(a)
Interpretation: The type of ion and symbol for the ion formed by the given element is to be identified.
Concept Introduction : There are two types of charged species, anion (negatively charged species) and cation (positively charged species). Anion is formed by the gaining of electron/s whereas a cation is formed by losing electron/s.
(a)
Answer to Problem 6LC
The ion formed by the given element is
Explanation of Solution
The given element is potassium. It belongs to group 1 which is alkali metals. It has 1 valence electron. In order to complete the octet, it can lose 1 electron to form a cation with a +1 charge. The symbol of the ion is
(b)
Interpretation: The type of ion and symbol for the ion formed by the given element is to be identified.
Concept Introduction : There are two types of charged species, anion (negatively charged species) and cation (positively charged species). Anion is formed by the gaining of electron/s whereas a cation is formed by losing electron/s.
(b)
Answer to Problem 6LC
The ion formed by the given element is
Explanation of Solution
The given element is oxygen. It belongs to group 16 and has 6 valence electrons. In order to complete the octet, it can gain 2 electrons to form an anion with a -2 charge. The symbol of the ion is
(c)
Interpretation: The type of ion and symbol for the ion formed by the given element is to be identified.
Concept Introduction : There are two types of charged species, anion (negatively charged species) and cation (positively charged species). Anion is formed by the gaining of electron/s whereas a cation is formed by losing electron/s.
(c)
Answer to Problem 6LC
The ion formed by the given element is
Explanation of Solution
The given element is bromine. It belongs to group 17 in the periodic table. It has 7 valence electrons. Thus, in order to complete the octet, it can gain 1 electron to form an anion with a -1 charge. The symbol is
(d)
Interpretation: The type of ion and symbol for the ion formed by the given element is to be identified.
Concept Introduction : There are two types of charged species, anion (negatively charged species) and cation (positively charged species). Anion is formed by the gaining of electron/s whereas a cation is formed by losing electron/s.
(d)
Answer to Problem 6LC
The ion formed by the given element is
Explanation of Solution
The given element is tin. It can lose 2 electrons to form a cation with a +2 charge. The symbol is
(e)
Interpretation: The type of ion and symbol for the ion formed by the given element is to be identified.
Concept Introduction : There are two types of charged species, anion (negatively charged species) and cation (positively charged species). Anion is formed by the gaining of electron/s whereas a cation is formed by losing electron/s.
(e)
Answer to Problem 6LC
The ion formed by the given element is
Explanation of Solution
The given element is beryllium. It belongs to group 2 which is alkaline earth metal. It has 2 valence electrons. In order to complete the octet, it can lose 2 electrons to form a cation with a +2 charge. The symbol is
(f)
Interpretation: The type of ion and symbol for the ion formed by the given element is to be identified.
Concept Introduction : There are two types of charged species, anion (negatively charged species) and cation (positively charged species). Anion is formed by the gaining of electron/s whereas a cation is formed by losing electron/s.
(f)
Answer to Problem 6LC
The ion formed by the given element is
Explanation of Solution
The given element is cobalt. It can lose 3 electrons to form a cation with a +3 charge. The symbol is
Chapter 9 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
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