Genetics: From Genes to Genomes
6th Edition
ISBN: 9781259700903
Author: Leland Hartwell Dr., Michael L. Goldberg Professor Dr., Janice Fischer, Leroy Hood Dr.
Publisher: McGraw-Hill Education
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Chapter 10, Problem 22P
Complete genome sequences indicate that the human genome has roughly 27,000 genes, while the worm (nematode) genome has about 22,000 genes. Explain how the human genome with only about 20% more genes can encode a creature enormously more complex than the worm.
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Chapter 10 Solutions
Genetics: From Genes to Genomes
Ch. 10 - Prob. 1PCh. 10 - List three independent techniques you could use to...Ch. 10 - Figure 10.2a has numbers indicating the...Ch. 10 - Which of the enzymes from the following list would...Ch. 10 - Prob. 5PCh. 10 - a. What sequence information about a gene is...Ch. 10 - Why do geneticists studying eukaryotic organisms...Ch. 10 - Consider three different kinds of human libraries:...Ch. 10 - The human genome has been sequenced, but we still...Ch. 10 - This problem investigates issues encountered in...
Ch. 10 - For the sake of simplicity, Fig. 10.4 omitted one...Ch. 10 - Give two different reasons for the much higher...Ch. 10 - Using a cDNA library, you isolated two different...Ch. 10 - The figure that follows shows part of a modified...Ch. 10 - In Problem 14, cDNAs F and G could not be found in...Ch. 10 - Fig. 10.10 presents a model for exon shuffling in...Ch. 10 - An interesting phenomenon found in vertebrate DNA...Ch. 10 - a. If you found a zinc-finger domain which...Ch. 10 - Prob. 19PCh. 10 - In the human immune system, so-called B cells can...Ch. 10 - Chimpanzees have a set of hemoglobin genes very...Ch. 10 - Complete genome sequences indicate that the human...Ch. 10 - On your computers browser, view the page accessed...Ch. 10 - Prob. 24PCh. 10 - Prob. 25PCh. 10 - Certain individuals with mild forms of...Ch. 10 - The 1 and 2 genes in humans are identical in their...Ch. 10 - Prob. 28P
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- The Japanese canopy plant (Paris japonica) has one of the largest of all eukaryotic genomes, with approximately 150 billion base pairs, about 50 times the size of the human genome. In contrast, the bladderwort Utricularia gibba has one of the smallest plant genomes, with only 82 million base pairs. What predictions can you make about the genomes of these two species?arrow_forwardYou are interested in finding out the function of a particular gene in the mouse genome. You have determined the nucleotide sequence of the gene, defined the portion that codes for its protein product, and searched the relevant database for similar sequences; however, neither the gene nor the encoded protein resembles anything previously described. What types of additional information about the gene and the encoded protein would you like to know in order to narrow down its function, and why?arrow_forwardGiven our knowledge of genome sizes in different organisms, would you predict that Homo sapiens or the two-toed salamander (Amphiuma means) has the larger genome?arrow_forward
- Annotation of the human genome sequence reveals a discrepancy between the number of protein-coding genes and the number of predicted proteins actually expressed by the genome. Proteomic analysis indicates that human cells are capable of synthesizing more than 100,000 different proteins and perhaps three times this number. What is the discrepancy, and how can it be reconciled?arrow_forwardAntibiotics such as chloramphenicol, tetracycline, and erythromycin inhibit protein synthesis in bacteria, but have no effect on the synthesis of proteins encoded by eukaryotic nuclear genes. Cycloheximide inhibits the synthesis of proteins encoded by nuclear genes, but has no effect on bacterial protein synthesis. How might these compounds be used to determine which proteins are encoded by mitochondrial and chloroplast genomes?arrow_forwardWhat are some reasons why, in multicellular eukaryotes, genome size is not necessarily related to number of protein-coding genes or organismal complexity?arrow_forward
- In relation to central dogma of molecular biology answer the following questions: The length of a particular gene in human DNA, measured from the start site for transcription to the end of the protein-coding region, is 10,000 nucleotides, whereas the length of the mRNA produced from this gene is 4000 nucleotides. What is the most likely reason for this difference?arrow_forwardThe human genome does not encode substantially more protein domains than do invertebrate genomes, yet it encodes many more proteins. How are more proteins encoded when the number of domains does not differ substantially?arrow_forwardThe human genome contains approximately 106 copies of an Alusequence, one of the best-studied classes of short interspersed elements(SINEs), per haploid genome. Individual Alu units share a282-nucleotide consensus sequence followed by a 3 @adenine@richtail region [Schmid (1998)]. Given that there are approximately3 * 10^9 base pairs per human haploid genome, about how manybase pairs are spaced between each Alu sequence?arrow_forward
- Next-generation sequencing reveals that six new mutations have occurred in the coding regions of genes in an individual diploid fly. If the coding regions of this fly comprise 100 million nucleotides per haploid genome, what is the mutation rate per nucleotide?arrow_forwardArabidopsis thaliana has among the smallest genomes in higher plants, with a haploid genome size of about 100 Mb. If this genome is digested with BbvCl, a restriction enzyme which cuts at the sequence CCTCAGC GGAGTCG 1. approximately how many DNA fragments would be produced? Assume the DNA has a random sequence with equal amounts of each base.arrow_forwardThe figure below shows the introns and exons found in gene X. The size of each exon and intron is shown as well. A study on this organism found that two mature mRNA molecules are produced for this gene. One is 867 nucleotides in length, and the other is 685 nucleotides in length. Name the process responsible for producing this variation. Also explain how these 867 and 685 nucleotide fragments were produced by referring to the information provided. Hint: This organism produces a poly-A tail of 150 nucleotides.arrow_forward
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Genome Annotation, Sequence Conventions and Reading Frames; Author: Loren Launen;https://www.youtube.com/watch?v=MWvYgGyqVys;License: Standard Youtube License