Chapter 1, Problem 50R

(a)

To determine

To Find:The dimension of the given block.

Answer to Problem 50R

  $0.08{\text{m}}^2$

Explanation of Solution

Given:

Length of the object is $0.4\text{m}$

Breadth of the object is $0.2\text{m}$

Height of the object is $0.7\text{m}$

Formula:

Dimension of an object is

  $\text{Dimension}\text{=}\text{Length}\times \text{Breadth}$   ...... (1)

Calculation:

Substitute $0.4\text{m}$ for length and $0.2\text{m}$ for breadth in equation (1)

  $\begin{array}{c}\text{Dimension}\text{=}\text{Length}\times \text{Breadth}\\ \text{=}\text{0}\text{.4}\times \text{0}\text{.2}\\ \text{=}\text{0}\text{.08}{\text{m}}^2\end{array}$

Conclusion:

Hence, the required answer is $0.08{\text{m}}^2$ .

(b)

To determine

To Find: The volume of the given block.

Answer to Problem 50R

  $0.056{\text{m}}^{\text{3}}$

Explanation of Solution

Given:

Length of the object is $0.4\text{m}$

Breadth of the object is $0.2\text{m}$

Height of the object is $0.7\text{m}$

Formula:

Volume of an object is

  $\text{Volume}\text{=}\text{Length}\times \text{Breadth}\times \text{height}$   ...... (1)

Calculation:

Substitute $0.4\text{m}$ for length, $0.2\text{m}$ for breadth and $0.7\text{m}$ for volume in equation (1)

  $\begin{array}{c}\text{Volume}\text{=}\text{Length}\times \text{Breadth}\times \text{height}\\ \text{=}\text{0}\text{.4}\times \text{0}\text{.2}\times \text{0}\text{.7}\\ =0.056{\text{m}}^{\text{3}}\end{array}$

Conclusion:

Hence, the required answer is $0.056{\text{m}}^{\text{3}}$ .