a. To determine: The conclusion that can be drawn by the results obtained from mating mutant strains with wild-type strains of Neurospora . Introduction: In Neurospora , after meiosis, the four meiotic products undergo subsequent mitosis to produce eight spores in the ascus.

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Answer 1

Question

Chapter 5, Problem 46P

Summary Introduction

a.

To determine:

The conclusion that can be drawn by the results obtained from mating mutant strains with wild-type strains of Neurospora.

Introduction:

In Neurospora, after meiosis, the four meiotic products undergo subsequent mitosis to produce eight spores in the ascus.

Summary Introduction

b.

To determine:

The conclusions that can be drawn by the results obtained from mating mutant strains.

Introduction:

Assume that the three mutant strains are referred to as trp1, trp2, and trp3. In each haploid strain of Neurospora, one mutant trp^- phenotype results from one mutant gene.

Summary Introduction

c.

To determine:

The number of PD, NPD, and T out of 100 octads.

Introduction:

The tetrad that has the parental configuration of alleles is known as parental ditype (PD). Nonparental ditype (NPD) contains four recombinant spores, two of each type. Tetratype (T) contains four different spores, two spores are recombinants, and two are parental.

Summary Introduction

d.

To draw:

The genetic map that can provide a suitable explaination for the given data.

Introduction:

The cross between trp1 and trp2 can be represented as follows:

trp1−trp2+×trp1+trp2−→trp1−trp1+trp2+trp2−.

Summary Introduction

e.

To determine:

The reason that the given case does not present the mating in the table as ordered octads.

Introduction:

First-division (MI) and second-division segregation pattern are the types of segregation pattern for each gene that can be seen by the ordered octads.

Summary Introduction

f.

To determine:

The reason that the distance between gene and centromere can be observed from crosses given in the table.

Introduction:

SCO (single crossover) refers to the meiosis that takes place with a single crossover between a particular gene pair.

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The figure below shows the life cycle of the fungus Neurospora. The adult stage of the Neurospora is a multicellular haploid. b) Neurospora has an arginine amino acid synthesis pathway shown below. Suppose I take the strain above that only grows with arginine supplements and cross it to a different mutant Neurospora strain that grows with arginine and citrulline supplements but not with ornithine supplements. Assuming gens A, B, and C are unlinked and there is only one mutation per stain: What percentage of the progeny will grow on ornithine? What percentage on citrulline? What percentage on arginine?

From a cross between e+ f+ g+ and e− f − g− strains ofNeurospora, recombination between these linkedgenes resulted in a few octads containing the followingordered set of spores:e+ f+ g+e+ f+ g+e+ f − g+e+ f − g+e− f − g−e− f − g−e− f − g−e− f − g−a. Where was recombination initiated?b. Did crossing-over occur between genes e and g?Explain.c. Why do you end up with 2 f+ : 6 f − but 4 e+: 4 e−and 4g+: 4g−?d. Could you characterize these unusual octads as MIor MII for any of the three genes involved?Explain.

Baker's yeast, Saccharomyces cerevisiae, is a single-celled, diploid fungus (which is, of course, a eukaryote, that is capable of both meiosis and sexual reproduction). Wild type yeast can normally grow on solid or liquid minimal medium; you isolate three mutant strains which are no longer capable of growing on minimal medium alone, however, they can grow on medium supplemented with adenine. All three yeast strains are homozygous for the underlying alleles. When you cross mutant strain 1 and mutant strain 2, the offspring cannot grow on minimal medium alone and require adenine supplementation; when you cross mutant strain 1 and mutant strain 3, the offspring can grow on minimal medium alone and do not require adenine. After crossing the F1 generation of the cross between mutant strains 1 and 3, you count and determine the phenotypes of 1,000 colonies (here a colony is equivalent to an individual): 563 colonies that can grow on minimal medium alone; 437 colonies that require adenine…

Answer 2

Question

Chapter 5, Problem 46P

Summary Introduction

a.

To determine:

The conclusion that can be drawn by the results obtained from mating mutant strains with wild-type strains of Neurospora.

Introduction:

In Neurospora, after meiosis, the four meiotic products undergo subsequent mitosis to produce eight spores in the ascus.

Summary Introduction

b.

To determine:

The conclusions that can be drawn by the results obtained from mating mutant strains.

Introduction:

Assume that the three mutant strains are referred to as trp1, trp2, and trp3. In each haploid strain of Neurospora, one mutant trp^- phenotype results from one mutant gene.

Summary Introduction

c.

To determine:

The number of PD, NPD, and T out of 100 octads.

