Chemistry for Engineering Students - 3rd Edition - by Lawrence S. Brown, Tom Holme - ISBN 9781285199023

Chemistry for Engineering Students
3rd Edition
Lawrence S. Brown, Tom Holme
Publisher: Cengage Learning
ISBN: 9781285199023

Solutions for Chemistry for Engineering Students

Book Details

Reflecting Cengage Learning's commitment to offering flexible teaching solutions and value for students and instructors, this new hybrid version features the instructional presentation found in the printed text while delivering all the end-of chapter exercises online in OWLv2, the leading online learning system for chemistry. The result--a briefer printed text that engages students online! Help your students improve their grades and understanding of concepts with this value-packed Hybrid Edition. An access code to OWLv2 with MindTap Reader, is included with the text, providing students with powerful online resources that include tutorials, simulations, randomized homework questions, videos, a complete interactive electronic version of the textbook, and more! Enhanced with a remarkable number of new problems and applications, the Third Edition of CHEMISTRY FOR ENGINEERING STUDENTS provides a concise, thorough, and relevant introduction to chemistry that prepares students for further study in any engineering field. Updated with even more questions and applications specifically geared toward engineering students, the book emphasizes the connection between molecular properties and observable physical properties and the connections between chemistry and other subjects studied by engineering students, such as mathematics and physics. This new edition is now fully supported by OWL, the most widely-used online learning system for chemistry.

Sample Solutions for this Textbook

We offer sample solutions for Chemistry for Engineering Students homework problems. See examples below:

