Chemistry 2012 Student Edition (hard Cover) Grade 11
Chemistry 2012 Student Edition (hard Cover) Grade 11
12th Edition
ISBN: 9780132525763
Author: Prentice Hall
Publisher: Prentice Hall
Question
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Chapter 9, Problem 85A

(a)

Interpretation Introduction

Interpretation: The chemical formulas of the given compound are to be determined.

Concept Introduction: Ionic compounds are named by writing the name of the metal with its charge in Roman numerals in parentheses followed by the name of the anion. Ionic compounds are electrically neutral.

(a)

Expert Solution
Check Mark

Answer to Problem 85A

The chemical formula of calcium bromide is CaBr2 .

Explanation of Solution

Calcium is an alkaline earth metal with two positive charges and bromine is a monovalent anion. To balance the charges, two bromine binds with each calcium ion, hence the formula CaBr2 .

(b)

Interpretation Introduction

Interpretation: The chemical formulas of the given compound are to be determined.

Concept Introduction: Ionic compounds are named by writing the name of the metal with its charge in Roman numerals in parentheses followed by the name of the anion. Ionic compounds are electrically neutral.

(b)

Expert Solution
Check Mark

Answer to Problem 85A

The chemical formula of silver chloride is AgCl .

Explanation of Solution

Silver is denoted by the symbol Ag which exists as Ag+ ions and combines with chloride ions to give AgCl.

(c)

Interpretation Introduction

Interpretation: The chemical formulas of the given compound are to be determined.

Concept Introduction: Ionic compounds are named by writing the name of the metal with its charge in Roman numerals in parentheses followed by the name of the anion. Ionic compounds are electrically neutral.

(c)

Expert Solution
Check Mark

Answer to Problem 85A

Aluminum carbide can be chemically represented as Al4C3 .

Explanation of Solution

Aluminum is a trivalent cation and carbon is a tetravalent atom, they combine to form aluminum carbide. Their valences are exchanged with each other and written as the subscript to give the formula Al4C3 .

(d)

Interpretation Introduction

Interpretation: The chemical formulas of the given compound are to be determined.

Concept Introduction: Ionic compounds are named by writing the name of the metal with its charge in Roman numerals in parentheses followed by the name of the anion. Ionic compounds are electrically neutral.

(d)

Expert Solution
Check Mark

Answer to Problem 85A

Nitrogen dioxide can be chemically represented as NO2 .

Explanation of Solution

Nitrogen dioxide contains one nitrogen atom and two oxygen atoms. It is formed by the sharing of electrons, hence the formula NO2 .

(e)

Interpretation Introduction

Interpretation: The chemical formulas of the given compound are to be determined.

Concept Introduction: Ionic compounds are named by writing the name of the metal with its charge in Roman numerals in parentheses followed by the name of the anion. Ionic compounds are electrically neutral.

(e)

Expert Solution
Check Mark

Answer to Problem 85A

The chemical formula of tin(IV) cyanide is SnCN4 .

Explanation of Solution

From the given name tin is having a +4 charge. so to neutralize the charge four monovalent cyanide ions are needed. Hence the formula is SnCN4 .

(f)

Interpretation Introduction

Interpretation: The chemical formulas of the given compound are to be determined.

Concept Introduction: Ionic compounds are named by writing the name of the metal with its charge in Roman numerals in parentheses followed by the name of the anion. Ionic compounds are electrically neutral.

(f)

Expert Solution
Check Mark

Answer to Problem 85A

Lithium hydride can be represented by the chemical formula LiH.

Explanation of Solution

Lithium is an alkali metal that exists as a mono-positive ion. it binds with hydride ions to give lithium hydride with the formula LiH.

(g)

Interpretation Introduction

Interpretation: The chemical formulas of the given compound are to be determined.

Concept Introduction: Ionic compounds are named by writing the name of the metal with its charge in Roman numerals in parentheses followed by the name of the anion. Ionic compounds are electrically neutral.

(g)

Expert Solution
Check Mark

Answer to Problem 85A

The chemical formula of strontium acetate is C4H6O4Sr , it can also be represented as SrCH3COO2 .

Explanation of Solution

Strontium is a group of two metals that exist as a dipositive ion. it combines with two acetate ions to form strontium acetate. So the chemical formula of the compound is C4H6O4Sr .

(h)

Interpretation Introduction

Interpretation: The chemical formulas of the given compound are to be determined.

Concept Introduction: Ionic compounds are named by writing the name of the metal with its charge in Roman numerals in parentheses followed by the name of the anion. Ionic compounds are electrically neutral.

(h)

Expert Solution
Check Mark

Answer to Problem 85A

The chemical formula of sodium silicate is Na2SiO3 .

Explanation of Solution

A silicate ion is an anion containing one silicon atom and three oxygen atoms, having two positive charges. This charge is neutralized by two sodium ions giving the formula Na2SiO3 .

