Chemistry 2012 Student Edition (hard Cover) Grade 11
Chemistry 2012 Student Edition (hard Cover) Grade 11
12th Edition
ISBN: 9780132525763
Author: Prentice Hall
Publisher: Prentice Hall
Question
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Chapter 9, Problem 75A

(a)

Interpretation Introduction

Interpretation: The chemical formula of the given compound should be determined.

Concept Introduction: Binary acids are named by using the prefix ‘hydro-‘followed by the base name of the anion and then the suffix ‘-ic’ is used. In the case of oxoacids, the base name of oxoanion has the suffix ‘-ous’ or ‘-ic.

(a)

Expert Solution
Check Mark

Answer to Problem 75A

The chemical formula of nitrous acid is HNO2 .

Explanation of Solution

Nitrous acid contains hydrogen ions and nitrite ions. If the anion name of an acid containing oxygen ends in ‘-ite’ then the name of the acid ends in ‘-ous’. So, in nitrous acid, the anion is a nitrite ion, hence the name HNO2 .

(b)

Interpretation Introduction

Interpretation: The chemical formula of the given compound should be determined.

Concept Introduction: Binary acids are named by using the prefix ‘hydro-‘followed by the base name of the anion and then the suffix ‘-ic’ is used. In the case of oxoacids, the base name of oxoanion has the suffix ‘-ous’ or ‘-ic.

(b)

Expert Solution
Check Mark

Answer to Problem 75A

Aluminum hydroxide can be chemically represented as AlOH3 .

Explanation of Solution

Aluminum hydroxide contains Al3+ ions and OH ions. To maintain electrical neutrality three hydroxide ions are needed per aluminum ion. the three is written as a subscript, hence, it is represented as AlOH3 .

(c)

Interpretation Introduction

Interpretation: The chemical formula of the given compound should be determined.

Concept Introduction: Binary acids are named by using the prefix ‘hydro-‘followed by the base name of the anion and then the suffix ‘-ic’ is used. In the case of oxoacids, the base name of oxoanion has the suffix ‘-ous’ or ‘-ic.

(c)

Expert Solution
Check Mark

Answer to Problem 75A

The chemical formula of hydroselenic acid is H2Se .

Explanation of Solution

Hydroselenic acid consists of two hydrogen atoms bonded to a selenium atom. So, the formula can be written as H2Se .

(d)

Interpretation Introduction

Interpretation: The chemical formula of the given compound should be determined.

Concept Introduction: Binary acids are named by using the prefix ‘hydro-‘followed by the base name of the anion and then the suffix ‘-ic’ is used. In the case of oxoacids, the base name of oxoanion has the suffix ‘-ous’ or ‘-ic.

(d)

Expert Solution
Check Mark

Answer to Problem 75A

Strontium hydroxide can be chemically represented as SrOH2 .

Explanation of Solution

Strontium is an alkaline earth metal that forms Sr2+ ions. It combines with two hydroxide ions to form SrOH2 .

(e)

Interpretation Introduction

Interpretation: The chemical formula of the given compound should be determined.

Concept Introduction: Binary acids are named by using the prefix ‘hydro-‘followed by the base name of the anion and then the suffix ‘-ic’ is used. In the case of oxoacids, the base name of oxoanion has the suffix ‘-ous’ or ‘-ic.

(e)

Expert Solution
Check Mark

Answer to Problem 75A

The chemical formula of phosphoric acid is H3PO4 .

Explanation of Solution

Phosphoric acid is formed by the combination of phosphate ion with hydrogen ion. Phosphate is a polyatomic anion with a -3 charge, which is neutralized by three hydrogen atoms. Thus, the chemical formula is H3PO4 .

