The mass of chloroform and HF required to make starting material CHClF 2 has to be stated. Concept Introduction: Polymers are the high molecular mass compounds. The small monomers units joined together to form large molecule, this reaction is known as polymerization reaction. Addition polymerization is the polymerization in which monomer units are linked together with no side product formation. Addition polymerization is given by the molecules which contains carbon-carbon double bond.

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Answer 1

Question

Definition Definition Chemical process in which one or more monomers combine to produce a very large chain-like molecule called a polymer. The functional groups present on the monomers and their steric effects are responsible for polymerization through a sequence of reactions that vary in complexity. There exists a stable covalent chemical bond between monomers that sets apart polymerization from other processes.

Chapter 10, Problem 100QRT

Interpretation Introduction

Interpretation:

The mass of chloroform and $HF$ required to make starting material $CHClF2$ has to be stated.

Concept Introduction:

Polymers are the high molecular mass compounds. The small monomers units joined together to form large molecule, this reaction is known as polymerization reaction. Addition polymerization is the polymerization in which monomer units are linked together with no side product formation. Addition polymerization is given by the molecules which contains carbon-carbon double bond.

Expert Solution & Answer

Explanation of Solution

The polymer Teflon is formed by the addition reaction of tetrafluoroethylene.

Consider the given reaction as follows.

$F2C=CF2→peroxide catalystTeflon$

From the above reaction, one mole of tetrafluoroethylene gives one mole of Teflon. The molar mass of tetrafluoroethylene and teflon is same. Therefore, $1 kg$ of Teflon is obtained by $1 kg$ tetrafluoroethylene.

Conversion of kilograms to grams is as follows.

$1 kg=1000 g$

The molar mass of tetrafluoroethylene is $100.02 g mol−1$ .

Use the following expression for moles of a compound.

$Number of moles=Given massMolar mass$

Substitute $1000 g$ for given mass and $100.02 g mol−1$ for molar mass.

$Number of moles of tetrafluoroethylene=1000 g100.02 g mol−1=9.99 mol$

Consider the reaction for the formation of tetrafluoroethylene.

$2 CHClF2→high TF2C=CF2+2 HCl$

From the given reaction, $2 mol$ of $CHClF2$ gives $1 mol$ of $F2C=CF2$ . Therefore, $9.99 mol$ of $F2C=CF2$ is formed from $19.98 mol$ of $CHClF2$ .

Consider the given reaction as follows.

$CHCl3+2 HF→CHClF2+2 HCl$

One mole of $CHClF2$ is formed by the one mole of $CHCl3$ . Therefore, $19.98 mol$ of $CHClF2$ is formed by $19.98 mol$ of $CHCl3$ .

The molar mass of $CHCl3$ is $119.37 g mol−1$ .

Use the following expression to calculate the amount of $CHCl3$ required.

$Amount of CHCl3=Number of moles×Molar mass$

Substitute $119.37 g mol−1$ for molar mass and $19.98 mol$ for moles in the above equation.

$Amount of CHCl 3=19.98 mol×119.37 g mol−1=2.38×103 g_$

One mole of $CHClF2$ is formed by the two moles of $HF$ . Therefore, $19.98 mol$ of $CHClF2$ is formed by $39.96 mol$ of $HF$ .

The molar mass of $HF$ is $20.01 g mol−1$ .

Use the following expression to calculate the amount of $HF$ required.

$Amount of HF=Number of moles×Molar mass$

Substitute $20.01 g mol−1$ for molar mass and $39.96 mol$ for moles in above equation.

$Amount of HF=39.96 mol×20.01 g mol−1=7.94×102 g_$

Therefore, for preparing $1 kg$ Teflon, $2.38×103 g_$ of chloroform and $7.94×102 g_$ of $HF$ is required.

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Answer 2

Question

Definition Definition Chemical process in which one or more monomers combine to produce a very large chain-like molecule called a polymer. The functional groups present on the monomers and their steric effects are responsible for polymerization through a sequence of reactions that vary in complexity. There exists a stable covalent chemical bond between monomers that sets apart polymerization from other processes.

Chapter 10, Problem 100QRT

Interpretation Introduction

Interpretation:

The mass of chloroform and $HF$ required to make starting material $CHClF2$ has to be stated.

