PRACTICE OF STATISTICS F/AP EXAM
PRACTICE OF STATISTICS F/AP EXAM
6th Edition
ISBN: 9781319113339
Author: Starnes
Publisher: MAC HIGHER
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Chapter 3, Problem T3.11SPT

(a)

To determine

To make a scatterplot of these data using age as the explanatory variable and describe what you see.

(a)

Expert Solution
Check Mark

Explanation of Solution

The scatterplot of the age on the horizontal axis and height on the vertical axis is as follows:

  PRACTICE OF STATISTICS F/AP EXAM, Chapter 3, Problem T3.11SPT

Thus, we have the direction is positive because the pattern in the scatterplot slopes upwards. And the form is linear because there is no strong curvature present in the scatterplot. The strength is strong because the points only deviate very slightly from the general pattern in the points. The unusual points appear to be one outlier because the leftmost point in the scatterplot lies far from the other points in the scatterplot.

(b)

To determine

To find the equation of the least squares regression line using your calculator.

(b)

Expert Solution
Check Mark

Answer to Problem T3.11SPT

  y^=71.95+0.3833x .

Explanation of Solution

Using calculator, press on STAT and then select 1 : Edit . and then enter the data of sugar in the list L1 and enter the data of calories in the list L2 .

Next, press on STAT select CALC and then select Linreg(a+bx) . Next we need to finish the command by entering L1L2 .

  Linreg(a+bx)L1L2

Finally, pressing on ENTER then gives us the following result:

  y=a+bxa=71.95b=0.3833r2=0.9888r=0.9944

This then implies the regression line as:

  y^=a+bxy^=71.95+0.3833x

Where x be age and y be height.

(c)

To determine

To calculate and interpret the residual for the point when Sarah was 48 months old.

(c)

Expert Solution
Check Mark

Answer to Problem T3.11SPT

Residual is 0.3484 .

Explanation of Solution

The regression line is:

  y^=71.95+0.3833x

Thus, the height of Sarah will be when Sarah was 48 months old:

  y^=71.95+0.3833x=71.95+0.3833(48)=90.3484

The residual will be as:

  Residual=yy^=9090.3484=0.3484

This then implies that we overestimated the height of Sarah by 0.3484 cm, when making a prediction using the regression line.

(d)

To determine

To explain would you be confident using the equation from part (b) to predict Sarah’s height when she was 48 months old.

(d)

Expert Solution
Check Mark

Answer to Problem T3.11SPT

No, we are not.

Explanation of Solution

Since there are twelve months in a year then 40 years corresponds with

  40×12=480

The data contains ages from 36 months to 60 months. We then note that 480 months is not in the range of the ages, which implies that we would not be confident using the equation from part (b) to predict Sarah’s height when Sarah was 48 months old because we would be using extrapolation.

Chapter 3 Solutions

PRACTICE OF STATISTICS F/AP EXAM

Ch. 3.1 - Prob. 11ECh. 3.1 - Prob. 12ECh. 3.1 - Prob. 13ECh. 3.1 - Prob. 14ECh. 3.1 - Prob. 15ECh. 3.1 - Prob. 16ECh. 3.1 - Prob. 17ECh. 3.1 - Prob. 18ECh. 3.1 - Prob. 19ECh. 3.1 - Prob. 20ECh. 3.1 - Prob. 21ECh. 3.1 - Prob. 22ECh. 3.1 - Prob. 23ECh. 3.1 - Prob. 24ECh. 3.1 - Prob. 25ECh. 3.1 - Prob. 26ECh. 3.1 - Prob. 27ECh. 3.1 - Prob. 28ECh. 3.1 - Prob. 29ECh. 3.1 - Prob. 30ECh. 3.1 - Prob. 31ECh. 3.1 - Prob. 32ECh. 3.1 - Prob. 33ECh. 3.1 - Prob. 34ECh. 3.1 - Prob. 35ECh. 3.1 - Prob. 36ECh. 3.2 - Prob. 37ECh. 3.2 - Prob. 38ECh. 3.2 - Prob. 39ECh. 3.2 - Prob. 40ECh. 3.2 - Prob. 41ECh. 3.2 - Prob. 42ECh. 3.2 - Prob. 43ECh. 3.2 - Prob. 44ECh. 3.2 - Prob. 45ECh. 3.2 - Prob. 46ECh. 3.2 - Prob. 47ECh. 3.2 - Prob. 48ECh. 3.2 - Prob. 49ECh. 3.2 - Prob. 50ECh. 3.2 - Prob. 51ECh. 3.2 - Prob. 52ECh. 3.2 - Prob. 53ECh. 3.2 - Prob. 54ECh. 3.2 - Prob. 55ECh. 3.2 - Prob. 56ECh. 3.2 - Prob. 57ECh. 3.2 - Prob. 58ECh. 3.2 - Prob. 59ECh. 3.2 - Prob. 60ECh. 3.2 - Prob. 61ECh. 3.2 - Prob. 62ECh. 3.2 - Prob. 63ECh. 3.2 - Prob. 64ECh. 3.2 - Prob. 65ECh. 3.2 - Prob. 66ECh. 3.2 - Prob. 67ECh. 3.2 - Prob. 68ECh. 3.2 - Prob. 69ECh. 3.2 - Prob. 70ECh. 3.2 - Prob. 71ECh. 3.2 - Prob. 72ECh. 3.2 - Prob. 73ECh. 3.2 - Prob. 74ECh. 3.2 - Prob. 75ECh. 3.2 - Prob. 76ECh. 3.2 - Prob. 77ECh. 3.2 - Prob. 78ECh. 3.2 - Prob. 79ECh. 3.2 - Prob. 80ECh. 3 - Prob. R3.1RECh. 3 - Prob. R3.2RECh. 3 - Prob. R3.3RECh. 3 - Prob. R3.4RECh. 3 - Prob. R3.5RECh. 3 - Prob. R3.6RECh. 3 - Prob. T3.1SPTCh. 3 - Prob. T3.2SPTCh. 3 - Prob. T3.3SPTCh. 3 - Prob. T3.4SPTCh. 3 - Prob. T3.5SPTCh. 3 - Prob. T3.6SPTCh. 3 - Prob. T3.7SPTCh. 3 - Prob. T3.8SPTCh. 3 - Prob. T3.9SPTCh. 3 - Prob. T3.10SPTCh. 3 - Prob. T3.11SPTCh. 3 - Prob. T3.12SPTCh. 3 - Prob. T3.13SPT
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