Steel Design (Activate Learning with these NEW titles from Engineering!)
6th Edition
ISBN: 9781337094740
Author: Segui, William T.
Publisher: Cengage Learning
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Chapter 5, Problem 5.5.11P
To determine
(a)
To compute:
To determine
(b)
To compute:
The value of
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The service load bending moments on a beam are 128 kip-ft for dead load and 107 kip-ft for
live load. The beam is 12 in. wide, f'c is 3000 psi and fy is 60 ksi. Determine Mu. Mt. p. R.
the depth of the beam and the As of tensile reinforcing required. How many no. 8 bars or No.
10 bars would have the required As?
P =
L1 =
L2=
L1
Your Answer:
P
195
2.50
4.5
Answer
KN
m
m
L2
▷ View hint for Question 1
P
The proposed beam for the loading diagram above is a steel W530x138 W-section.
What is the maximum bending stress?
answer in MPa do not include units
L1
beam
2. The beam shown in Figure P5.8-3 is a W16 × 31 of A992 steel and has continuous lateral support. The two concentrated loads are service live loads. Neglect the weight of the beam and determine whether the beam is adequate for flexure and shear.
a. Use LRFD. b. Use ASD.
Chapter 5 Solutions
Steel Design (Activate Learning with these NEW titles from Engineering!)
Ch. 5 - Prob. 5.2.1PCh. 5 - Prob. 5.2.2PCh. 5 - Verify the value of Zx for a W1850 that is...Ch. 5 - Prob. 5.2.4PCh. 5 - Prob. 5.4.1PCh. 5 - Prob. 5.4.2PCh. 5 - Determine the smallest value of yield stress Fy,...Ch. 5 - Prob. 5.5.1PCh. 5 - Prob. 5.5.2PCh. 5 - Prob. 5.5.3P
Ch. 5 - Prob. 5.5.4PCh. 5 - Prob. 5.5.5PCh. 5 - Prob. 5.5.6PCh. 5 - Prob. 5.5.7PCh. 5 - Prob. 5.5.8PCh. 5 - Prob. 5.5.9PCh. 5 - If the beam in Problem 5.5-9 i5 braced at A, B,...Ch. 5 - Prob. 5.5.11PCh. 5 - Prob. 5.5.12PCh. 5 - Prob. 5.5.13PCh. 5 - Prob. 5.5.14PCh. 5 - Prob. 5.5.15PCh. 5 - Prob. 5.5.16PCh. 5 - Prob. 5.6.1PCh. 5 - Prob. 5.6.2PCh. 5 - Prob. 5.6.3PCh. 5 - Prob. 5.6.4PCh. 5 - Compute the nominal shear strength of an M107.5 of...Ch. 5 - Compute the nominal shear strength of an M1211.8...Ch. 5 - Prob. 5.8.3PCh. 5 - Prob. 5.8.4PCh. 5 - Prob. 5.10.1PCh. 5 - Prob. 5.10.2PCh. 5 - Same as Problem 5.10-2, except that lateral...Ch. 5 - Prob. 5.10.4PCh. 5 - The given beam is laterally supported at the ends...Ch. 5 - Prob. 5.10.6PCh. 5 - Prob. 5.10.7PCh. 5 - Prob. 5.11.1PCh. 5 - Prob. 5.11.2PCh. 5 - Prob. 5.11.3PCh. 5 - Prob. 5.11.4PCh. 5 - Prob. 5.11.5PCh. 5 - Prob. 5.11.6PCh. 5 - Prob. 5.11.7PCh. 5 - Prob. 5.11.8PCh. 5 - Prob. 5.11.9PCh. 5 - Prob. 5.12.1PCh. 5 - Prob. 5.12.2PCh. 5 - Prob. 5.12.3PCh. 5 - Prob. 5.13.1PCh. 5 - Prob. 5.13.2PCh. 5 - Prob. 5.14.1PCh. 5 - Prob. 5.14.2PCh. 5 - Prob. 5.14.3PCh. 5 - Prob. 5.14.4PCh. 5 - Prob. 5.15.1PCh. 5 - Prob. 5.15.2PCh. 5 - Prob. 5.15.3PCh. 5 - Prob. 5.15.4PCh. 5 - Prob. 5.15.5PCh. 5 - Prob. 5.15.6PCh. 5 - Prob. 5.15.7PCh. 5 - Same as Problem 5.15-7, except that the sag rods...
