Chapter 1, Problem 11STP

To determine

The correct option to be chosen.

Answer to Problem 11STP

The required conversions are, $\boxed{615\text{ mg}=0.615\text{g}}$ , $\boxed{75\text{ dL}=7500\text{ mL}}$

  $\boxed{\text{0}\text{.95 km}=95000\text{ cm}}$

Explanation of Solution

Given:

1. 615 mg to g (b) 75 dL to mL (c) 0.95 km to cm

Formula used:

The expression for conversion from mg to g is,

  $1\text{ mg}=0.001\text{ g}$....................(1)

Here mg is milligram and g is gram.

The expression for conversion from dL to mL is,

  $1\text{ dL}=100\text{ mL}$....................(2)

Here dL is deciliter and mLis milliliter.

The expression for conversion from km to cm is,

  $1\text{ km}=\text{100000 cm}$....................(3)

Here km is kilometer and cm is centimeter.

Calculation:

Substitute 615 mg for 1mg in equation (1)

  $\begin{array}{l}615\text{ mg}=615\times 0.001\text{ g}\\ \boxed{615\text{ mg}=0.615\text{g}}\end{array}$

Substitute 75 dL for 1dL in equation (2)

  $\begin{array}{l}75\text{ dL}=75\times 100\text{ mL}\\ \boxed{75\text{ dL}=7500\text{ mL}}\end{array}$

Substitute 0.95 km for 1 km in equation (3)

  $\begin{array}{l}\text{0}\text{.95 km}=0.95\times 100000\text{ cm}\\ \boxed{\text{0}\text{.95 km}=95000\text{ cm}}\end{array}$

Conclusion:

Hence, the required conversions are, $\boxed{615\text{ mg}=0.615\text{g}}$ , $\boxed{75\text{ dL}=7500\text{ mL}}$

  $\boxed{\text{0}\text{.95 km}=95000\text{ cm}}$