In the periodic table, elements increase in metallic nature when approaching the “left” side of the...Chapter 3, Problem 1COChapter 3, Problem 3.16PAEChapter 3, Problem 3.34PAEChapter 3, Problem 3.35PAEChapter 3, Problem 3.43PAEChapter 3, Problem 3.64PAEChapter 3, Problem 3.65PAEChapter 3, Problem 3.66PAEMolarity is defined as the number of moles of solute in 1 L of solution. The final solution is 0.45...Chapter 3, Problem 3.98PAEChapter 4, Problem 1COChapter 4, Problem 4.7PAEChapter 4, Problem 4.10PAEChapter 4, Problem 4.14PAEChapter 4, Problem 4.15PAEChapter 4, Problem 4.26PAEChapter 4, Problem 4.31PAEChapter 4, Problem 4.49PAEChapter 4, Problem 4.72PAEGiven information: Total mass of Alloy = 7.264 g Total mass of H2(g) released out = 0.3284 g...Chapter 4, Problem 4.87PAEReactions given below take place to result the given products....The physical properties of gases are as follows: The gases have no fixed shape and volume. The...Chapter 5, Problem 5.33PAEChapter 5, Problem 5.43PAEChapter 5, Problem 5.47PAEChapter 5, Problem 5.65PAENo of moles of gas =mass of gas molar mass of CH4 =15.0 g16.0 g/m ( mass of CH4( given)=15.0 g)molar...The ideal gas equation is as follows: PV=nRT Or, PV=(mM) RT Or, M=mRT/PV =( 2.298 g)( 0.0821 atm...Chapter 5, Problem 5.89PAEThus, total number of moles = [0.40+0.50+0.30] mol = 1.20 mol = N1 As given total pressure = P = 740...Step 1: Write the chemical equation The SO2 and O2 react to produce SO3 according to the equation: 2...Chapter 5, Problem 5.103PAEChapter 6, Problem 1COChapter 6, Problem 16COPauli’s exclusion principle and Hund’s rule are useful in writing electronic configurations of atoms...Chapter 6, Problem 6.17PAEλ=( hCE)h=6.634×10−34JsC=3×108m/sE=6.0×10−19J Putting these values in above equation you get λ=(...Chapter 6, Problem 6.42PAEAtomic radius is the distance between center of nucleus and outermost electron shell. Atomic radius...Chapter 6, Problem 6.85PAEChapter 6, Problem 6.86PAEChapter 7, Problem 1COChapter 7, Problem 7.72PAEThe electronic configuration of I is [Kr]4d105s25p5. In the excited state, the configuration becomes...The electronic configuration of P is 3s23p33d0. In the excited state, the configuration becomes...The electronic configuration of Xeis 4d105s25p65d0. In the excited state, the configuration becomes...Chapter 7, Problem 7.76PAEIn the structure of diamond each carbon atom is linked to four other carbon atoms forming a three...1 metric ton of silicon = 106 gm of silicon. On conversion of 106 gm of silicon to moles of silicon,...1 metric ton of silicon = 106 gm of silicon. On conversion of 106 gm of silicon to moles of silicon,...Chapter 9, Problem 1COChapter 9, Problem 9.15PAEChapter 9, Problem 9.16PAEChapter 9, Problem 9.37PAEChapter 9, Problem 9.48PAEChapter 9, Problem 9.52PAEChapter 9, Problem 9.55PAEChapter 9, Problem 9.58PAEChapter 9, Problem 9.79PAEChapter 9, Problem 9.85PAEThe given reaction is: 3CO2(g)+Si3N4(s)→2SiO2(s)+2N2(g)+3C(s) Reaction enthalpy can be calculated...1 barrel of oil can produce 19.5 gallons = 73815.5 mL of gasoline We know, 1 gallon = 3785.41 mL...The causes to obstacles in the recovery and recycling of plastic solid waste in terms of economic,...Based on the thermodynamics third law, ’At absolute zero of temperature, the entropy of every...Chapter 10, Problem 10.47PAEChapter 10, Problem 10.69PAEThe change in Gibbs free energy of a reaction is calculated as follows: ΔG0 = sum of ΔG0 (product) -...Chapter 10, Problem 10.75PAEChapter 10, Problem 10.76PAEChapter 10, Problem 10.84PAEChapter 10, Problem 10.88PAEChapter 10, Problem 10.91PAEChapter 10, Problem 10.101PAEChapter 10, Problem 10.102PAEOzone also formed at ground level but the mechanism and kinetics are very different from that in...Chapter 11, Problem 11.6PAEChapter 11, Problem 11.20PAEChapter 11, Problem 11.24PAEChapter 11, Problem 11.30PAEChapter 11, Problem 11.33PAEChapter 11, Problem 11.35PAEChapter 11, Problem 11.36PAEChapter 11, Problem 11.49PAEGiven Information: The table containing the total pressures in the reaction vessel during the...Chapter 11, Problem 11.57PAEO(g)+N2(g)→NO(g)+ N(g) The rate of the equation for the reaction can be written as follows. R= −k...Chapter 11, Problem 11.70PAE(a) The molar ratio of the reactant molecules, products in balance equation is called stoichiometry....Chapter 12, Problem 1COUsing the formula K = [C]eqc[D]eqd[A]eqa[B]eqb we can calculate the values of equilibrium constants...Chapter 12, Problem 12.36PAEWhen the salt is dissolved in water, it forms the ions. When AgBr is dissolved in water, it...Let solubility of ZnCO3 is 3 then ZnCO 3 ( S ) Zn2+(aq)M C O 3 2− ( aq )M Initial concentration...AgCN(S)⇌Ag+(aq)+CN−(aq)KSP=[Ag+][CN−] Solubility of AgCN is 7.73×10−9M, it means that Concentration...Chapter 12, Problem 12.65PAEChapter 12, Problem 12.67PAECH3COOH(aq)+H2O(l)→CH3COO−(aq)+H3O+(aq) Rate of equilibrium expression...NH3(g)+H2O(l)→NH4+(aq)+OH−(aq) Apply the concept aA+bB⇌cC+dD Rate of equilibrium reaction...The given reaction is as follows:H2(g)+Cl2(g)⇌2HCl(g) First step is to calculate the value of...Here, sulfur dioxide, sodium chloride and water are formed when sodium hydrogen sulfite is reacted...For reaction S(s)+O2(g)⇌SO2(g) Enthalpy change (ΔH0)=ΔHf0[Product]−ΔHf0[Reactants]...There are different types of corrosion: Pitting corrosion: is the most destructive type of...Chapter 13, Problem 3COCell potential in standard condition: Measurement of standard electrode potential of Zn2+/Zn...Chapter 13, Problem 13.26PAEChapter 13, Problem 13.29PAEChapter 13, Problem 13.32PAEIn this reaction, Half-cell reaction at the anode Ga(s)→Ga3+(aq)+3e− Half-cell reaction at the...Chapter 13, Problem 13.39PAEChapter 13, Problem 13.43PAEChapter 13, Problem 13.49PAEChapter 13, Problem 13.104PAEUse the given data to calculate the following: 1st Step: Calculate the total amount of charge...Cosmic rays are divided into mainly three types: galactic cosmic rays, extragalactic cosmic rays and...Because this is an alpha decay, the helium nucleus is ejected with decrease in mass number by 4 and...Atomic numbers of thorium and radium are 90 and 88, respectively. Consider the transformation:...The 232Th radioactive series beginning with 232Th and ending with 208Pb. The sequence occurs as...Given information: The experimentally determined mass of 14C is 14.003242 u. Formula used: E =...Given information: Experimentally determined mass of 7Li is 7.016004 u. Formula used: E = (Δm)c2Δm =...Given information: Experimentally determined mass of 14N is 14.003074 u. Formula used: E = (Δm)c2...Formula used: E = (Δm)c2Δm = Mass defectc = Velocity of light Calculation: Let’s calculate the...92235U+01n→52137Te+4097Zr+201n Apply Einstein’s equation E=Δmc2 Δm= Mass of product − mass of...Write the balanced nuclear reaction. 92235U+01n→3890Sr+54143NP+301n Mass of reactant =mu+mn (putting...The total amount of electrical energy generated by all the nuclear reactors is...Calculating decay constant for A26l as follows: k=0.693t 1 2 k=0.6937.17× 105 yr=9.66×10−7 yr−1 Now,...

More Editions of This Book

Corresponding editions of this textbook are also available below:

EBK CHEMISTRY FOR ENGINEERING STUDENTS,
4th Edition
ISBN: 9781337671439
CHEMISTRY F/ENGINEERING STUDENTS
6th Edition
ISBN: 9780534389741
CHEM FOR ENGNRNG SDNTS (EBOOK) W/ACCES
3rd Edition
ISBN: 9781337739382
Bundle: Chemistry for Engineering Students, 3rd, Loose-Leaf + OWLv2 with Quick Prep and Student Solutions Manual 24-Months Printed Access Card
3rd Edition
ISBN: 9781305600874
Bundle: Chemistry for Engineering Students, 3rd, Loose-Leaf + OWLv2 with QuickPrep 24-Months Printed Access Card
3rd Edition
ISBN: 9781305367388

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