Genetics: From Genes to Genomes
6th Edition
ISBN: 9781259700903
Author: Leland Hartwell Dr., Michael L. Goldberg Professor Dr., Janice Fischer, Leroy Hood Dr.
Publisher: McGraw-Hill Education
expand_more
expand_more
format_list_bulleted
Concept explainers
Textbook Question
Chapter 5, Problem 47P
A single yeast cell placed on a solid agar will divide mitotically to produce a colony of about 10 cells. A haploid yeast cell that has a mutation in the ade2 gene will produce a red colony; an ade2+ colony will be white. Some of the colonies formed from diploid yeast cells with a genotype of ade2+ / ade2− will contain sectors of red within a white colony.
a. | How would you explain these sectors? |
b. | Although the white colonies are roughly the same size, the red sectors within |
some of the white colonies vary markedly in size. Why? Do you expect the | |
majority of the red sectors to be relatively large or relatively small? |
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
You are studying a new fungus, G. lucasus, and are interested the molecules that control the cell cycle of this new organism. You make some mutant cells and find an intriguing mutant that
has two mutations - one in the force gene and one in the darkside gene.
a. You perform propidium-iodide cell cycle analysis by flow cytometry on wild-type and the double mutant cells and your results are below. During what stage(s) of the cell cycle are the
double mutant cells arresting their growth? Please briefly explain your answer.
# of cells
Wild-Type Cells
In
180 kDa
110 kDa
80 kDa
b. In studying the gene products of the force and darkside genes, you determine that the force gene produces a polypeptide of 80 kDa, and the darkside gene produces a polypeptide of 42
kDa. You collect lysates from wild-type cells in G₁, S, or G₂/M phases of the cell cycle and perform a Western blot (immunoblot) with either an antibody against force or an antibody against
darkside ... only you forget to label your…
Using the data below for Allium cepa, express the total number of cells in mitosis as a percentage of the total number of cells in the field of view for Field 1. This is the
mitotic index.
Give your answer as a whole number (i.e. no decimals) and without any units.
Total number
of cells in
Number of cells in:
A.cepa root tip
field of view
M
A
Field 1
181
16
9
4
147
112
Field 2
12
7
6
Field 3
11
9
You have identified five genes in S. cerevisiae that are induced when the yeast are grown in a high-salt (NaCl) medium. To study the potential roles of these genes in acclimation to the growth in high-salt conditions, you wish to examine the phenotypes of loss- and gain-of-function alleles of each. How will you do this?
Chapter 5 Solutions
Genetics: From Genes to Genomes
Ch. 5 - Choose the phrase from the right column that best...Ch. 5 - a. A Drosophila male from a true-breeding stock...Ch. 5 - Prob. 3PCh. 5 - The Punnett square in Fig. 5.4 shows how Mendels...Ch. 5 - In mice, the dominant allele Gs of the X-linked...Ch. 5 - In Drosophila, males from a true-breeding stock...Ch. 5 - If the a and b loci are 20 m.u. apart in humans...Ch. 5 - CCDD and ccdd individuals were crossed to each...Ch. 5 - In mice, the autosomal locus coding for the...Ch. 5 - In a particular human family, John and his mother...
Ch. 5 - Albino rabbits lacking pigment are homozygous for...Ch. 5 - In corn, the allele A allows the deposition of...Ch. 5 - If the a and b loci are 40 cM apart and an AA BB...Ch. 5 - Write the number of different kinds of phenotypes,...Ch. 5 - A DNA variant has been found linked to a rare...Ch. 5 - Figure 5.7a shows chromosomes during prophase of...Ch. 5 - Figure 5.7b shows bivalents in mouse primary...Ch. 5 - Cinnabar eyes cn and reduced bristles rd are...Ch. 5 - In Drosophila, the autosomal recessive dp allele...Ch. 5 - From a series of two-point crosses, the following...Ch. 5 - Map distances were determined for four different...Ch. 5 - In the tubular flowers of foxgloves, wild-type...Ch. 5 - In Drosophila, the recessive allele mb of one gene...Ch. 5 - A snapdragon with pink petals, black anthers, and...Ch. 5 - In Drosophila, three autosomal genes have the...Ch. 5 - Drosophila females heterozygous for each of three...Ch. 5 - Male Drosophila expressing the autosomal recessive...Ch. 5 - a. In Drosophila, crosses between F1 heterozygotes...Ch. 5 - A true-breeding strain of Virginia tobacco has...Ch. 5 - Prob. 30PCh. 5 - The following list of four Drosophila mutations...Ch. 5 - Do the data that Mendel obtained fit his...Ch. 5 - Two genes control color in corn snakes as follows:...Ch. 5 - A mouse from a true-breeding population with...Ch. 5 - Neurospora of genotype a c are crossed with...Ch. 5 - A cross was performed between one haploid strain...Ch. 5 - Prob. 40PCh. 5 - Prob. 41PCh. 5 - Indicate the percentage of tetrads that would have...Ch. 5 - Prob. 43PCh. 5 - This problem leads you through the derivation of a...Ch. 5 - a. In ordered tetrad analysis, what is the maximum...Ch. 5 - Prob. 46PCh. 5 - A single yeast cell placed on a solid agar will...Ch. 5 - Figure 5.29 shows mitotic recombination leading to...Ch. 5 - A diploid strain of yeast has a wild-type...Ch. 5 - In Drosophila, the yellow y gene is near the...Ch. 5 - Neurofibromas are tumors of the skin that can...Ch. 5 - Two important methods for understanding the...