Concept Introduction:

Polymers are the high molecular mass compounds. The small monomers units joined together to form large molecule, this reaction is known as polymerization reaction. Addition polymerization is the polymerization in which monomer units are linked together with no side product formation. Addition polymerization is given by the molecules which contains carbon-carbon double bond.

Expert Solution & Answer

Explanation of Solution

The polymer Teflon is formed by the addition reaction of tetrafluoroethylene.

Consider the given reaction as follows.

$F2C=CF2→peroxide catalystTeflon$

From the above reaction, one mole of tetrafluoroethylene gives one mole of Teflon. The molar mass of tetrafluoroethylene and teflon is same. Therefore, $1 kg$ of Teflon is obtained by $1 kg$ tetrafluoroethylene.

Conversion of kilograms to grams is as follows.

$1 kg=1000 g$

The molar mass of tetrafluoroethylene is $100.02 g mol−1$ .

Use the following expression for moles of a compound.

$Number of moles=Given massMolar mass$

Substitute $1000 g$ for given mass and $100.02 g mol−1$ for molar mass.

$Number of moles of tetrafluoroethylene=1000 g100.02 g mol−1=9.99 mol$

Consider the reaction for the formation of tetrafluoroethylene.

$2 CHClF2→high TF2C=CF2+2 HCl$

From the given reaction, $2 mol$ of $CHClF2$ gives $1 mol$ of $F2C=CF2$ . Therefore, $9.99 mol$ of $F2C=CF2$ is formed from $19.98 mol$ of $CHClF2$ .

Consider the given reaction as follows.

$CHCl3+2 HF→CHClF2+2 HCl$

One mole of $CHClF2$ is formed by the one mole of $CHCl3$ . Therefore, $19.98 mol$ of $CHClF2$ is formed by $19.98 mol$ of $CHCl3$ .

The molar mass of $CHCl3$ is $119.37 g mol−1$ .

Use the following expression to calculate the amount of $CHCl3$ required.

$Amount of CHCl3=Number of moles×Molar mass$

Substitute $119.37 g mol−1$ for molar mass and $19.98 mol$ for moles in the above equation.

$Amount of CHCl 3=19.98 mol×119.37 g mol−1=2.38×103 g_$

One mole of $CHClF2$ is formed by the two moles of $HF$ . Therefore, $19.98 mol$ of $CHClF2$ is formed by $39.96 mol$ of $HF$ .

The molar mass of $HF$ is $20.01 g mol−1$ .

Use the following expression to calculate the amount of $HF$ required.

$Amount of HF=Number of moles×Molar mass$

Substitute $20.01 g mol−1$ for molar mass and $39.96 mol$ for moles in above equation.

$Amount of HF=39.96 mol×20.01 g mol−1=7.94×102 g_$

Therefore, for preparing $1 kg$ Teflon, $2.38×103 g_$ of chloroform and $7.94×102 g_$ of $HF$ is required.

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Answer 3

Question

Definition Definition Chemical process in which one or more monomers combine to produce a very large chain-like molecule called a polymer. The functional groups present on the monomers and their steric effects are responsible for polymerization through a sequence of reactions that vary in complexity. There exists a stable covalent chemical bond between monomers that sets apart polymerization from other processes.

Chapter 10, Problem 100QRT

Interpretation Introduction

Interpretation:

The mass of chloroform and $HF$ required to make starting material $CHClF2$ has to be stated.

Concept Introduction:

Polymers are the high molecular mass compounds. The small monomers units joined together to form large molecule, this reaction is known as polymerization reaction. Addition polymerization is the polymerization in which monomer units are linked together with no side product formation. Addition polymerization is given by the molecules which contains carbon-carbon double bond.

Expert Solution & Answer

Explanation of Solution

The polymer Teflon is formed by the addition reaction of tetrafluoroethylene.

Consider the given reaction as follows.

$F2C=CF2→peroxide catalystTeflon$

From the above reaction, one mole of tetrafluoroethylene gives one mole of Teflon. The molar mass of tetrafluoroethylene and teflon is same. Therefore, $1 kg$ of Teflon is obtained by $1 kg$ tetrafluoroethylene.

Conversion of kilograms to grams is as follows.

$1 kg=1000 g$

The molar mass of tetrafluoroethylene is $100.02 g mol−1$ .

