Becker's World of the Cell (9th Edition)
Becker's World of the Cell (9th Edition)
9th Edition
ISBN: 9780321934925
Author: Jeff Hardin, Gregory Paul Bertoni
Publisher: PEARSON
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Chapter 5, Problem 5.6PS

QUANTITATIVE The Equilibrium Constant. The following reaction is one of the steps in the glycolytic pathway, which we will encounter again in Chapter 9. You should recognize it already, however, because we used it as an example earlier (see Reaction 5-9):

glucose-6-phosphate fructose-6-phosphate     (5-28)

The equilibrium constant Keq for this reaction at 25°C is 0.5.

(a) Assume that you incubate a solution containing 0.15 M glucose-6-phosphate (G6P) overnight at 25°C with the enzyme phosphoglucoisomerase that catalyzes Reaction 5-28. How many millimoles of fructose-6-phosphate (F6P) will you recover from 10 mL of the incubation mixture the next morning?

(b) What answer would you get for part a if you had started with a solution containing 0.15 M F6P instead?

(c) What answer would you expect for part a if you had started with a solution containing 0.15 M G6P but forgot to add phosphoglucoisomerase to the incubation mixture?

(d) Would you be able to answer the question in part a if you had incubated at 15°C instead of 25°C? Why or why not?

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. Pyruvate can be processed under anaerobic conditions to ethanol (in yeast) or to lactate (in mammals), as shown. Explain the primary purpose of these reactions. Describe the major biochemical features of each reaction
Long explanations are NOT NEEDED. Answer only d and e. ATP accounting. Consider 1 molecule of the sucrose (monomeric units: glucose and fructose) that will undergo complete oxidation. -Number of pyruvate molecules after glycolysis is 4.-Net ATP produced in glycolysis only (via substrate-level phosphorylation) is 2.-Number of NADH produced using the pyruvate dehydrogenase complex reaction is 1. Now find:d. Number of NADH and FADH2 produced from Krebs cycle.e. Net ATP produced (complete oxidation via Malate aspartate shuttle).
They are everywhere. What energetic barrier prevents glycolysis from simply running in reverse tosynthesis glucose? What is the energetic cost to overcome this barrier?
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