Steel Design (Activate Learning with these NEW titles from Engineering!)
6th Edition
ISBN: 9781337094740
Author: Segui, William T.
Publisher: Cengage Learning
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Question
Chapter 5, Problem 5.11.3P
To determine
(a)
The shape for a typical floor beam.
To determine
(b)
The shape for a typical floor beam.
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A steel beam is reinforced by three steel rods. The modulous of elasticity for
concrete is 20Gpa and for steel is 200Gpa. Maximum allowable stress for concrete
is 9.45Mpa and for steel is 140Mpa. Calculate the largest allowable positive WBT
bending moment in the beam.
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The modulus of elasticity for concrete is
20Gpa and for the steel is 200 Gpa.
Allowable stress for concrete is 9Mpa and
for steel is 140Mpa. Calculate the maxium
allowable bending momemt that can be
applied per metal rod of the concrete slab.
150mm
200mm
D=16mm
140 mm
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50mm
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140 mm
140 mm
140 mm
There is a 6m long column. Its section is made up
by 3 steel plates welding flame cutting automatic
welding flange side. The two sides of column are
pinned. And there is a supporting point at the
middle of column in x-direction. Determine the
axial compression resistance.
a. Use Q390 steel
b. Use Q235 steel
c. Discuss the effect of steel grąde (yield stress)
on the compressive behavior of column.
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A simply supported beam has a height of 600 mm and a width of 300mm. Determine the maximum safe live load that the beam can carry. The dead load is the beam weight plus a superimposed load of 15 kN/m The stirrup size is 12 mm, the top bars are 2-20 mm and the bottom bars are 5-28 mm. The clear distance between layers of bottom bars is the bar size, 28 mm. Use fc'=30 MPa, Grade 60 (fy=414 MPa) reinforcements and concrete cover of 50 mm.
Chapter 5 Solutions
Steel Design (Activate Learning with these NEW titles from Engineering!)
Ch. 5 - Prob. 5.2.1PCh. 5 - Prob. 5.2.2PCh. 5 - Verify the value of Zx for a W1850 that is...Ch. 5 - Prob. 5.2.4PCh. 5 - Prob. 5.4.1PCh. 5 - Prob. 5.4.2PCh. 5 - Determine the smallest value of yield stress Fy,...Ch. 5 - Prob. 5.5.1PCh. 5 - Prob. 5.5.2PCh. 5 - Prob. 5.5.3P
Ch. 5 - Prob. 5.5.4PCh. 5 - Prob. 5.5.5PCh. 5 - Prob. 5.5.6PCh. 5 - Prob. 5.5.7PCh. 5 - Prob. 5.5.8PCh. 5 - Prob. 5.5.9PCh. 5 - If the beam in Problem 5.5-9 i5 braced at A, B,...Ch. 5 - Prob. 5.5.11PCh. 5 - Prob. 5.5.12PCh. 5 - Prob. 5.5.13PCh. 5 - Prob. 5.5.14PCh. 5 - Prob. 5.5.15PCh. 5 - Prob. 5.5.16PCh. 5 - Prob. 5.6.1PCh. 5 - Prob. 5.6.2PCh. 5 - Prob. 5.6.3PCh. 5 - Prob. 5.6.4PCh. 5 - Compute the nominal shear strength of an M107.5 of...Ch. 5 - Compute the nominal shear strength of an M1211.8...Ch. 5 - Prob. 5.8.3PCh. 5 - Prob. 5.8.4PCh. 5 - Prob. 5.10.1PCh. 5 - Prob. 5.10.2PCh. 5 - Same as Problem 5.10-2, except that lateral...Ch. 5 - Prob. 5.10.4PCh. 5 - The given beam is laterally supported at the ends...Ch. 5 - Prob. 5.10.6PCh. 5 - Prob. 5.10.7PCh. 5 - Prob. 5.11.1PCh. 5 - Prob. 5.11.2PCh. 5 - Prob. 5.11.3PCh. 5 - Prob. 5.11.4PCh. 5 - Prob. 5.11.5PCh. 5 - Prob. 5.11.6PCh. 5 - Prob. 5.11.7PCh. 5 - Prob. 5.11.8PCh. 5 - Prob. 5.11.9PCh. 5 - Prob. 5.12.1PCh. 5 - Prob. 5.12.2PCh. 5 - Prob. 5.12.3PCh. 5 - Prob. 5.13.1PCh. 5 - Prob. 5.13.2PCh. 5 - Prob. 5.14.1PCh. 5 - Prob. 5.14.2PCh. 5 - Prob. 5.14.3PCh. 5 - Prob. 5.14.4PCh. 5 - Prob. 5.15.1PCh. 5 - Prob. 5.15.2PCh. 5 - Prob. 5.15.3PCh. 5 - Prob. 5.15.4PCh. 5 - Prob. 5.15.5PCh. 5 - Prob. 5.15.6PCh. 5 - Prob. 5.15.7PCh. 5 - Same as Problem 5.15-7, except that the sag rods...