Introduction:

The tetrad that has the parental configuration of alleles is known as parental ditype (PD). Nonparental ditype (NPD) contains four recombinant spores, two of each type. Tetratype (T) contains four different spores, two spores are recombinants, and two are parental.

Summary Introduction

d.

To draw:

The genetic map that can provide a suitable explaination for the given data.

Introduction:

The cross between trp1 and trp2 can be represented as follows:

trp1−trp2+×trp1+trp2−→trp1−trp1+trp2+trp2−.

Summary Introduction

e.

To determine:

The reason that the given case does not present the mating in the table as ordered octads.

Introduction:

First-division (MI) and second-division segregation pattern are the types of segregation pattern for each gene that can be seen by the ordered octads.

Summary Introduction

f.

To determine:

The reason that the distance between gene and centromere can be observed from crosses given in the table.

Introduction:

SCO (single crossover) refers to the meiosis that takes place with a single crossover between a particular gene pair.

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Answer 3

Question

Chapter 5, Problem 46P

Summary Introduction

a.

To determine:

The conclusion that can be drawn by the results obtained from mating mutant strains with wild-type strains of Neurospora.

Introduction:

In Neurospora, after meiosis, the four meiotic products undergo subsequent mitosis to produce eight spores in the ascus.

Summary Introduction

b.

To determine:

The conclusions that can be drawn by the results obtained from mating mutant strains.

Introduction:

Assume that the three mutant strains are referred to as trp1, trp2, and trp3. In each haploid strain of Neurospora, one mutant trp^- phenotype results from one mutant gene.

Summary Introduction

c.

To determine:

The number of PD, NPD, and T out of 100 octads.

Introduction:

The tetrad that has the parental configuration of alleles is known as parental ditype (PD). Nonparental ditype (NPD) contains four recombinant spores, two of each type. Tetratype (T) contains four different spores, two spores are recombinants, and two are parental.

Summary Introduction

d.

To draw:

The genetic map that can provide a suitable explaination for the given data.

Introduction:

The cross between trp1 and trp2 can be represented as follows:

trp1−trp2+×trp1+trp2−→trp1−trp1+trp2+trp2−.

Summary Introduction

e.

To determine:

The reason that the given case does not present the mating in the table as ordered octads.

Introduction:

First-division (MI) and second-division segregation pattern are the types of segregation pattern for each gene that can be seen by the ordered octads.

Summary Introduction

f.

To determine:

The reason that the distance between gene and centromere can be observed from crosses given in the table.

Introduction:

SCO (single crossover) refers to the meiosis that takes place with a single crossover between a particular gene pair.

Expert Solution & Answer

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See solution

Answer 4

Question

Chapter 5, Problem 46P

Summary Introduction

a.

To determine:

The conclusion that can be drawn by the results obtained from mating mutant strains with wild-type strains of Neurospora.

Introduction:

In Neurospora, after meiosis, the four meiotic products undergo subsequent mitosis to produce eight spores in the ascus.

Summary Introduction

b.

To determine:

The conclusions that can be drawn by the results obtained from mating mutant strains.

Introduction:

Assume that the three mutant strains are referred to as trp1, trp2, and trp3. In each haploid strain of Neurospora, one mutant trp^- phenotype results from one mutant gene.

Summary Introduction

c.

To determine:

The number of PD, NPD, and T out of 100 octads.

Introduction:

The tetrad that has the parental configuration of alleles is known as parental ditype (PD). Nonparental ditype (NPD) contains four recombinant spores, two of each type. Tetratype (T) contains four different spores, two spores are recombinants, and two are parental.

Summary Introduction

d.

To draw:

The genetic map that can provide a suitable explaination for the given data.

Introduction:

The cross between trp1 and trp2 can be represented as follows:

trp1−trp2+×trp1+trp2−→trp1−trp1+trp2+trp2−.

Summary Introduction

e.

To determine:

The reason that the given case does not present the mating in the table as ordered octads.

Introduction:

First-division (MI) and second-division segregation pattern are the types of segregation pattern for each gene that can be seen by the ordered octads.

Summary Introduction

f.

To determine:

The reason that the distance between gene and centromere can be observed from crosses given in the table.

Introduction:

SCO (single crossover) refers to the meiosis that takes place with a single crossover between a particular gene pair.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 5

Chapter 5, Problem 46P

Summary Introduction

a.

To determine:

The conclusion that can be drawn by the results obtained from mating mutant strains with wild-type strains of Neurospora.

Introduction:

In Neurospora, after meiosis, the four meiotic products undergo subsequent mitosis to produce eight spores in the ascus.

Summary Introduction

b.

