Chemistry: The Molecular Science
5th Edition
ISBN: 9781285199047
Author: John W. Moore, Conrad L. Stanitski
Publisher: Cengage Learning
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Question
Chapter 10, Problem 118QRT
(a)
Interpretation Introduction
Interpretation:
The Lewis structure for the given compound,
Concept Introduction:
Lewis dot structure of a molecule is the structural representation in which bonded atoms of a molecule are shown along with the lone pair of electrons present on them. The valence electrons around an atom are shown by dots. Bonds between atoms are shown by lines and the lone pair of electrons is shown by a pair of dots.
(b)
Interpretation Introduction
Interpretation:
Two resonance structures for this molecule have to be drawn.
Concept Introduction:
Resonance is the phenomena of the delocalization of pi electrons to give extra stability to the molecule. This extra stability comes from the distribution of the energy of the molecule in the resonance structures formed.
(c)
Interpretation Introduction
Interpretation:
The VSEPR theory has to be used to predict the geometry around each carbon and nitrogen atom in the resonance structures.
Concept Introduction:
The three dimensional arrangement of atoms possesses by the molecule in space is known as the molecular geometry. The molecular geometry of any molecule is identified by using the central metal atom, pair of electrons and atoms surrounding the central atom with the help of VSEPR theory. The shape in VSEPR model gives specific angles between the bonds for the corresponding shape and these angles are known as bond angles.
(d)
Interpretation Introduction
Interpretation:
The correct prediction in part (c) has to be detected.
Concept Introduction:
The hybridization is the process of combining atomic orbitals together to get the appropriate directional properties and improved overlapping of atomic orbitals. A hybrid orbital is formed by the mixing of orbital.
(e)
Interpretation Introduction
Interpretation:
The hybridization of nitrogen atom has to be described.
Concept Introduction:
The hybridization is the process of combining atomic orbitals together to get the appropriate directional properties and improved overlapping of atomic orbitals. A hybrid orbital is formed by the mixing of orbital.
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(a) Determine the formal charge of oxygen
in the following structure. If the atom is
formally neutral, indicate a charge of zero.
(b) Draw an alternative Lewis (resonance)
structure for the compound given in part (a).
Show the unshared pairs and nonzero formal
charges in your structure. Don't use radicals.
Formal charge on O
0
For each of the following covalent bonds: (a) use the symbols δ+ and δ- to indicate the direction of polarity (if any).(a) C-F; (b) N-Br; (c) B-C; (d) Si-H(b) Rank the following covalent bonds in order of increasing polarity. (i) C-H, O-H, N-H; (ii) C-N, C-O, B-O; (iii) C-P, C-S, C-N
(i) Draw a complete Lewis dot structure for each of the following compounds. Clearly (ii) indicate all bonds and lone electrons, as well as the formal charge of each atom in the compound. a) NO3 b) NH4* c) CO2
Chapter 10 Solutions
Chemistry: The Molecular Science
Ch. 10.1 - Heptane, C7H16, can be catalytically reformed to...Ch. 10.1 - Prob. 10.2ECh. 10.1 - Prob. 10.1PSPCh. 10.1 - Prob. 10.3ECh. 10.2 - Prob. 10.4ECh. 10.4 - Using a table of average bond enthalpies. Table...Ch. 10.4 - Prob. 10.5CECh. 10.4 - Prob. 10.6CECh. 10.4 - Prob. 10.7CECh. 10.4 - Prob. 10.3PSP