Chapter 9 Solutions

Chemistry 2012 Student Edition (hard Cover) Grade 11

Ch. 9.2 - Prob. 11SPCh. 9.2 - Prob. 12SPCh. 9.2 - Prob. 13SPCh. 9.2 - Prob. 14SPCh. 9.2 - Prob. 15SPCh. 9.2 - Prob. 16SPCh. 9.2 - Prob. 17SPCh. 9.2 - Prob. 18LCCh. 9.2 - Prob. 19LCCh. 9.2 - Prob. 20LCCh. 9.2 - Prob. 21LCCh. 9.2 - Prob. 22LCCh. 9.2 - Prob. 23LCCh. 9.2 - Prob. 24LCCh. 9.2 - Prob. 25LCCh. 9.2 - Prob. 26LCCh. 9.3 - Prob. 27SPCh. 9.3 - Prob. 28SPCh. 9.3 - Prob. 29LCCh. 9.3 - Prob. 30LCCh. 9.3 - Prob. 31LCCh. 9.3 - Prob. 32LCCh. 9.3 - Prob. 33LCCh. 9.3 - Prob. 34LCCh. 9.3 - Prob. 35LCCh. 9.3 - Prob. 36LCCh. 9.4 - Prob. 37SPCh. 9.4 - Prob. 38SPCh. 9.4 - Prob. 39SPCh. 9.4 - Prob. 40SPCh. 9.4 - Prob. 41LCCh. 9.4 - Prob. 42LCCh. 9.4 - Prob. 43LCCh. 9.4 - Prob. 44LCCh. 9.4 - Prob. 45LCCh. 9.4 - Prob. 46LCCh. 9.4 - Prob. 47LCCh. 9.5 - Prob. 48SPCh. 9.5 - Prob. 49SPCh. 9.5 - Prob. 50LCCh. 9.5 - Prob. 51LCCh. 9.5 - Prob. 52LCCh. 9.5 - Prob. 53LCCh. 9.5 - Prob. 54LCCh. 9.5 - Prob. 55LCCh. 9.5 - Prob. 56LCCh. 9 - Prob. 57ACh. 9 - Prob. 58ACh. 9 - Prob. 59ACh. 9 - Prob. 60ACh. 9 - Prob. 61ACh. 9 - Prob. 62ACh. 9 - Prob. 63ACh. 9 - Prob. 64ACh. 9 - Prob. 65ACh. 9 - Prob. 66ACh. 9 - Prob. 67ACh. 9 - Prob. 68ACh. 9 - Prob. 69ACh. 9 - Prob. 70ACh. 9 - Prob. 71ACh. 9 - Prob. 72ACh. 9 - Prob. 73ACh. 9 - Prob. 74ACh. 9 - Prob. 75ACh. 9 - Prob. 76ACh. 9 - Prob. 77ACh. 9 - Prob. 78ACh. 9 - Prob. 79ACh. 9 - Prob. 80ACh. 9 - Prob. 81ACh. 9 - Prob. 82ACh. 9 - Prob. 83ACh. 9 - Prob. 84ACh. 9 - Prob. 85ACh. 9 - Prob. 86ACh. 9 - Prob. 87ACh. 9 - Prob. 88ACh. 9 - Prob. 89ACh. 9 - Prob. 90ACh. 9 - Prob. 91ACh. 9 - Prob. 92ACh. 9 - Prob. 93ACh. 9 - Prob. 94ACh. 9 - Prob. 95ACh. 9 - Prob. 96ACh. 9 - Prob. 97ACh. 9 - Prob. 98ACh. 9 - Prob. 99ACh. 9 - Prob. 100ACh. 9 - Prob. 101ACh. 9 - Prob. 102ACh. 9 - Prob. 103ACh. 9 - Prob. 104ACh. 9 - Prob. 105ACh. 9 - Prob. 106ACh. 9 - Prob. 107ACh. 9 - Prob. 108ACh. 9 - Prob. 110ACh. 9 - Prob. 111ACh. 9 - Prob. 112ACh. 9 - Prob. 113ACh. 9 - Prob. 114ACh. 9 - Prob. 115ACh. 9 - Prob. 116ACh. 9 - Prob. 117ACh. 9 - Prob. 118ACh. 9 - Prob. 119ACh. 9 - Prob. 120ACh. 9 - Prob. 121ACh. 9 - Prob. 122ACh. 9 - Prob. 123ACh. 9 - Prob. 124ACh. 9 - Prob. 125ACh. 9 - Prob. 126ACh. 9 - Prob. 127ACh. 9 - Prob. 128ACh. 9 - Prob. 129ACh. 9 - Prob. 130ACh. 9 - Prob. 131ACh. 9 - Prob. 1STPCh. 9 - Prob. 2STPCh. 9 - Prob. 3STPCh. 9 - Prob. 4STPCh. 9 - Prob. 5STPCh. 9 - Prob. 6STPCh. 9 - Prob. 7STPCh. 9 - Prob. 8STPCh. 9 - Prob. 9STPCh. 9 - Prob. 10STPCh. 9 - Prob. 11STPCh. 9 - Prob. 12STPCh. 9 - Prob. 13STP
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