Use the following expression for moles of a compound.

$Number of moles=Given massMolar mass$

Substitute $1000 g$ for given mass and $100.02 g mol−1$ for molar mass.

$Number of moles of tetrafluoroethylene=1000 g100.02 g mol−1=9.99 mol$

Consider the reaction for the formation of tetrafluoroethylene.

$2 CHClF2→high TF2C=CF2+2 HCl$

From the given reaction, $2 mol$ of $CHClF2$ gives $1 mol$ of $F2C=CF2$ . Therefore, $9.99 mol$ of $F2C=CF2$ is formed from $19.98 mol$ of $CHClF2$ .

Consider the given reaction as follows.

$CHCl3+2 HF→CHClF2+2 HCl$

One mole of $CHClF2$ is formed by the one mole of $CHCl3$ . Therefore, $19.98 mol$ of $CHClF2$ is formed by $19.98 mol$ of $CHCl3$ .

The molar mass of $CHCl3$ is $119.37 g mol−1$ .

Use the following expression to calculate the amount of $CHCl3$ required.

$Amount of CHCl3=Number of moles×Molar mass$

Substitute $119.37 g mol−1$ for molar mass and $19.98 mol$ for moles in the above equation.

$Amount of CHCl 3=19.98 mol×119.37 g mol−1=2.38×103 g_$

One mole of $CHClF2$ is formed by the two moles of $HF$ . Therefore, $19.98 mol$ of $CHClF2$ is formed by $39.96 mol$ of $HF$ .

The molar mass of $HF$ is $20.01 g mol−1$ .

Use the following expression to calculate the amount of $HF$ required.

$Amount of HF=Number of moles×Molar mass$

Substitute $20.01 g mol−1$ for molar mass and $39.96 mol$ for moles in above equation.

$Amount of HF=39.96 mol×20.01 g mol−1=7.94×102 g_$

Therefore, for preparing $1 kg$ Teflon, $2.38×103 g_$ of chloroform and $7.94×102 g_$ of $HF$ is required.

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Answer 4

Question

Definition Definition Chemical process in which one or more monomers combine to produce a very large chain-like molecule called a polymer. The functional groups present on the monomers and their steric effects are responsible for polymerization through a sequence of reactions that vary in complexity. There exists a stable covalent chemical bond between monomers that sets apart polymerization from other processes.

Chapter 10, Problem 100QRT

Interpretation Introduction

Interpretation:

The mass of chloroform and $HF$ required to make starting material $CHClF2$ has to be stated.

Concept Introduction:

Polymers are the high molecular mass compounds. The small monomers units joined together to form large molecule, this reaction is known as polymerization reaction. Addition polymerization is the polymerization in which monomer units are linked together with no side product formation. Addition polymerization is given by the molecules which contains carbon-carbon double bond.

Expert Solution & Answer

Explanation of Solution

The polymer Teflon is formed by the addition reaction of tetrafluoroethylene.

Consider the given reaction as follows.

$F2C=CF2→peroxide catalystTeflon$

From the above reaction, one mole of tetrafluoroethylene gives one mole of Teflon. The molar mass of tetrafluoroethylene and teflon is same. Therefore, $1 kg$ of Teflon is obtained by $1 kg$ tetrafluoroethylene.

Conversion of kilograms to grams is as follows.

$1 kg=1000 g$

The molar mass of tetrafluoroethylene is $100.02 g mol−1$ .

Use the following expression for moles of a compound.

$Number of moles=Given massMolar mass$

Substitute $1000 g$ for given mass and $100.02 g mol−1$ for molar mass.

$Number of moles of tetrafluoroethylene=1000 g100.02 g mol−1=9.99 mol$

Consider the reaction for the formation of tetrafluoroethylene.

$2 CHClF2→high TF2C=CF2+2 HCl$

From the given reaction, $2 mol$ of $CHClF2$ gives $1 mol$ of $F2C=CF2$ . Therefore, $9.99 mol$ of $F2C=CF2$ is formed from $19.98 mol$ of $CHClF2$ .

Consider the given reaction as follows.

$CHCl3+2 HF→CHClF2+2 HCl$

One mole of $CHClF2$ is formed by the one mole of $CHCl3$ . Therefore, $19.98 mol$ of $CHClF2$ is formed by $19.98 mol$ of $CHCl3$ .