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- The figure below shows the life cycle of the fungus Neurospora. The adult stage of the Neurospora is a multicellular haploid: a. Between which two stages of the Neurospora life cycle do most mitotic cell divisions occur? b. Neurospora has an arginine amino acid synthesis pathway shown below: Suppose I have a neurospora strain that has a mutation such that it will not grow unless I supplement the media (food) with arginine (but not with citrulline or ornithine). What gene is mutated? Explain your reasoning. c. Suppose I take the strain above that only grows with arginine supplements and cross it to a different mutant Neurospora strain that grows with arginine and citrulline supplements but not ornithine supplements. Assming genes A, B and C are unlinked and there is only one mutation per strain: i) What percentage of the progeny will grow on ornithine? ii) What percentage on citrulline? iii) What percentage on arginine? Show your work for i), ii) and iii). [Can be answered in less…arrow_forwardIndicate the percentage of tetrads that would have 0,1, 2, 3, or 4 viable spores after Saccharomycescerevisiae a / α diploids of the following genotypesare sporulated:a. A true-breeding wild-type strain (with no mutations in any gene essential for viability).b. A strain heterozygous for a null (completely inactivating) mutation in a single essential gene.For the remaining parts of this problem, considercrosses between yeast strains of the form a × b, wherea and b are both temperature-sensitive mutations indifferent essential genes. The cross is conducted under permissive (low-temperature) conditions. Indicatethe percentage of tetrads that would have 0, 1, 2, 3, or4 viable spores subsequently measured under restrictive (high-temperature) conditions.c. a and b are unlinked, and both are 0 m.u. from thecentromere.d. a and b are unlinked; a is 0 m.u. from the centromere, while b is 10 m.u. from the centromere.e. a and b are 0 m.u. apart.f. a and b are 10 m.u. apart. Assume all…arrow_forwardFor a haploid fungus, the starting point in the biosynthesis of the amino acid arginine is Compound X, which is always present in and absorbed from the environment. The arginine biosynthetic pathway is: Enzyme A Enzyme B Enzyme Ç Compound X It is know that genes encoding enzymes A and C are on two different chromosomes. Compound Y Compound Z- Arginine A mutant strain of genotype a (lacking only enzyme A) is crossed to a mutant strain of genotype c (lacking only enzyme C) to generate a diploid strain. Sporulation (i.e. meiosis) is subsequently induced in the resulting diploid strain. What proportion of the spores (haploids formed by sporulation) is expected to grow on medium without arginine but supplemented with Compound Y? O 100% 50% 0% 25%arrow_forward
- To identify genes controlling the cell cycle in budding yeast, a genetic screen was carried out. In this screen, haploid yeast cells were exposed to a DNA damaging agent to introduce random mutations in the genome. By culturing cells at an elevated temperature (e.g. 37 degrees), where many mutated genes lose their function, scientists identified yeast mutants that showed growth defects and arrest at specific stages of the cell cycle (e.g. in mitosis with large buds). In this screen, mutants of the cyclin-dependent kinase were identified, but not mutants of cyclins. Explain the reason for this outcome.arrow_forwardFor fruit flies, N=4 and 2N=8 a. Sketch a dividing fruit fly cell which is in prophase I. b. Sketch a dividing fruit fly cell which is in metaphase of mitosis. A 35 year old man developed increasing pain in his left thigh and a marked limp, over 3 weeks. Five years he had undergone a nephrectomy for a renal carcinoma. An isotope showed metastasis in his right lateral ribs and left femur and he had been taking sunitinib. Assuming you are the attending physician, what is the most appropriate next step in his management?arrow_forwardUsing individual data for Allium cepa, express the number of cells in each of the different stages of mitosis as a percentage of the total number of cells in mitosis, and obtain the average across the three fields of view Enter the value for prophase as a whole number (no decimals or units). Total number of cells in Number of cells in: A.cepa root tip field of view P M T Field 1 181 16 4 Field 2 7 5 147 12 8. Field 3 112 11arrow_forward
