PRIN.OF HIGHWAY ENGINEERING&TRAFFIC ANA.
7th Edition
ISBN: 9781119610526
Author: Mannering
Publisher: WILEY
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Chapter 3, Problem 62P
To determine
The elevation of the lowest point of the curve.
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A 1600-ft-long equal tangent sag vertical curve has the PVI at station 120+00 and elevation 1500 ft. The initial grade is -3.5% and the final grade is +6.5%.
determine the elevation of lowest point.
1525
1520
1518.20
1514
3.9 An equal-tangent crest curve connects a +2% initial
grade with a -1% final grade, and is designed for 55
mi/h. The station of the PVI is 233 + 40 with elevation
1203 ft. What is the elevation of the curve at station 234
+00?
a 400-ft equal tangent sag vertical curve has its PC t station 100 + 00 and elevation 500ft. The initial grade is -4.0% and the final grade is +2.5%. Determine the stationing of the lowest point.(take note that 1 station consists of 100 ft.)
Chapter 3 Solutions
PRIN.OF HIGHWAY ENGINEERING&TRAFFIC ANA.
Ch. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Prob. 3PCh. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 8PCh. 3 - Prob. 9PCh. 3 - Prob. 10P
Ch. 3 - Prob. 11PCh. 3 - Prob. 12PCh. 3 - Prob. 13PCh. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 19PCh. 3 - Prob. 20PCh. 3 - Prob. 21PCh. 3 - Prob. 22PCh. 3 - Prob. 23PCh. 3 - Prob. 24PCh. 3 - Prob. 25PCh. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - Prob. 30PCh. 3 - Prob. 31PCh. 3 - Prob. 32PCh. 3 - Prob. 33PCh. 3 - Prob. 34PCh. 3 - Prob. 35PCh. 3 - Prob. 36PCh. 3 - Prob. 37PCh. 3 - Prob. 38PCh. 3 - Prob. 39PCh. 3 - Prob. 40PCh. 3 - Prob. 41PCh. 3 - Prob. 42PCh. 3 - Prob. 43PCh. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - Prob. 47PCh. 3 - Prob. 48PCh. 3 - Prob. 49PCh. 3 - Prob. 50PCh. 3 - Prob. 51PCh. 3 - Prob. 52PCh. 3 - Prob. 53PCh. 3 - Prob. 54PCh. 3 - Prob. 55PCh. 3 - Prob. 56PCh. 3 - Prob. 57PCh. 3 - Prob. 58PCh. 3 - Prob. 59PCh. 3 - Prob. 60PCh. 3 - Prob. 61PCh. 3 - Prob. 62PCh. 3 - Prob. 63PCh. 3 - Prob. 64PCh. 3 - Prob. 65PCh. 3 - Prob. 66PCh. 3 - Prob. 67P
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- The vertical parabolic curve has its P.I. at station 14 + 750 with elevation of 76.30m. The grade of the back tangent is 3.4% and the forward tangent is -4.8%. If the length of the curve is 300,a. Compute the location of the vertical curve turning point form P.I. (highest point).b. Compute the elevation of the vertical curve turning point. c. Compute the stationing of the vertical curve turning point.arrow_forwardA vertical equal-tangent, 1000 ft long, connects an initial grade of -2.5% and a final grade of +2%. The PVC of the curve is located at station 95 + 00 and has an elevation of 850 ft. At which station is the PVI of the curve located? 80 + 00 83 + 75 O 90 + 00 O 95 + 00 O 100 + 00arrow_forward3. A grade g1 of +3.25% intersects grade g2 of -2.75% at a vertex whose station and elevation are STA 257+17.65 and 3,820.14 ft, respectively. An equal-tangent parabolic curve 900 ft long has been selected to join the two tangents. a. Compute the station and elevation of PVC. b. Compute the station and elevation of the first full station inside the curve. c. Identify the station and elevation of the highest point on the curve.arrow_forward
- A Vertical parabolic curve of length 180m has the following specifications. The point of interaction of grade lines is at station 4 + 316 and its elevation is 38m. The backwards tangent has a grade of -2.2% and the grade of the forward tangent is +3%. Under this conditions determine the following: (a) Station and elevation of PC & PT (b) Station of the lowest point of the curve (c) Elevation of the lowest point of the curvearrow_forward1. An equal-tangent crest vertical curve is being designed for a speed of 45 mph. The curve connects grades of 1.3% and -2.4% in the direction of interest. The curve high point is at station 110+30 and has an elevation of 930 ft. What is the station and elevation of the PVC and the PVI? [Answer: PVI station: 110+50.3; PVI elevation: 930.6']arrow_forwardAn equal tangent vertical curve is to be constructed between grades of -2.0% (initial) and 1.0% (final). The PVI is at station 11 + 000.000 and at elevation 420 m. Due to a street crossing the roadway, the elevation of the roadway at station 11 + 071.000 must be at 421.5 m. Design the curve. with drawingarrow_forward
- Vertical curve A symmetrical parabolic curve passes through point A whose elevation is 23.23 m at a distance of 54 m from the PVC. The elevation of the PVC at Station 4 + 100 is 22.56 m. The grade of the back tangent is +2% and the length of the curve is 120 m. 1. Compute the grade of the forward tangent. 2. Compute the stationing of the highest point of the curve. 3. Compute the elevation of the highest point of the curve.arrow_forward2. A symmetrical sag curve has a descending grade of -4.2% and an ascending grade of +2.5% intersecting at Station 10+120, whose elevation is 382.3÷4 m. The rate of change of grade is restricted to 0.60%. a. What is the vertical offset of the parabolic curve to the point of intersection of the tangent grades? b. At what distance from PC is the lowest point of the curve located?arrow_forwardAn equal-tangent crest vertical curve with a length L unknown, has an initial grade is G₁ = +2.5% and the final grade is G₂ = -1.0%. The highest point of the curve is at Xh = 800m, its elevation is yh = 1000m and its station is STA = 32 +000. Determine the stationing and elevation of the PVI, PVC, and PVT.arrow_forward
- A parabolic curve has a descending grade of -0.85% which meets an ascending grade of 0.35% at sta. 10+025. The max allowable change of grade per 19.5 m station is 0.145. Elevation at station 10+025 is 241 m. 1. What is the length of the curve 2. Compute the elevation of the lowest point of the curve. 3. Compute the elevation at station 10+000.arrow_forward1.) A -2.6% grade meets a +4.8% grade near an underpass. To maintain the minimum clearance allowed under the bridge and at the same time introduce a vertical transition curve in the grade line, it is necessary to use a curve that lies 240m on one side of the vertex of the straight grade and 115m on the other. The station of the beginning of the curve, PC, is 18 + 612 and its elevation is 415.81m. a. Determine the elevation at station 18 + 672. b. Determine the stationing of the lowest point of the curve.arrow_forwardA symmetrical parabolic summit curve connects two grades of +4.9% and -3.2%. It is to pass through a point "D" on the curve at station 25 + 180m . If the stationing of the grade intersection is 25 + 145m and the stationing of PVC is 24 + 979m determine the following: Length of the parabolic curve Stationing of the highest point. Difference in elevation between PVC and PVI Difference in elevation between PVC and point Darrow_forward
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