations can have dramatic effects on proteins. ( Hint; Be sure to find the initiation site).arrow_forward
- 1) Which statement below explains the trick in sanger sequencing that produces fluorescently labeled fragments at every length within a fragment? a) When synthesizing a copy of the DNA to be sequenced, a high concentration of fluorescently labeled dideoxynucleotides (ddNTPs) are used along with a low concentration of deoxynucleotides (dNTPs) to produce the chain termination events at every location in the sequence. b) When synthesizing a copy of the DNA to be sequenced, fluorescently labeled dideoxynucleotides (ddNTPs) are used instead of deoxynucleotides (dNTPs) to produce the chain termination events at every location in the sequence. c) When synthesizing a copy of the DNA to be sequenced, a low concentration of fluorescently labeled dideoxynucleotides (ddNTPs) are used along with a high concentration of deoxynucleotides (dNTPs) to produce the chain termination events at every location in the sequence. d) When synthesizing a copy of the DNA to be sequenced, fluorescently labeled…arrow_forwarda) Complete the table below. Assume that reading is from left to right and that the columns represent transcriptional and translational alignments. Label the 5’ and 3’ ends of DNA and RNA and carboxy and amino acid ends of protein. (You may fill in this chart by hand writing- no typing necessary here.) 2. b) Is the top or bottom DNA strand the template strand?arrow_forwardYou would like to add a nuclear localization sequence (NLS) of Lys-Lys-Lys-Arg-Lys to a protein that is usually found in the cytoplasm of a yeast cell. To accomplish this, you introduce the nucleotide sequence encoding the NLS into the gene that encodes the cytoplasmic protein of interest. a. What is the size of the nucleotide insert that will encode the NLS? Briefly explain. 5' 3' b. Below is a diagram of the gene encoding the cytoplasmic protein of interest in the yeast genome. If your goal is to put the NLS at the carboxyl (C) terminus of the protein, at which location (A-E) should the NLS be inserted? Briefly explain. A TATAA ATATT promoter +1 B ATG TAC D TAA ATT stop codon E 3' 5'arrow_forward
- Given the following Wild Type and Mutated DNA sequences: 1.) Identify where the base pair change occurs ( what letter changed?) 2.) For BOTH sequences, write the mRNA strands, define the codon regions and amino acid sequences. 3.) Describe what kind of mutation has occurred (missense, nonsense, or silent), and what effect this may have on the protein. Wild Type DNA Sequence: 3' - AGGCTCGCCTGT - 5' Mutated DNA Sequence: 3' - AGTCTCGCCTGT - 5'arrow_forwardYou isolate a mouse Tau-gene-containing DNA fragment from the chicken and hybridize it to the freshly-made and isolated hnRNA (primary transcript) from the nucleus of the mouse cells transcribed from the Tau gene (immediately after it was produced), allowing no time for processing of the hnRNA. Describe what you see when you look at the DNA/RNA hybrid molecule under the electron microscope.arrow_forwardA eukaryotic gene has two introns and three exons. The first intron closest to the promoter is 157 bp long and the second, farthest from the promoter, is 236. The three exons, in sequence from closest to farthest from the promoter, are 213 bp, 180 bp and 423 bp respectively. Draw the structure you would obtain if you hybridized the template strand of the transcribed region of this gene and three hundred base pairs of additional flanking DNA at each end with the mRNA produced from this gene. Can you estimate the size in amino acid residues of the protein coded for by this gene? Please justify you answer.arrow_forward
- Biology: The Dynamic Science (MindTap Course List)BiologyISBN:9781305389892Author:Peter J. Russell, Paul E. Hertz, Beverly McMillanPublisher:Cengage Learning