- You are working with two different yeast cultures to study their genetics. But, you are not sure what the mating type of either of the yeast cultures is. (As a reminder, yeast mating types are either a or alpha). As a test, you mix the two cultures together and then observe them under a microscope. If this is the image that you see, what can you conclude about the mating types of the yeast? Explain your answer, including what type of cell morphology you see on this microscope slide.arrow_forwardA line of mouse cells is grown for many generations in a medium with 15N. Cells in G1 are then switched to a new medium that contains 14N. Draw a pair of homologous chromosomes from these cells at the following stages, showing the two strands of DNA molecules found in the chromosomes. Use different colors to represent strands with 14N and 15N. Q. Cells in anaphase of mitosis, after switching to medium with 14Narrow_forwardA cross was performed between a yeast strain that requires methionine and lysine for growth (met− lys−)and another yeast strain, which is met+ lys+. One hundred asci were dissected, and colonies were grownfrom the four spores in each ascus. Cells from thesecolonies were tested for their ability to grow on petriplates containing either minimal medium (min), min+ lysine (lys), min + methionine (met), or min + lys+ met. The asci could be divided into two groupsbased on this analysis:Group 1: In 89 asci, cells from two of the four spore colonies couldgrow on all four kinds of media, while the other two spore coloniescould grow only on min + lys + met.Group 2: In 11 asci, cells from one of the four spore colonies couldgrow on all four kinds of petri plates. Cells from a second one ofthe four spore colonies could grow only on min + lys plates andon min + lys + met plates. Cells from a third of the four sporecolonies could only grow on min + met plates and on min + lys+ met. Cells from the…arrow_forward
- In the experiment of cell fusion, when tumor cells were fused with normal cells, the initially formed tetraploid cells (or subsequently arising sub-tetraploid cells) were discovered to have lost the ability to form tumors. What is the explanation for this observation?arrow_forwardIn a haploid yeast strain, eight recessive mutationswere found that resulted in a requirement for theamino acid lysine. All the mutations were found to revert at a frequency of about 1 × 10−6 except mutations5 and 6, which did not revert. Matings were madebetween a and α cells carrying these mutations. Theability of the resultant diploid strains to grow onminimal medium in the absence of lysine is shown inthe following chart (+ means growth and − means nogrowth.)1 2 3 4 5 6 7 81 − + + + + − + −2 + − + + + + + +3 + + − − − − − +4 + + − − − − − +5 + + − − − − − +6 − + − − − − − −7 + + − − − − − +8 − + + + + − + −a. How many complementation groups were revealedby these data? Which point mutations are foundwithin which complementation groups?The same diploid strains are now induced to undergosporulation. The vast majority of resultant spores areauxotrophic; that is, they cannot form colonies whenplated on minimal medium (without lysine). However,particular diploids can produce rare spores…arrow_forwardIn a tissue engineering experiment, stem cells are grown in a circular dish (diameter = 3 cm) with a thin layer of cell culture media covering the cells. It is expected that these cells will differentiate when exposed a new differentiation factor (small molecule) at a surface concentration of 50 ng/cm? During the experiment, 1 ug of the factor is placed at the center of the dish. Assume the diffusivity of the factor in cell culture media is 1 x 10^-5 cm^2/s. A. How long does it take before the cells 1 cm from the center of the dish begin to differentiate? B. Do you expect the cells at the edge of the dish differentiate? Justify your answer with calculations.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Human Anatomy & Physiology (11th Edition)BiologyISBN:9780134580999Author:Elaine N. Marieb, Katja N. HoehnPublisher:PEARSONBiology 2eBiologyISBN:9781947172517Author:Matthew Douglas, Jung Choi, Mary Ann ClarkPublisher:OpenStaxAnatomy & PhysiologyBiologyISBN:9781259398629Author:McKinley, Michael P., O'loughlin, Valerie Dean, Bidle, Theresa StouterPublisher:Mcgraw Hill Education,
- Molecular Biology of the Cell (Sixth Edition)BiologyISBN:9780815344322Author:Bruce Alberts, Alexander D. Johnson, Julian Lewis, David Morgan, Martin Raff, Keith Roberts, Peter WalterPublisher:W. W. Norton & CompanyLaboratory Manual For Human Anatomy & PhysiologyBiologyISBN:9781260159363Author:Martin, Terry R., Prentice-craver, CynthiaPublisher:McGraw-Hill Publishing Co.Inquiry Into Life (16th Edition)BiologyISBN:9781260231700Author:Sylvia S. Mader, Michael WindelspechtPublisher:McGraw Hill Education
Human Anatomy & Physiology (11th Edition)
Biology
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:PEARSON
Biology 2e
Biology
ISBN:9781947172517
Author:Matthew Douglas, Jung Choi, Mary Ann Clark
Publisher:OpenStax
Anatomy & Physiology
Biology
ISBN:9781259398629
Author:McKinley, Michael P., O'loughlin, Valerie Dean, Bidle, Theresa Stouter
Publisher:Mcgraw Hill Education,
Molecular Biology of the Cell (Sixth Edition)
Biology
ISBN:9780815344322
Author:Bruce Alberts, Alexander D. Johnson, Julian Lewis, David Morgan, Martin Raff, Keith Roberts, Peter Walter
Publisher:W. W. Norton & Company
Laboratory Manual For Human Anatomy & Physiology
Biology
ISBN:9781260159363
Author:Martin, Terry R., Prentice-craver, Cynthia
Publisher:McGraw-Hill Publishing Co.
Inquiry Into Life (16th Edition)
Biology
ISBN:9781260231700
Author:Sylvia S. Mader, Michael Windelspecht
Publisher:McGraw Hill Education
genetic recombination strategies of bacteria CONJUGATION, TRANSDUCTION AND TRANSFORMATION; Author: Scientist Cindy;https://www.youtube.com/watch?v=_Va8FZJEl9A;License: Standard youtube license