Interpretation: The invalid orbital designation needs to be identified.
Concept Introduction: Quantum numbers are defined as a set of numbers required to explain the position of an electron in an atom. The four quantum numbers are principal quantum number ( n ), azimuthal quantum number ( l ), magnetic quantum number ( m ), and spin quantum number (s). For any orbital of a known principal quantum number, the azimuthal quantum number is up to
Answer to Problem 37A
The correct answer is option (b) and option (c).
Explanation of Solution
Reason for correct option/s:
In option (b), the given orbital is 2d . Thus, the principal quantum number is 2. Now, there will be up to
Here, 0 indicates s orbital and 1 indicates p orbital. Since the d orbital is not possible for principal quantum number 2, the 2d orbital is an invalid designation.
In option (c), the given orbital is 3f . Thus, the principal quantum number is 3. Now, there will be up to
Here, 0 indicates s orbital, 1 indicates p orbital and 2 indicates d orbital. Since the f orbital is not possible for principal quantum number 3, the 3f orbital is an invalid designation.
Therefore, options (b) and (c) are correct.
Reason for incorrect option/s:
In option (a), the given orbital is 4s . Thus, the principal quantum number is 4. Now, there will be up to
Here, 0 indicates s orbital, 1 indicates p orbital, 2 indicates d orbital and 3 indicates f orbital. Thus, 4s orbital is a valid designation.
In option (d), the given orbital is 3p . Thus, the principal quantum number is 3. Now, there will be up to
Here, 0 indicates s orbital, 1 indicates p orbital and 2 indicates d orbital. Thus, 3p orbital is a valid designation.
Therefore, options (a) and (d) are incorrect.
Chapter 5 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
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