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- 3. A rectangular beam has the following properties: Width, b = 400 mm Effective depth, d 620 mm Tension bars, 10 pcs 28-mm-diameter Compression bars, 3 pcs 25-mm-diameter d' = 70 mm fy = 415 MPa f'c = 22 MPa Determine the design strength of the beam and the safe service live load if the service dead load is 320 kN-m.arrow_forwardA 3-m long steel column of hollow circular cross-section is supported on a steel base plate and a concrete pedestal. Column ends are hinged and sidesway is prevented.the outside diameter of the column is 260 mm, allowable compressive stress is 55 MPa and the allowable concrete bearing stress is 10 Mpa.40. Compute the required thickness of the column tio support axial load of 800 Kn.A. 18 mm B. 19 mm C.20 mm D. 10mm41. Compute for the minimum required diameter of the base plate.A. 300 mm B. 320 mm C.350 mm D. 280 mm42. If the thickness of column is 10mm, find the critical slenderness ratio.A. 33.914 B. 45.871 C.87.876 D. 23.811arrow_forwardSituation #2: A rectangular beam has the following properties: Width, b = 400 mm 415 MPa Effective depth, d = 620 mm 22 MPa Tension bars, 10 pcs 28-mm-diameter Compression bars, 3 pcs 25-mm-diamter d' = 70 mm fy= = fc' = Determine the design strength of the beam and the safe live load if the service dead load is 320 kN.marrow_forward
- USE NSCP 2010 A simply supported beam is reinforced with 4 – 28 mm ø at the bottomand 2 – 28 mm ø at the top of the beam. Steel covering to centroid ofreinforcement is 70 mm at the top and bottom of the beam. The beamhas a total depth of 400 mm and a widthof 300 mm. fc’ = 30 MPa, fy = 415 MPa. Balanced steel ratio ρb = 0.031.Compute the ultimate moment capacity of the beam in kN-m. Usereduction factor of 0.90arrow_forwardDetermine collapse load Wu for continuous beam ABCDE loaded and supported as shown in figure . For span AC plastic moment of resistance is 50 % more than that of CE .arrow_forwardQuestion 29 The laminated beam, shown in cross section, is composed of ?ve 6- in. by 2-in. planks that are glued together. The beam carries a uniformly distributed load of intensity we over its 8-ft simply supported span. If the working stresses are 75 psi for shear in glue, 90 psi for shear in wood, and 8ø0 psi for bending in wood, + 6 in. 1. determine the maximum allowable value of we so that the shear stress in the wood is not exceeded. A. 900 lb/ft C. 833 lb/ft determine the maximum allowable value of we so that the shear B. 555 lb/ft D. NOTA 2. stress in the glue is not exceeded. A. 900 lb/ft C. 833 lb/ft B. 555 lb/ft D. NOTA 3. determine the maximum allowable value of we so that the bending stress in the wood is not exceeded. А. 900 lb/ft В. 555 lb/ft C. 833 lb/ft D. NOTA 5 @ 2 in. = 10 in. –arrow_forward
- Q2: The reinforced concrete Isolated T-Beam shown in Figure 2, carried uniform distribution live load (35 KN/m) and uniform distribution dead load (30 KN/m). Determine the flexural reinforcement to resist the positive moment (only). (Neglect self-weight), use f'c=28 MPa and fr-420 MPa. 750 mm 80 mm 2m+ - 2 m As 250 Figure 2 إضافة ملف 600 mmarrow_forward2. The column shown in the figure is reinforced with 6 - 25mm diam steel with fy: = 415Mpa and f'c = 27Mpa a. Determine the nominal load pn when e = 200mm b. Determine the nominal load when e = 350mm C. 250 mm 65 mm 400mm 65 mm e CD Pnarrow_forwardA beam has a width of 300 mm and an effective depth of 480 mm strength Pc= 34 MPa. Steel yield strength fy=415 MPa. The section is to be reinforced for tension only and the effective concrete cover is 70 mm. Deadload moment is 140 kN-m and the liveload moment is 180 kN-m. Use 2010 NSCP with t= 0.005. A. What is the governing steel ratio? B. What is the maximum number of bars needed for a 25mm diameter reinforcements? C. What is the minimum number of bars needed for a 25mm diameter reinforcements?arrow_forward
- Design an interior span slab of a concrete floor system with the following description: Span = 30 m Imposed dead load= 900 N/m2 Live load= 4900 N/m2 fc’= 28 MPa fy = 415 MPa Note :- Solve by ACI methodarrow_forwardDesign a simply supported rectangular reinforced concrete beam. Note: Neglected the self-weight of the beam. Wu (D.L) PLL Wa (L.L) h b W D.L P LL W LL Fc bar No. of Fy MPа MPa (mm) (mm) (m) kN/m kN kN/m dia. layers 325 500 17 50 20 20 two 28 420arrow_forwardThe uniformly distributed live load on the floor plan in the figure given below is 65 lb/ft². Consider the live load reduction if permitted by the ASCE standard. A (B) B2 G3 -6 @ 6.67' = 40- I B4 G4 B1 40' G1 C2 G2 C3 Establish the loading for girder G3. The loading (P) for girder G3 is [ B3 20' kips. (3) 2 @ 10' = 20' I+ 5 @ 8'=40'arrow_forward
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