To determine:

The conclusions that can be drawn by the results obtained from mating mutant strains.

Introduction:

Assume that the three mutant strains are referred to as trp1, trp2, and trp3. In each haploid strain of Neurospora, one mutant trp^- phenotype results from one mutant gene.

Summary Introduction

c.

To determine:

The number of PD, NPD, and T out of 100 octads.

Introduction:

The tetrad that has the parental configuration of alleles is known as parental ditype (PD). Nonparental ditype (NPD) contains four recombinant spores, two of each type. Tetratype (T) contains four different spores, two spores are recombinants, and two are parental.

Summary Introduction

d.

To draw:

The genetic map that can provide a suitable explaination for the given data.

Introduction:

The cross between trp1 and trp2 can be represented as follows:

trp1−trp2+×trp1+trp2−→trp1−trp1+trp2+trp2−.

Summary Introduction

e.

To determine:

The reason that the given case does not present the mating in the table as ordered octads.

Introduction:

First-division (MI) and second-division segregation pattern are the types of segregation pattern for each gene that can be seen by the ordered octads.

Summary Introduction

f.

To determine:

The reason that the distance between gene and centromere can be observed from crosses given in the table.

Introduction:

SCO (single crossover) refers to the meiosis that takes place with a single crossover between a particular gene pair.

Answer 6

Chapter 5, Problem 46P

Summary Introduction

a.

To determine:

The conclusion that can be drawn by the results obtained from mating mutant strains with wild-type strains of Neurospora.

Introduction:

In Neurospora, after meiosis, the four meiotic products undergo subsequent mitosis to produce eight spores in the ascus.

Answer 7

Chapter 5, Problem 46P

Summary Introduction

a.

To determine:

The conclusion that can be drawn by the results obtained from mating mutant strains with wild-type strains of Neurospora.

Introduction:

In Neurospora, after meiosis, the four meiotic products undergo subsequent mitosis to produce eight spores in the ascus.

Answer 8

Summary Introduction

b.

To determine:

The conclusions that can be drawn by the results obtained from mating mutant strains.

Introduction:

Assume that the three mutant strains are referred to as trp1, trp2, and trp3. In each haploid strain of Neurospora, one mutant trp^- phenotype results from one mutant gene.

Answer 9

Summary Introduction

b.

To determine:

The conclusions that can be drawn by the results obtained from mating mutant strains.

Introduction:

Assume that the three mutant strains are referred to as trp1, trp2, and trp3. In each haploid strain of Neurospora, one mutant trp^- phenotype results from one mutant gene.

Answer 10

Summary Introduction

c.

To determine:

The number of PD, NPD, and T out of 100 octads.

Introduction:

The tetrad that has the parental configuration of alleles is known as parental ditype (PD). Nonparental ditype (NPD) contains four recombinant spores, two of each type. Tetratype (T) contains four different spores, two spores are recombinants, and two are parental.

Answer 11

Summary Introduction

c.

To determine:

The number of PD, NPD, and T out of 100 octads.

Introduction:

The tetrad that has the parental configuration of alleles is known as parental ditype (PD). Nonparental ditype (NPD) contains four recombinant spores, two of each type. Tetratype (T) contains four different spores, two spores are recombinants, and two are parental.

Answer 12

Summary Introduction

d.

To draw:

The genetic map that can provide a suitable explaination for the given data.

Introduction:

The cross between trp1 and trp2 can be represented as follows:

trp1−trp2+×trp1+trp2−→trp1−trp1+trp2+trp2−.

Answer 13

Summary Introduction

d.

To draw:

The genetic map that can provide a suitable explaination for the given data.

Introduction:

The cross between trp1 and trp2 can be represented as follows:

trp1−trp2+×trp1+trp2−→trp1−trp1+trp2+trp2−.

Answer 14

Summary Introduction

e.

To determine:

The reason that the given case does not present the mating in the table as ordered octads.

Introduction:

First-division (MI) and second-division segregation pattern are the types of segregation pattern for each gene that can be seen by the ordered octads.

Answer 15

Summary Introduction

e.

To determine:

The reason that the given case does not present the mating in the table as ordered octads.

Introduction:

First-division (MI) and second-division segregation pattern are the types of segregation pattern for each gene that can be seen by the ordered octads.

Answer 16

Summary Introduction

f.

To determine:

The reason that the distance between gene and centromere can be observed from crosses given in the table.

Introduction:

SCO (single crossover) refers to the meiosis that takes place with a single crossover between a particular gene pair.

Answer 17

Summary Introduction

f.