The molar mass of $CHCl3$ is $119.37 g mol−1$ .

Use the following expression to calculate the amount of $CHCl3$ required.

$Amount of CHCl3=Number of moles×Molar mass$

Substitute $119.37 g mol−1$ for molar mass and $19.98 mol$ for moles in the above equation.

$Amount of CHCl 3=19.98 mol×119.37 g mol−1=2.38×103 g_$

One mole of $CHClF2$ is formed by the two moles of $HF$ . Therefore, $19.98 mol$ of $CHClF2$ is formed by $39.96 mol$ of $HF$ .

The molar mass of $HF$ is $20.01 g mol−1$ .

Use the following expression to calculate the amount of $HF$ required.

$Amount of HF=Number of moles×Molar mass$

Substitute $20.01 g mol−1$ for molar mass and $39.96 mol$ for moles in above equation.

$Amount of HF=39.96 mol×20.01 g mol−1=7.94×102 g_$

Therefore, for preparing $1 kg$ Teflon, $2.38×103 g_$ of chloroform and $7.94×102 g_$ of $HF$ is required.

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Answer 5

Chapter 10, Problem 100QRT

Interpretation Introduction

Interpretation:

The mass of chloroform and $HF$ required to make starting material $CHClF2$ has to be stated.

Concept Introduction:

Polymers are the high molecular mass compounds. The small monomers units joined together to form large molecule, this reaction is known as polymerization reaction. Addition polymerization is the polymerization in which monomer units are linked together with no side product formation. Addition polymerization is given by the molecules which contains carbon-carbon double bond.

Expert Solution & Answer

Explanation of Solution

The polymer Teflon is formed by the addition reaction of tetrafluoroethylene.

Consider the given reaction as follows.

$F2C=CF2→peroxide catalystTeflon$

From the above reaction, one mole of tetrafluoroethylene gives one mole of Teflon. The molar mass of tetrafluoroethylene and teflon is same. Therefore, $1 kg$ of Teflon is obtained by $1 kg$ tetrafluoroethylene.

Conversion of kilograms to grams is as follows.

$1 kg=1000 g$

The molar mass of tetrafluoroethylene is $100.02 g mol−1$ .

Use the following expression for moles of a compound.

$Number of moles=Given massMolar mass$

Substitute $1000 g$ for given mass and $100.02 g mol−1$ for molar mass.

$Number of moles of tetrafluoroethylene=1000 g100.02 g mol−1=9.99 mol$

Consider the reaction for the formation of tetrafluoroethylene.

$2 CHClF2→high TF2C=CF2+2 HCl$

From the given reaction, $2 mol$ of $CHClF2$ gives $1 mol$ of $F2C=CF2$ . Therefore, $9.99 mol$ of $F2C=CF2$ is formed from $19.98 mol$ of $CHClF2$ .

Consider the given reaction as follows.

$CHCl3+2 HF→CHClF2+2 HCl$

One mole of $CHClF2$ is formed by the one mole of $CHCl3$ . Therefore, $19.98 mol$ of $CHClF2$ is formed by $19.98 mol$ of $CHCl3$ .

The molar mass of $CHCl3$ is $119.37 g mol−1$ .

Use the following expression to calculate the amount of $CHCl3$ required.

$Amount of CHCl3=Number of moles×Molar mass$

Substitute $119.37 g mol−1$ for molar mass and $19.98 mol$ for moles in the above equation.

$Amount of CHCl 3=19.98 mol×119.37 g mol−1=2.38×103 g_$

One mole of $CHClF2$ is formed by the two moles of $HF$ . Therefore, $19.98 mol$ of $CHClF2$ is formed by $39.96 mol$ of $HF$ .

The molar mass of $HF$ is $20.01 g mol−1$ .

Use the following expression to calculate the amount of $HF$ required.

$Amount of HF=Number of moles×Molar mass$

Substitute $20.01 g mol−1$ for molar mass and $39.96 mol$ for moles in above equation.

$Amount of HF=39.96 mol×20.01 g mol−1=7.94×102 g_$

Therefore, for preparing $1 kg$ Teflon, $2.38×103 g_$ of chloroform and $7.94×102 g_$ of $HF$ is required.

