Concept explainers
QUANTITATIVE More Enzyme Kinetics. The galactose formed in Reaction 6-17 can be phosphorylated by the transfer of a phosphoryl group from ATP, a reaction catalyzed by the enzyme galactokinase:
Assume that you have isolated the galactokinase enzyme and have determined its kinetic parameters by varying the concentration of galactose in the presence of a constant, high (i.e., saturating) concentration of ATP. The double-reciprocal (Lineweaver–Burk) plot of the data is shown as Figure 6-17.
Figure 6-17 Double-Reciprocal Plot for the Enzyme Galactokinase. See Problem 6-7.
(a) What is the Km of galactokinase for galactose under these assay conditions? What does Km tell us about the enzyme?
(b) What is the Vmax of the enzyme under these assay conditions? What does Vmax tell us about the enzyme?
(c) Assume that you now repeat the experiment, but with the ATP concentration varied and galactose present at a constant, high concentration. Assuming that all other conditions aremaintained as before, would you expect to get the same Vmax value as in part b? Why or why not?
(d) In the experiment described in part c, the Km value turned out to be very different from the value determined in part b. Can you explain why?
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Becker's World of the Cell (9th Edition)
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