Chapter 9 Solutions

Chemistry 2012 Student Edition (hard Cover) Grade 11

Ch. 9.2 - Prob. 11SPCh. 9.2 - Prob. 12SPCh. 9.2 - Prob. 13SPCh. 9.2 - Prob. 14SPCh. 9.2 - Prob. 15SPCh. 9.2 - Prob. 16SPCh. 9.2 - Prob. 17SPCh. 9.2 - Prob. 18LCCh. 9.2 - Prob. 19LCCh. 9.2 - Prob. 20LCCh. 9.2 - Prob. 21LCCh. 9.2 - Prob. 22LCCh. 9.2 - Prob. 23LCCh. 9.2 - Prob. 24LCCh. 9.2 - Prob. 25LCCh. 9.2 - Prob. 26LCCh. 9.3 - Prob. 27SPCh. 9.3 - Prob. 28SPCh. 9.3 - Prob. 29LCCh. 9.3 - Prob. 30LCCh. 9.3 - Prob. 31LCCh. 9.3 - Prob. 32LCCh. 9.3 - Prob. 33LCCh. 9.3 - Prob. 34LCCh. 9.3 - Prob. 35LCCh. 9.3 - Prob. 36LCCh. 9.4 - Prob. 37SPCh. 9.4 - Prob. 38SPCh. 9.4 - Prob. 39SPCh. 9.4 - Prob. 40SPCh. 9.4 - Prob. 41LCCh. 9.4 - Prob. 42LCCh. 9.4 - Prob. 43LCCh. 9.4 - Prob. 44LCCh. 9.4 - Prob. 45LCCh. 9.4 - Prob. 46LCCh. 9.4 - Prob. 47LCCh. 9.5 - Prob. 48SPCh. 9.5 - Prob. 49SPCh. 9.5 - Prob. 50LCCh. 9.5 - Prob. 51LCCh. 9.5 - Prob. 52LCCh. 9.5 - Prob. 53LCCh. 9.5 - Prob. 54LCCh. 9.5 - Prob. 55LCCh. 9.5 - Prob. 56LCCh. 9 - Prob. 57ACh. 9 - Prob. 58ACh. 9 - Prob. 59ACh. 9 - Prob. 60ACh. 9 - Prob. 61ACh. 9 - Prob. 62ACh. 9 - Prob. 63ACh. 9 - Prob. 64ACh. 9 - Prob. 65ACh. 9 - Prob. 66ACh. 9 - Prob. 67ACh. 9 - Prob. 68ACh. 9 - Prob. 69ACh. 9 - Prob. 70ACh. 9 - Prob. 71ACh. 9 - Prob. 72ACh. 9 - Prob. 73ACh. 9 - Prob. 74ACh. 9 - Prob. 75ACh. 9 - Prob. 76ACh. 9 - Prob. 77ACh. 9 - Prob. 78ACh. 9 - Prob. 79ACh. 9 - Prob. 80ACh. 9 - Prob. 81ACh. 9 - Prob. 82ACh. 9 - Prob. 83ACh. 9 - Prob. 84ACh. 9 - Prob. 85ACh. 9 - Prob. 86ACh. 9 - Prob. 87ACh. 9 - Prob. 88ACh. 9 - Prob. 89ACh. 9 - Prob. 90ACh. 9 - Prob. 91ACh. 9 - Prob. 92ACh. 9 - Prob. 93ACh. 9 - Prob. 94ACh. 9 - Prob. 95ACh. 9 - Prob. 96ACh. 9 - Prob. 97ACh. 9 - Prob. 98ACh. 9 - Prob. 99ACh. 9 - Prob. 100ACh. 9 - Prob. 101ACh. 9 - Prob. 102ACh. 9 - Prob. 103ACh. 9 - Prob. 104ACh. 9 - Prob. 105ACh. 9 - Prob. 106ACh. 9 - Prob. 107ACh. 9 - Prob. 108ACh. 9 - Prob. 110ACh. 9 - Prob. 111ACh. 9 - Prob. 112ACh. 9 - Prob. 113ACh. 9 - Prob. 114ACh. 9 - Prob. 115ACh. 9 - Prob. 116ACh. 9 - Prob. 117ACh. 9 - Prob. 118ACh. 9 - Prob. 119ACh. 9 - Prob. 120ACh. 9 - Prob. 121ACh. 9 - Prob. 122ACh. 9 - Prob. 123ACh. 9 - Prob. 124ACh. 9 - Prob. 125ACh. 9 - Prob. 126ACh. 9 - Prob. 127ACh. 9 - Prob. 128ACh. 9 - Prob. 129ACh. 9 - Prob. 130ACh. 9 - Prob. 131ACh. 9 - Prob. 1STPCh. 9 - Prob. 2STPCh. 9 - Prob. 3STPCh. 9 - Prob. 4STPCh. 9 - Prob. 5STPCh. 9 - Prob. 6STPCh. 9 - Prob. 7STPCh. 9 - Prob. 8STPCh. 9 - Prob. 9STPCh. 9 - Prob. 10STPCh. 9 - Prob. 11STPCh. 9 - Prob. 12STPCh. 9 - Prob. 13STP
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