Answer 6

Chapter 10, Problem 100QRT

Interpretation Introduction

Interpretation:

The mass of chloroform and $HF$ required to make starting material $CHClF2$ has to be stated.

Concept Introduction:

Polymers are the high molecular mass compounds. The small monomers units joined together to form large molecule, this reaction is known as polymerization reaction. Addition polymerization is the polymerization in which monomer units are linked together with no side product formation. Addition polymerization is given by the molecules which contains carbon-carbon double bond.

Expert Solution & Answer

Explanation of Solution

The polymer Teflon is formed by the addition reaction of tetrafluoroethylene.

Consider the given reaction as follows.

$F2C=CF2→peroxide catalystTeflon$

From the above reaction, one mole of tetrafluoroethylene gives one mole of Teflon. The molar mass of tetrafluoroethylene and teflon is same. Therefore, $1 kg$ of Teflon is obtained by $1 kg$ tetrafluoroethylene.

Conversion of kilograms to grams is as follows.

$1 kg=1000 g$

The molar mass of tetrafluoroethylene is $100.02 g mol−1$ .

Use the following expression for moles of a compound.

$Number of moles=Given massMolar mass$

Substitute $1000 g$ for given mass and $100.02 g mol−1$ for molar mass.

$Number of moles of tetrafluoroethylene=1000 g100.02 g mol−1=9.99 mol$

Consider the reaction for the formation of tetrafluoroethylene.

$2 CHClF2→high TF2C=CF2+2 HCl$

From the given reaction, $2 mol$ of $CHClF2$ gives $1 mol$ of $F2C=CF2$ . Therefore, $9.99 mol$ of $F2C=CF2$ is formed from $19.98 mol$ of $CHClF2$ .

Consider the given reaction as follows.

$CHCl3+2 HF→CHClF2+2 HCl$

One mole of $CHClF2$ is formed by the one mole of $CHCl3$ . Therefore, $19.98 mol$ of $CHClF2$ is formed by $19.98 mol$ of $CHCl3$ .

The molar mass of $CHCl3$ is $119.37 g mol−1$ .

Use the following expression to calculate the amount of $CHCl3$ required.

$Amount of CHCl3=Number of moles×Molar mass$

Substitute $119.37 g mol−1$ for molar mass and $19.98 mol$ for moles in the above equation.

$Amount of CHCl 3=19.98 mol×119.37 g mol−1=2.38×103 g_$

One mole of $CHClF2$ is formed by the two moles of $HF$ . Therefore, $19.98 mol$ of $CHClF2$ is formed by $39.96 mol$ of $HF$ .

The molar mass of $HF$ is $20.01 g mol−1$ .

Use the following expression to calculate the amount of $HF$ required.

$Amount of HF=Number of moles×Molar mass$

Substitute $20.01 g mol−1$ for molar mass and $39.96 mol$ for moles in above equation.

$Amount of HF=39.96 mol×20.01 g mol−1=7.94×102 g_$

Therefore, for preparing $1 kg$ Teflon, $2.38×103 g_$ of chloroform and $7.94×102 g_$ of $HF$ is required.

Answer 7

Chapter 10, Problem 100QRT

Interpretation Introduction

Interpretation:

The mass of chloroform and $HF$ required to make starting material $CHClF2$ has to be stated.

Concept Introduction:

Polymers are the high molecular mass compounds. The small monomers units joined together to form large molecule, this reaction is known as polymerization reaction. Addition polymerization is the polymerization in which monomer units are linked together with no side product formation. Addition polymerization is given by the molecules which contains carbon-carbon double bond.

Answer 8

Expert Solution & Answer

Explanation of Solution

The polymer Teflon is formed by the addition reaction of tetrafluoroethylene.

Consider the given reaction as follows.

$F2C=CF2→peroxide catalystTeflon$

From the above reaction, one mole of tetrafluoroethylene gives one mole of Teflon. The molar mass of tetrafluoroethylene and teflon is same. Therefore, $1 kg$ of Teflon is obtained by $1 kg$ tetrafluoroethylene.

Conversion of kilograms to grams is as follows.

$1 kg=1000 g$

The molar mass of tetrafluoroethylene is $100.02 g mol−1$ .

Use the following expression for moles of a compound.

$Number of moles=Given massMolar mass$