Chemistry 2012 Student Edition (hard Cover) Grade 11
Chemistry 2012 Student Edition (hard Cover) Grade 11
12th Edition
ISBN: 9780132525763
Author: Prentice Hall
Publisher: Prentice Hall
Question
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Chapter 9.1, Problem 1SP

(a)

Interpretation Introduction

Interpretation: The ion formed by the given element is to be identified.

Concept Introduction : There are two types of charged species, anion (negatively charged species) and cation (positively charged species). Anion is formed by the gaining of electron/s whereas a cation is formed by losing electron/s.

(a)

Expert Solution
Check Mark

Answer to Problem 1SP

The ion formed by the given element is an anion.

Explanation of Solution

The given element is selenium. The atomic number of Se is 34. It belongs to group 16 in the periodic table which is the oxygen family. It has 6 valence electrons. To complete an octet, it can gain two electrons to form an anion with a -2 charge.

(b)

Interpretation Introduction

Interpretation: The ion formed by the given element is to be identified.

Concept Introduction : There are two types of charged species, anion (negatively charged species) and cation (positively charged species). Anion is formed by the gaining of electron/s whereas a cation is formed by losing electron/s.

(b)

Expert Solution
Check Mark

Answer to Problem 1SP

The ion formed by the given element is a cation.

Explanation of Solution

The given element is barium. The atomic number of Ba is 56. It belongs to group 2 in the periodic table which is alkaline earth metals. It has 2 valence electrons. In order to complete the octet, it can lose two electrons to form a cation with a +2 charge.

(c)

Interpretation Introduction

Interpretation: The ion formed by the given element is to be identified.

Concept Introduction : There are two types of charged species, anion (negatively charged species) and cation (positively charged species). Anion is formed by the gaining of electron/s whereas a cation is formed by losing electron/s.

(c)

Expert Solution
Check Mark

Answer to Problem 1SP

The ion formed by the given element is an anion.

Explanation of Solution

The given element is phosphorus. The atomic number of phosphorus is 15. It belongs to group 15 in the periodic table which is the nitrogen family. It has 5 valence electrons. In order to complete the octet, it can gain three electrons to form an anion with a -3 charge.

(d)

Interpretation Introduction

Interpretation: The ion formed by the given element is to be identified.

Concept Introduction : There are two types of charged species, anion (negatively charged species) and cation (positively charged species). Anion is formed by the gaining of electron/s whereas a cation is formed by losing electron/s.

(d)

Expert Solution
Check Mark

Answer to Problem 1SP

The ion formed by the given element is an anion.

Explanation of Solution

The given element is iodine. The atomic number of iodine is 53. It belongs to group 17 which is the halogen family. It has 7 valence electrons. Thus, in order to complete the octet, it can gain one electron to form an anion with a -1 charge.

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Chapter 8, Problem 14STP
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Chapter 9.1, Problem 2SP

