Chemistry 2012 Student Edition (hard Cover) Grade 11
Chemistry 2012 Student Edition (hard Cover) Grade 11
12th Edition
ISBN: 9780132525763
Author: Prentice Hall
Publisher: Prentice Hall
Question
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Chapter 9, Problem 96A

(a)

Interpretation Introduction

Interpretation: The molecular formulas of the compound given in the figure is to be determined.

Concept Introduction: Nitrogen and oxygen are both non-metals. They combine through sharing of valence electrons to form molecular compounds. They combine to form more than one stable compound obeying the law of multiple proportions.

(a)

Expert Solution
Check Mark

Answer to Problem 96A

The given compound is a nitrous oxide that has the chemical formula N2O .

Explanation of Solution

In the figure, there are two blue balls representing nitrogen atoms and one red ball denoting oxygen atoms giving the formula N2O .

(b)

Interpretation Introduction

Interpretation: The molecular formulas of the compound given in the figure is to be determined.

Concept Introduction: Nitrogen and oxygen are both non-metals. They combine through sharing of valence electrons to form molecular compounds. They combine to form more than one stable compound obeying the law of multiple proportions.

(b)

Expert Solution
Check Mark

Answer to Problem 96A

The given compound is nitrogen dioxide which has the chemical formula NO2 .

Explanation of Solution

In the figure, there are two red balls representing oxygen atoms and one blue ball denoting nitrogen atoms giving the formula NO2 .

(c)

Interpretation Introduction

Interpretation: The molecular formulas of the compound given in the figure is to be determined.

Concept Introduction: Nitrogen and oxygen are both non-metals. They combine through sharing of valence electrons to form molecular compounds. They combine to form more than one stable compound obeying the law of multiple proportions.

(c)

Expert Solution
Check Mark

Answer to Problem 96A

The compound given in the figure is nitric oxide. It is denoted chemically as NO.

Explanation of Solution

Nitric oxide consists of one nitrogen and one oxygen atom. The figure consists of one blue ball denoting nitrogen and a red one for oxygen, thus the given compound is nitric oxide.

(d)

Interpretation Introduction

Interpretation: The molecular formulas of the compound given in the figure is to be determined.

Concept Introduction: Nitrogen and oxygen are both non-metals. They combine through sharing of valence electrons to form molecular compounds. They combine to form more than one stable compound obeying the law of multiple proportions.

(d)

Expert Solution
Check Mark

Answer to Problem 96A

The given compound is dinitrogen tetroxide with the formula N2O4 .

Explanation of Solution

The figure contains two blue nitrogen balls and four red oxygen balls, giving the formula N2O4 . The name of the compound is dinitrogen tetroxide, using the prefixes ‘di’ for 2 and ‘tetra’ for 4.