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- The given girder has beams framing into it at the ends and at every L/3 point. The beam carries a service live load of 20 kips as shown and superimposed uniformly distributed service dead load of 10 kip/ft. Select the lightest A992 W-section that can carry the load. Do not check for deflection. P, = 20 kips LL PLL W. = 10 kip/ft DL = 20 ft WDL L/3 BEAMS FRAMING INTO GIRDER Larrow_forwardSITUATION 1 Determine (approximately) the force in each member of the truss. Assume the diagonals can support either a tensile or a compressíve force and assuming that the díagonals cannot support a compressíve force. A. Use Method 2 7 k 14 k 14 k 7 k Н F E oo 2 k 380 6 ft A D В C 8 ft 8 ft 8 ft B. Use Method 1 50 kN 40 kN 20 kN E D 3 m B 3 m 3 marrow_forwardTASK 3 250 180 14 I 30 24 Weld 450 A compound girder consists of a steel joist with steel plates welded onto each flange as shown. If the ends are simply supported and the effective span is 10 m, what is the maximum UDL which can be supported by the girder? [kN/m] Allowable longitudinal stress in plates = 110 MN/m² Allowable load in shear for each weld = 60 kN/m Allowable shearing stress in web of girder = 75 MN/m² Note: 1.0 MN/m² = 1.0 N/mm² 50arrow_forward
- Problem 1. A W30 x 116 beam has the top flange restrained against lateral displacement and rotation and has an unstiffened web. A point load is applied to the top flange at 2m. From the left support. The beam spans 12 m. Use A36 steel with yield strength of Fy = 248 Mpa. a. Compute the maximum value of point loadthat may be applied without web yieldingoccurring. Properties of W30 x 116d = 762 mmK = 41.28 mmbf = 266.7 mmtf = 21.59 mmtw = 14.33 mmarrow_forwardA built up column section is composed of 2 C 310 x 45 and2 plates b x 12 mm as shown in Figure ST – 169. The column has a height of8 m and both ends are hinges. Use Fy = 290 MPa. 1. Find the value of b so that the section is equally strong in both axes?2. Compute the value of the allowable compressive load for ASD.3. Compute the value of the design strength for LRFD.arrow_forwardSafe Support Spacing and S-1-bd Table below shows formulas for shear, bending moment and deflection for three-span continuous uniform load beam. R₁ = R₁ = 0.4wl R₁ = R₁ = 1.1wl V V Vmax=0.6wl Vdes = 0.6wl-w M M w(² Mmax= 10 A AMEE we Amax 145E'I If the bending and shear stress equation, and allowable deflection values are given as follow: • fb = M/S • fv = 3V/2bd • A = 1/16" a- Calculate safe support spacing for this beam (express the safe support spacing as a function of several variable). b- Express the equations for section modulus, moment of inertia and bd. Three-span, continuous, uniform l | = -w (d+ 12 )arrow_forward
- Assignment 5.2 -Steel Beam Analysis P-20 kips P-? kips W 24 x 76 A992 Steel The beam carries the following service dead load and live load 10h 20t P=20 kips P=? kips 30h Determine the maximum Lateral support is provided at both ends and at the load points service live load that the beam can carry, if the weight of the beam is neglected.arrow_forwardProblem 1. A W30 x 116 beam hasthe top flange restrained againstlateral displacement and rotationand has an unstiffened web. A pointload is applied to the top flange at2m. From the left support. The beamspans 12 m. Use A36 steel with yieldstrength of Fy = 248 Mpa. a. Compute the maximum value of point loadthat may be applied without web yieldingoccurring. b. Compute the maximum value of point loadthat may be applied without web cripplingoccurring. Properties of W30 x 116d = 762 mmK = 41.28 mmbf = 266.7 mmtf = 21.59 mmtw = 14.33 mmarrow_forwardQ3: For the beam shown below, find the number of a p20 bar required to resist the applied load. fY=420 MPa, f'c=28. PD = 16KN, PL=28KN. Do all the required checks. All concrete covers are 40 mm, the stirrups bar dimeter is 10 mm. Neglect the beam self-weight. Draw the final section. P 400 mm 4m 8m 60 mm 275arrow_forward
- Problem 1. A W30 x 116 beams has the top flange restrained against lateral displacement and rotation and has an unstiffened web. A point load is applied to the top flange at 2m. From the left support. The beam spans 12 m. Use A36 steel with yield strength of Fy = 248 Mpa. b. Compute the maximum value of point load that may be applied without web crippling occurring. d = 762 mm; K = 41.28 mm; bf = 266.7 mm; tf = 21.59 mm; tw = 14.33 mmarrow_forwardA 12 x 65 section (Fy = 345 MPa, E =200000MPa) is used as a beam which has full lateral bracings. a) What is the LRFD flexural design strength ØMn of the beam in kN.m? b) What safe live load w (N/m) can be applied on the beam loaded as shown in Figure 3? Beam weight is neglected. Properties of W 12 x 65 d = 307.55 mm tf = 15.37 mm bf 304.5 mm tw = 9.91 mm Sx 1440.423 x 10³ mm³ Zx 1586.268 x10³ mm³ h=T=241.3 mmarrow_forward1. An unsymmetrical flexural member consists of a 70 × 600 topflange, a 70 x 400 bottom flange, and a 12 × 180 web.a, Determine the Section Modulus.b. Determine the distance from the top of the shape to the horizontalplastic neutral axis.c. If A572 Grade 50 steel is used, what is the plastic moment MPy forthe horizontal plastic neutral axis?arrow_forward
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