To determine:

The reason that the distance between gene and centromere can be observed from crosses given in the table.

Introduction:

SCO (single crossover) refers to the meiosis that takes place with a single crossover between a particular gene pair.

Answer 18

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Answer 19

Expert Solution & Answer

Answer 20

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Answer 21

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a. To determine: The conclusion that can be drawn by the results obtained from mating mutant strains with wild-type strains of Neurospora . Introduction: In Neurospora , after meiosis, the four meiotic products undergo subsequent mitosis to produce eight spores in the ascus.

Solution Summary: The author analyzes the results obtained from mating mutant strains with wild-type Neurospora. One mutant gene is responsible for trp - phenotype.

Concept explainers

Videos

a.

To determine:

The conclusion that can be drawn by the results obtained from mating mutant strains with wild-type strains of Neurospora.

Introduction:

In Neurospora, after meiosis, the four meiotic products undergo subsequent mitosis to produce eight spores in the ascus.

b.

To determine:

The conclusions that can be drawn by the results obtained from mating mutant strains.

Introduction:

Assume that the three mutant strains are referred to as trp1, trp2, and trp3. In each haploid strain of Neurospora, one mutant trp^- phenotype results from one mutant gene.

d.

To draw:

The genetic map that can provide a suitable explaination for the given data.

Introduction:

The cross between trp1 and trp2 can be represented as follows:

trp1−trp2+×trp1+trp2−→trp1−trp1+trp2+trp2−.

e.

To determine:

The reason that the given case does not present the mating in the table as ordered octads.

Introduction:

First-division (MI) and second-division segregation pattern are the types of segregation pattern for each gene that can be seen by the ordered octads.

f.

To determine:

The reason that the distance between gene and centromere can be observed from crosses given in the table.

Introduction:

SCO (single crossover) refers to the meiosis that takes place with a single crossover between a particular gene pair.

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Chapter 5 Solutions

a. To determine: The conclusion that can be drawn by the results obtained from mating mutant strains with wild-type strains of Neurospora . Introduction: In Neurospora , after meiosis, the four meiotic products undergo subsequent mitosis to produce eight spores in the ascus.

Solution Summary: The author analyzes the results obtained from mating mutant strains with wild-type Neurospora. One mutant gene is responsible for trp - phenotype.

Concept explainers

Videos

a. To determine: The conclusion that can be drawn by the results obtained from mating mutant strains with wild-type strains of Neurospora. Introduction: In Neurospora, after meiosis, the four meiotic products undergo subsequent mitosis to produce eight spores in the ascus.

b. To determine: The conclusions that can be drawn by the results obtained from mating mutant strains. Introduction: Assume that the three mutant strains are referred to as trp1, trp2, and trp3. In each haploid strain of Neurospora, one mutant trp- phenotype results from one mutant gene.

d. To draw: The genetic map that can provide a suitable explaination for the given data. Introduction: The cross between trp1 and trp2 can be represented as follows: trp1−trp2+×trp1+trp2−→trp1−trp1+trp2+trp2−.

e. To determine: The reason that the given case does not present the mating in the table as ordered octads. Introduction: First-division (MI) and second-division segregation pattern are the types of segregation pattern for each gene that can be seen by the ordered octads.

f. To determine: The reason that the distance between gene and centromere can be observed from crosses given in the table. Introduction: SCO (single crossover) refers to the meiosis that takes place with a single crossover between a particular gene pair.

Want to see the full answer?

Chapter 5 Solutions

a.

To determine:

The conclusion that can be drawn by the results obtained from mating mutant strains with wild-type strains of Neurospora.

Introduction:

In Neurospora, after meiosis, the four meiotic products undergo subsequent mitosis to produce eight spores in the ascus.

b.

To determine:

The conclusions that can be drawn by the results obtained from mating mutant strains.

Introduction:

Assume that the three mutant strains are referred to as trp1, trp2, and trp3. In each haploid strain of Neurospora, one mutant trp^- phenotype results from one mutant gene.

d.

To draw:

The genetic map that can provide a suitable explaination for the given data.

Introduction:

The cross between trp1 and trp2 can be represented as follows:

trp1−trp2+×trp1+trp2−→trp1−trp1+trp2+trp2−.

e.

To determine:

The reason that the given case does not present the mating in the table as ordered octads.

Introduction:

First-division (MI) and second-division segregation pattern are the types of segregation pattern for each gene that can be seen by the ordered octads.

f.

To determine:

The reason that the distance between gene and centromere can be observed from crosses given in the table.

Introduction:

SCO (single crossover) refers to the meiosis that takes place with a single crossover between a particular gene pair.