Chapter 9 Solutions

Chemistry 2012 Student Edition (hard Cover) Grade 11

Ch. 9.2 - Prob. 11SPCh. 9.2 - Prob. 12SPCh. 9.2 - Prob. 13SPCh. 9.2 - Prob. 14SPCh. 9.2 - Prob. 15SPCh. 9.2 - Prob. 16SPCh. 9.2 - Prob. 17SPCh. 9.2 - Prob. 18LCCh. 9.2 - Prob. 19LCCh. 9.2 - Prob. 20LCCh. 9.2 - Prob. 21LCCh. 9.2 - Prob. 22LCCh. 9.2 - Prob. 23LCCh. 9.2 - Prob. 24LCCh. 9.2 - Prob. 25LCCh. 9.2 - Prob. 26LCCh. 9.3 - Prob. 27SPCh. 9.3 - Prob. 28SPCh. 9.3 - Prob. 29LCCh. 9.3 - Prob. 30LCCh. 9.3 - Prob. 31LCCh. 9.3 - Prob. 32LCCh. 9.3 - Prob. 33LCCh. 9.3 - Prob. 34LCCh. 9.3 - Prob. 35LCCh. 9.3 - Prob. 36LCCh. 9.4 - Prob. 37SPCh. 9.4 - Prob. 38SPCh. 9.4 - Prob. 39SPCh. 9.4 - Prob. 40SPCh. 9.4 - Prob. 41LCCh. 9.4 - Prob. 42LCCh. 9.4 - Prob. 43LCCh. 9.4 - Prob. 44LCCh. 9.4 - Prob. 45LCCh. 9.4 - Prob. 46LCCh. 9.4 - Prob. 47LCCh. 9.5 - Prob. 48SPCh. 9.5 - Prob. 49SPCh. 9.5 - Prob. 50LCCh. 9.5 - Prob. 51LCCh. 9.5 - Prob. 52LCCh. 9.5 - Prob. 53LCCh. 9.5 - Prob. 54LCCh. 9.5 - Prob. 55LCCh. 9.5 - Prob. 56LCCh. 9 - Prob. 57ACh. 9 - Prob. 58ACh. 9 - Prob. 59ACh. 9 - Prob. 60ACh. 9 - Prob. 61ACh. 9 - Prob. 62ACh. 9 - Prob. 63ACh. 9 - Prob. 64ACh. 9 - Prob. 65ACh. 9 - Prob. 66ACh. 9 - Prob. 67ACh. 9 - Prob. 68ACh. 9 - Prob. 69ACh. 9 - Prob. 70ACh. 9 - Prob. 71ACh. 9 - Prob. 72ACh. 9 - Prob. 73ACh. 9 - Prob. 74ACh. 9 - Prob. 75ACh. 9 - Prob. 76ACh. 9 - Prob. 77ACh. 9 - Prob. 78ACh. 9 - Prob. 79ACh. 9 - Prob. 80ACh. 9 - Prob. 81ACh. 9 - Prob. 82ACh. 9 - Prob. 83ACh. 9 - Prob. 84ACh. 9 - Prob. 85ACh. 9 - Prob. 86ACh. 9 - Prob. 87ACh. 9 - Prob. 88ACh. 9 - Prob. 89ACh. 9 - Prob. 90ACh. 9 - Prob. 91ACh. 9 - Prob. 92ACh. 9 - Prob. 93ACh. 9 - Prob. 94ACh. 9 - Prob. 95ACh. 9 - Prob. 96ACh. 9 - Prob. 97ACh. 9 - Prob. 98ACh. 9 - Prob. 99ACh. 9 - Prob. 100ACh. 9 - Prob. 101ACh. 9 - Prob. 102ACh. 9 - Prob. 103ACh. 9 - Prob. 104ACh. 9 - Prob. 105ACh. 9 - Prob. 106ACh. 9 - Prob. 107ACh. 9 - Prob. 108ACh. 9 - Prob. 110ACh. 9 - Prob. 111ACh. 9 - Prob. 112ACh. 9 - Prob. 113ACh. 9 - Prob. 114ACh. 9 - Prob. 115ACh. 9 - Prob. 116ACh. 9 - Prob. 117ACh. 9 - Prob. 118ACh. 9 - Prob. 119ACh. 9 - Prob. 120ACh. 9 - Prob. 121ACh. 9 - Prob. 122ACh. 9 - Prob. 123ACh. 9 - Prob. 124ACh. 9 - Prob. 125ACh. 9 - Prob. 126ACh. 9 - Prob. 127ACh. 9 - Prob. 128ACh. 9 - Prob. 129ACh. 9 - Prob. 130ACh. 9 - Prob. 131ACh. 9 - Prob. 1STPCh. 9 - Prob. 2STPCh. 9 - Prob. 3STPCh. 9 - Prob. 4STPCh. 9 - Prob. 5STPCh. 9 - Prob. 6STPCh. 9 - Prob. 7STPCh. 9 - Prob. 8STPCh. 9 - Prob. 9STPCh. 9 - Prob. 10STPCh. 9 - Prob. 11STPCh. 9 - Prob. 12STPCh. 9 - Prob. 13STP
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