Chapter 9 Solutions

Chemistry 2012 Student Edition (hard Cover) Grade 11

Ch. 9.1 - Prob. 1SPCh. 9.1 - Prob. 2SPCh. 9.1 - Prob. 3LCCh. 9.1 - Prob. 4LCCh. 9.1 - Prob. 5LCCh. 9.1 - Prob. 6LCCh. 9.1 - Prob. 7LCCh. 9.1 - Prob. 8LCCh. 9.1 - Prob. 9LCCh. 9.2 - Prob. 10SP
Ch. 9.2 - Prob. 11SPCh. 9.2 - Prob. 12SPCh. 9.2 - Prob. 13SPCh. 9.2 - Prob. 14SPCh. 9.2 - Prob. 15SPCh. 9.2 - Prob. 16SPCh. 9.2 - Prob. 17SPCh. 9.2 - Prob. 18LCCh. 9.2 - Prob. 19LCCh. 9.2 - Prob. 20LCCh. 9.2 - Prob. 21LCCh. 9.2 - Prob. 22LCCh. 9.2 - Prob. 23LCCh. 9.2 - Prob. 24LCCh. 9.2 - Prob. 25LCCh. 9.2 - Prob. 26LCCh. 9.3 - Prob. 27SPCh. 9.3 - Prob. 28SPCh. 9.3 - Prob. 29LCCh. 9.3 - Prob. 30LCCh. 9.3 - Prob. 31LCCh. 9.3 - Prob. 32LCCh. 9.3 - Prob. 33LCCh. 9.3 - Prob. 34LCCh. 9.3 - Prob. 35LCCh. 9.3 - Prob. 36LCCh. 9.4 - Prob. 37SPCh. 9.4 - Prob. 38SPCh. 9.4 - Prob. 39SPCh. 9.4 - Prob. 40SPCh. 9.4 - Prob. 41LCCh. 9.4 - Prob. 42LCCh. 9.4 - Prob. 43LCCh. 9.4 - Prob. 44LCCh. 9.4 - Prob. 45LCCh. 9.4 - Prob. 46LCCh. 9.4 - Prob. 47LCCh. 9.5 - Prob. 48SPCh. 9.5 - Prob. 49SPCh. 9.5 - Prob. 50LCCh. 9.5 - Prob. 51LCCh. 9.5 - Prob. 52LCCh. 9.5 - Prob. 53LCCh. 9.5 - Prob. 54LCCh. 9.5 - Prob. 55LCCh. 9.5 - Prob. 56LCCh. 9 - Prob. 57ACh. 9 - Prob. 58ACh. 9 - Prob. 59ACh. 9 - Prob. 60ACh. 9 - Prob. 61ACh. 9 - Prob. 62ACh. 9 - Prob. 63ACh. 9 - Prob. 64ACh. 9 - Prob. 65ACh. 9 - Prob. 66ACh. 9 - Prob. 67ACh. 9 - Prob. 68ACh. 9 - Prob. 69ACh. 9 - Prob. 70ACh. 9 - Prob. 71ACh. 9 - Prob. 72ACh. 9 - Prob. 73ACh. 9 - Prob. 74ACh. 9 - Prob. 75ACh. 9 - Prob. 76ACh. 9 - Prob. 77ACh. 9 - Prob. 78ACh. 9 - Prob. 79ACh. 9 - Prob. 80ACh. 9 - Prob. 81ACh. 9 - Prob. 82ACh. 9 - Prob. 83ACh. 9 - Prob. 84ACh. 9 - Prob. 85ACh. 9 - Prob. 86ACh. 9 - Prob. 87ACh. 9 - Prob. 88ACh. 9 - Prob. 89ACh. 9 - Prob. 90ACh. 9 - Prob. 91ACh. 9 - Prob. 92ACh. 9 - Prob. 93ACh. 9 - Prob. 94ACh. 9 - Prob. 95ACh. 9 - Prob. 96ACh. 9 - Prob. 97ACh. 9 - Prob. 98ACh. 9 - Prob. 99ACh. 9 - Prob. 100ACh. 9 - Prob. 101ACh. 9 - Prob. 102ACh. 9 - Prob. 103ACh. 9 - Prob. 104ACh. 9 - Prob. 105ACh. 9 - Prob. 106ACh. 9 - Prob. 107ACh. 9 - Prob. 108ACh. 9 - Prob. 110ACh. 9 - Prob. 111ACh. 9 - Prob. 112ACh. 9 - Prob. 113ACh. 9 - Prob. 114ACh. 9 - Prob. 115ACh. 9 - Prob. 116ACh. 9 - Prob. 117ACh. 9 - Prob. 118ACh. 9 - Prob. 119ACh. 9 - Prob. 120ACh. 9 - Prob. 121ACh. 9 - Prob. 122ACh. 9 - Prob. 123ACh. 9 - Prob. 124ACh. 9 - Prob. 125ACh. 9 - Prob. 126ACh. 9 - Prob. 127ACh. 9 - Prob. 128ACh. 9 - Prob. 129ACh. 9 - Prob. 130ACh. 9 - Prob. 131ACh. 9 - Prob. 1STPCh. 9 - Prob. 2STPCh. 9 - Prob. 3STPCh. 9 - Prob. 4STPCh. 9 - Prob. 5STPCh. 9 - Prob. 6STPCh. 9 - Prob. 7STPCh. 9 - Prob. 8STPCh. 9 - Prob. 9STPCh. 9 - Prob. 10STPCh. 9 - Prob. 11STPCh. 9 - Prob. 12STPCh. 9 - Prob. 13STP
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