Stats: Modeling the World Nasta Edition Grades 9-12
Stats: Modeling the World Nasta Edition Grades 9-12
3rd Edition
ISBN: 9780131359581
Author: David E. Bock, Paul F. Velleman, Richard D. De Veaux
Publisher: PEARSON
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Chapter 4, Problem 22E

(a)

To determine

To Explain: the distribution.

(a)

Expert Solution
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Explanation of Solution

Given:

  Stats: Modeling the World Nasta Edition Grades 9-12, Chapter 4, Problem 22E , additional homework tip  1

By seeing the histogram, it is observed that the distribution is centred at about 290, with a standard deviation of about 10. The distribution looks normal (bell-shaped). The peak is at 290, and the standard spread looks to be about 10.

(b)

To determine

To find: the proportion of professional male golfers that is less than 280 yards.

(b)

Expert Solution
Check Mark

Answer to Problem 22E

15%

Explanation of Solution

Given:

  Stats: Modeling the World Nasta Edition Grades 9-12, Chapter 4, Problem 22E , additional homework tip  2

Calculation:

About 15%

Approximately 30 professional male golfers which is less than 280 yards therefore the proportion of professional male golfers drive on average less than 280 yard is

30 (20+5+3+1=29, take it 30 approximately.)

There are 202 golfers total. 30202=15% .

(c)

To determine

To Calculate: the mean on the basis of given histogram.

(c)

Expert Solution
Check Mark

Answer to Problem 22E

287.5

Explanation of Solution

Given:

  Stats: Modeling the World Nasta Edition Grades 9-12, Chapter 4, Problem 22E , additional homework tip  3

The mean is approximately 287.5

The data is largely normal (bell-shaped). The mean is about where the peak is lie.

(d)

To determine

To Explain: that expect the mean to be smaller, equal or larger than the median.

(d)

Expert Solution
Check Mark

Explanation of Solution

Given:

  Stats: Modeling the World Nasta Edition Grades 9-12, Chapter 4, Problem 22E , additional homework tip  4

The mean would be about equal to the median. The histogram appears to be normally distributed. The spread is equal approximately the mean in a perfectly normally distributed curve, the mean, median, and mode coincide

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