To construct: The 95% confidence interval for the population mean percent body fat of the female graduate physical therapy students.

Question

Want to see the full answer?

Answer 1

Question

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

Chapter 8.2, Problem 84E

a.

To determine

To construct: The 95% confidence interval for the population mean percent body fat of the female graduate physical therapy students.

b.

To determine

To find: The margin of error for the 95% confidence interval obtained in part (a).

c.

To determine

To interpret: The margin of error of the 95% confidence interval of the population mean.

d.

To determine

To find: The number of female graduates required to be sampled for the margin of error to be within 1.55 percent body fat for each of the 99% confidence interval.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Which model—the one for parliaments or the one for ministries (or cabinets)—presented in the article has the greater explanatory power? How can you tell?

Q. No. 3: Recently airlines have cut services, such as meals and snacks during flights, and started charging extra for some services, such as accommodating overweight luggage, last-minute flight changes, and pets traveling in the cabin. However, they are still concerned about service. Recently, a group of four carriers hired Brunner Marketing Research Inc. to survey passengers regarding their level of satisfaction with a recent flight. The survey included questions on ticketing, boarding, in-flight service, baggage handling, pilot communication, and so forth. Twenty-five questions offered a range of possible answers: excellent, good, fair, or poor. A response of excellent was given a score of 4, good a 3, fair a 2, and poor a 1. These responses were then totaled, so the total score was an indication of the satisfaction with the flight. The greater the score, the higher the level of satisfaction with the service. The highest possible score was 100. Brunner randomly selected and surveyed…

In a study of palatability of antibiotics for children, Doreen Matsui and her colleagues used a voluntary sample of healthy children to assess their reactions to the taste of four antibiotics. The children’s responses were measured on a 10-centimeter visual analog scale that incorporated the use of faces, from sad (low score) to happy (high score). The minimum and maximum scores were, respectively, 0 and 10. The data in the following table (simulated from the results given in Matsui’s report) were obtained when each of five children were asked to rate the taste of all four antibiotics. AntibioticChild I II III IV 1 4.8 2.2 6.8 6.22 8.1 9.2 6.6 9.63 5.0 2.6 3.6 6.54 7.9 9.4 5.3 8.55 3.9 7.4 2.1…

Answer 2

Question

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

Chapter 8.2, Problem 84E

a.

To determine

To construct: The 95% confidence interval for the population mean percent body fat of the female graduate physical therapy students.

b.

To determine

To find: The margin of error for the 95% confidence interval obtained in part (a).

c.

To determine

To interpret: The margin of error of the 95% confidence interval of the population mean.

d.

To determine

To find: The number of female graduates required to be sampled for the margin of error to be within 1.55 percent body fat for each of the 99% confidence interval.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

Chapter 8.2, Problem 84E

a.

To determine

To construct: The 95% confidence interval for the population mean percent body fat of the female graduate physical therapy students.

b.

To determine

To find: The margin of error for the 95% confidence interval obtained in part (a).

c.

To determine

To interpret: The margin of error of the 95% confidence interval of the population mean.

d.

To determine

To find: The number of female graduates required to be sampled for the margin of error to be within 1.55 percent body fat for each of the 99% confidence interval.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

Chapter 8.2, Problem 84E

a.

To determine

To construct: The 95% confidence interval for the population mean percent body fat of the female graduate physical therapy students.

b.

To determine

To find: The margin of error for the 95% confidence interval obtained in part (a).

c.

To determine

To interpret: The margin of error of the 95% confidence interval of the population mean.

d.

To determine

To find: The number of female graduates required to be sampled for the margin of error to be within 1.55 percent body fat for each of the 99% confidence interval.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 8.2, Problem 84E

a.

To determine

To construct: The 95% confidence interval for the population mean percent body fat of the female graduate physical therapy students.

b.

To determine

To find: The margin of error for the 95% confidence interval obtained in part (a).

c.

To determine

To interpret: The margin of error of the 95% confidence interval of the population mean.

d.

To determine

To find: The number of female graduates required to be sampled for the margin of error to be within 1.55 percent body fat for each of the 99% confidence interval.

Answer 6

Chapter 8.2, Problem 84E

a.

To determine

To construct: The 95% confidence interval for the population mean percent body fat of the female graduate physical therapy students.

Answer 7

Chapter 8.2, Problem 84E

a.

To determine

To construct: The 95% confidence interval for the population mean percent body fat of the female graduate physical therapy students.

Answer 8

b.

To determine

To find: The margin of error for the 95% confidence interval obtained in part (a).

Answer 9

b.

To determine

To find: The margin of error for the 95% confidence interval obtained in part (a).

Answer 10

c.

To determine

To interpret: The margin of error of the 95% confidence interval of the population mean.

Answer 11

c.

To determine

To interpret: The margin of error of the 95% confidence interval of the population mean.

Answer 12

d.

To determine

To find: The number of female graduates required to be sampled for the margin of error to be within 1.55 percent body fat for each of the 99% confidence interval.

Answer 13

d.

To determine

To find: The number of female graduates required to be sampled for the margin of error to be within 1.55 percent body fat for each of the 99% confidence interval.

Answer 14

Expert Solution & Answer

Answer 15

Expert Solution & Answer

Answer 16

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 17

Ch. 8.1 - The value of a statistic used to estimate a...Ch. 8.1 - What is a confidence-interval estimate of a...Ch. 8.1 - Prob. 3E Ch. 8.1 - Prob. 4E Ch. 8.1 - Prob. 5E Ch. 8.1 - Suppose that you lake 500 simple random samples...Ch. 8.1 - Prob. 7E Ch. 8.1 - A simple random sample is taken from a population...Ch. 8.1 - Refer to Exercise 8.7 and find a point estimate...Ch. 8.1 - Prob. 10E

To construct: The 95% confidence interval for the population mean percent body fat of the female graduate physical therapy students.

Solution Summary: The author explains the 95% confidence interval for the population mean percent body fat of female graduate physical therapy students.

Videos

To construct: The 95% confidence interval for the population mean percent body fat of the female graduate physical therapy students.

To find: The margin of error for the 95% confidence interval obtained in part (a).

To interpret: The margin of error of the 95% confidence interval of the population mean.

To find: The number of female graduates required to be sampled for the margin of error to be within 1.55 percent body fat for each of the 99% confidence interval.

Want to see the full answer?

Chapter 8 Solutions