Ch. 10.4 - Prob. 10.8CECh. 10.4 - Prob. 10.9CECh. 10.4 - Prob. 10.10CECh. 10.4 - Prob. 10.11ECh. 10.5 - Prob. 10.12ECh. 10.5 - Prob. 10.4PSPCh. 10.5 - Prob. 10.13ECh. 10.6 - Prob. 10.14CECh. 10.6 - Prob. 10.5PSPCh. 10.6 - Prob. 10.6PSPCh. 10.6 - Prob. 10.7PSPCh. 10.6 - Prob. 10.8PSPCh. 10.6 - Prob. 10.9PSPCh. 10.6 - Prob. 10.15CECh. 10.6 - Prob. 10.16ECh. 10.7 - Prob. 10.17CECh. 10.7 - Prob. 10.18CECh. 10.7 - Prob. 10.19CECh. 10.7 - Prob. 10.20CECh. 10.7 - Prob. 10.10PSPCh. 10.7 - Prob. 10.21ECh. 10 - Prob. ISPCh. 10 - Prob. IISPCh. 10 - Prob. IIISPCh. 10 - Prob. 1QRTCh. 10 - Prob. 2QRTCh. 10 - Prob. 3QRTCh. 10 - Prob. 4QRTCh. 10 - Prob. 5QRTCh. 10 - Prob. 6QRTCh. 10 - Prob. 7QRTCh. 10 - Give two reasons why ethylene glycol has a higher...Ch. 10 - Prob. 9QRTCh. 10 - Prob. 10QRTCh. 10 - Prob. 11QRTCh. 10 - Prob. 12QRTCh. 10 - Prob. 13QRTCh. 10 - Prob. 14QRTCh. 10 - Prob. 15QRTCh. 10 - Prob. 16QRTCh. 10 - Prob. 17QRTCh. 10 - Prob. 18QRTCh. 10 - Prob. 19QRTCh. 10 - Prob. 20QRTCh. 10 - Prob. 21QRTCh. 10 - Prob. 22QRTCh. 10 - Prob. 23QRTCh. 10 - Prob. 24QRTCh. 10 - Prob. 25QRTCh. 10 - Prob. 26QRTCh. 10 - Prob. 27QRTCh. 10 - Prob. 28QRTCh. 10 - Prob. 29QRTCh. 10 - Prob. 30QRTCh. 10 - Prob. 31QRTCh. 10 - Prob. 32QRTCh. 10 - Prob. 33QRTCh. 10 - Prob. 34QRTCh. 10 - Prob. 35QRTCh. 10 - Prob. 36QRTCh. 10 - Prob. 37QRTCh. 10 - Prob. 38QRTCh. 10 - Prob. 39QRTCh. 10 - Prob. 40QRTCh. 10 - Prob. 41QRTCh. 10 - Prob. 42QRTCh. 10 - Prob. 43QRTCh. 10 - Prob. 44QRTCh. 10 - Prob. 45QRTCh. 10 - Prob. 46QRTCh. 10 - Prob. 47QRTCh. 10 - Beeswax contains this compound:
Identify what...Ch. 10 - Prob. 49QRTCh. 10 - Prob. 50QRTCh. 10 - Prob. 51QRTCh. 10 - Prob. 52QRTCh. 10 - Prob. 53QRTCh. 10 - Prob. 54QRTCh. 10 - Prob. 55QRTCh. 10 - Prob. 56QRTCh. 10 - Prob. 57QRTCh. 10 - Prob. 58QRTCh. 10 - Prob. 59QRTCh. 10 - Prob. 60QRTCh. 10 - Prob. 61QRTCh. 10 - Prob. 62QRTCh. 10 - Prob. 63QRTCh. 10 - Prob. 64QRTCh. 10 - Prob. 65QRTCh. 10 - Prob. 66QRTCh. 10 - Prob. 67QRTCh. 10 - Prob. 68QRTCh. 10 - Prob. 69QRTCh. 10 - Prob. 70QRTCh. 10 - Prob. 71QRTCh. 10 - Prob. 72QRTCh. 10 - Prob. 73QRTCh. 10 - Prob. 74QRTCh. 10 - Prob. 75QRTCh. 10 - Prob. 76QRTCh. 10 - Prob. 77QRTCh. 10 - Prob. 78QRTCh. 10 - Prob. 79QRTCh. 10 -
Identify and name all the functional groups in...Ch. 10 - Prob. 81QRTCh. 10 - Prob. 82QRTCh. 10 - Prob. 83QRTCh. 10 - Prob. 84QRTCh. 10 - Prob. 85QRTCh. 10 - Prob. 86QRTCh. 10 - Prob. 87QRTCh. 10 - Prob. 88QRTCh. 10 - Prob. 89QRTCh. 10 - Prob. 90QRTCh. 10 - Prob. 91QRTCh. 10 - Prob. 92QRTCh. 10 - Prob. 93QRTCh. 10 - Prob. 94QRTCh. 10 - Prob. 95QRTCh. 10 - Prob. 96QRTCh. 10 - Assume that a car burns pure octane. C8H18 (d =...Ch. 10 - Prob. 98QRTCh. 10 - Prob. 99QRTCh. 10 - Prob. 100QRTCh. 10 - Prob. 101QRTCh. 10 - Prob. 102QRTCh. 10 - Prob. 103QRTCh. 10 - Prob. 104QRTCh. 10 - Prob. 105QRTCh. 10 - Prob. 106QRTCh. 10 - Prob. 107QRTCh. 10 - Prob. 108QRTCh. 10 - Prob. 109QRTCh. 10 - Prob. 110QRTCh. 10 - Prob. 111QRTCh. 10 - Prob. 112QRTCh. 10 - Prob. 113QRTCh. 10 - Prob. 114QRTCh. 10 - Prob. 115QRTCh. 10 - Prob. 116QRTCh. 10 - Prob. 118QRTCh. 10 - Prob. 119QRTCh. 10 - Prob. 120QRTCh. 10 - Prob. 121QRTCh. 10 - Prob. 122QRTCh. 10 - Prob. 123QRTCh. 10 - Prob. 124QRTCh. 10 - Prob. 125QRTCh. 10 - Prob. 126QRTCh. 10 - Prob. 127QRTCh. 10 - Prob. 10.ACPCh. 10 - Prob. 10.BCPCh. 10 - Prob. 10.CCP
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