Chemistry 2012 Student Edition (hard Cover) Grade 11
Chemistry 2012 Student Edition (hard Cover) Grade 11
12th Edition
ISBN: 9780132525763
Author: Prentice Hall
Publisher: Prentice Hall
Question
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Chapter 5, Problem 40A

(a)

Interpretation Introduction

Interpretation: The electron configuration for the element with atomic number 7 needs to be written.

Concept Introduction: The electron configuration explains the electron distribution in atomic orbitals. There is a standard notation to write an electron configuration. The atomic shell is written in a sequence with the number of electrons in superscript.

(a)

Expert Solution
Check Mark

Answer to Problem 40A

  1s22s22p3

Explanation of Solution

The given atomic number is 7. Since the atomic number is equal to the number of electrons, thus, the total number of electrons present in the atom will be 7. Now s , p, and d orbitals can maximum hold 2, 6, and 10 electrons; thus, the electron configuration of the element with atomic number 7 will be:

  1s22s22p3

(b)

Interpretation Introduction

Interpretation: The electron configuration for the element with atomic number 9 needs to be written.

Concept Introduction: The electron configuration explains the electron distribution in atomic orbitals. There is a standard notation to write an electron configuration. The atomic shell is written in a sequence with the number of electrons in superscript.

(b)

Expert Solution
Check Mark

Answer to Problem 40A

  1s22s22p5

Explanation of Solution

The given atomic number is 9. Since the atomic number is equal to the number of electrons, thus, the total number of electrons present in the atom will be 9. Now, s , p, and d orbitals can maximum hold 2, 6, and 10 electrons; thus, the electron configuration of the element with atomic number 9 will be:

  1s22s22p5

(c)

Interpretation Introduction

Interpretation: The electron configuration for the element with atomic number 12 needs to be written.

Concept Introduction: The electron configuration explains the electron distribution in atomic orbitals. There is a standard notation to write an electron configuration. The atomic shell is written in a sequence with the number of electrons in superscript.

(c)

Expert Solution
Check Mark

Answer to Problem 40A

  1s22s22p63s2

Explanation of Solution

The given atomic number is 12. Since the atomic number is equal to the number of electrons, thus, the total number of electrons present in the atom will be 12. Now, s , p, and d orbitals can maximum hold 2, 6, and 10 electrons; thus, the electron configuration of the element with atomic number 12 will be:

  1s22s22p63s2

(d)

Interpretation Introduction

Interpretation: The electron configuration for the element with atomic number 36 needs to be written.

Concept Introduction: The electron configuration explains the electron distribution in atomic orbitals. There is a standard notation to write an electron configuration. The atomic shell is written in a sequence with the number of electrons in superscript.

(d)

Expert Solution
Check Mark

Answer to Problem 40A

  1s22s22p63s23p64s23d104p6

Explanation of Solution

The given atomic number is 36. Since the atomic number is equal to the number of electrons, thus, the total number of electrons present in the atom will be 36. Now, s , p, and d orbitals can maximum hold 2, 6, and 10 electrons; thus, the electron configuration of the element with atomic number 36 will be:

  1s22s22p63s23p64s23d104p6

Here, 4s orbital is filled before 3d .

Chapter 5 Solutions

Chemistry 2012 Student Edition (hard Cover) Grade 11

Ch. 5.2 - Prob. 11LCCh. 5.2 - Prob. 12LCCh. 5.2 - Prob. 13LCCh. 5.2 - Prob. 14LCCh. 5.3 - Prob. 15SPCh. 5.3 - Prob. 16SPCh. 5.3 - Prob. 17SPCh. 5.3 - Prob. 18SPCh. 5.3 - Prob. 19LCCh. 5.3 - Prob. 20LCCh. 5.3 - Prob. 21LCCh. 5.3 - Prob. 22LCCh. 5.3 - Prob. 23LCCh. 5.3 - Prob. 24LCCh. 5.3 - Prob. 25LCCh. 5.3 - Prob. 26LCCh. 5 - Prob. 27ACh. 5 - Prob. 28ACh. 5 - Prob. 29ACh. 5 - Prob. 30ACh. 5 - Prob. 31ACh. 5 - Prob. 32ACh. 5 - Prob. 33ACh. 5 - Prob. 34ACh. 5 - Prob. 35ACh. 5 - Prob. 36ACh. 5 - Prob. 37ACh. 5 - Prob. 38ACh. 5 - Prob. 39ACh. 5 - Prob. 40ACh. 5 - Prob. 41ACh. 5 - Prob. 42ACh. 5 - Prob. 43ACh. 5 - Prob. 44ACh. 5 - Prob. 45ACh. 5 - Prob. 46ACh. 5 - Prob. 47ACh. 5 - Prob. 48ACh. 5 - Prob. 49ACh. 5 - Prob. 50ACh. 5 - Prob. 51ACh. 5 - Prob. 52ACh. 5 - Prob. 53ACh. 5 - Prob. 54ACh. 5 - Prob. 55ACh. 5 - Prob. 56ACh. 5 - Prob. 57ACh. 5 - Prob. 58ACh. 5 - Prob. 59ACh. 5 - Prob. 60ACh. 5 - Prob. 61ACh. 5 - Prob. 62ACh. 5 - Prob. 63ACh. 5 - Prob. 64ACh. 5 - Prob. 65ACh. 5 - Prob. 66ACh. 5 - Prob. 67ACh. 5 - Prob. 68ACh. 5 - Prob. 69ACh. 5 - Prob. 70ACh. 5 - Prob. 71ACh. 5 - Prob. 72ACh. 5 - Prob. 73ACh. 5 - Prob. 74ACh. 5 - Prob. 75ACh. 5 - Prob. 77ACh. 5 - Prob. 78ACh. 5 - Prob. 79ACh. 5 - Prob. 80ACh. 5 - Prob. 81ACh. 5 - Prob. 82ACh. 5 - Prob. 83ACh. 5 - Prob. 85ACh. 5 - Prob. 86ACh. 5 - Prob. 88ACh. 5 - Prob. 89ACh. 5 - Prob. 90ACh. 5 - Prob. 91ACh. 5 - Prob. 92ACh. 5 - Prob. 93ACh. 5 - Prob. 94ACh. 5 - Prob. 95ACh. 5 - Prob. 96ACh. 5 - Prob. 97ACh. 5 - Prob. 98ACh. 5 - Prob. 99ACh. 5 - Prob. 100ACh. 5 - Prob. 101ACh. 5 - Prob. 102ACh. 5 - Prob. 103ACh. 5 - Prob. 104ACh. 5 - Prob. 105ACh. 5 - Prob. 106ACh. 5 - Prob. 1STPCh. 5 - Prob. 2STPCh. 5 - Prob. 3STPCh. 5 - Prob. 4STPCh. 5 - Prob. 5STPCh. 5 - Prob. 6STPCh. 5 - Prob. 7STPCh. 5 - Prob. 8STPCh. 5 - Prob. 9STPCh. 5 - Prob. 10STPCh. 5 - Prob. 11STPCh. 5 - Prob. 12STPCh. 5 - Prob. 13STPCh. 5 - Prob. 14STPCh. 5 - Prob. 15STP
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